Displays the empty columns instead of data

I grew up a table from data source in the physical layer. I checked the data in the view, and there are data for all columns.
I need to create a report of this table (only). All the fields, I need to create the report exist in the same table. I didn't need another table to create this report.
But just for the sake of creating joins, I joined with a fact table in the physical layer and in the same way, at a table of dimension and/or fact in MDB table.
I created the report and the data is not displayed for columns 4 and 5. It displays empty for these columns.
Help, please.

Hello
try to purge the cache of the administrator and close all cursors to manage the side sessions answers then try to run the report.
Also check the properties of the columns in the physical layer to see the length defined for the column.

Tags: Business Intelligence

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SQLLDR: How to fill the empty columns with specific data by default?

Hello

We are 11G

Here is a complete example:

(1) the definition of the table:

create table IMPORT_PRJ_TIMESHEETS
(
  RESSOURCE_CODE VARCHAR2(20),
  REFERENCE_DATE VARCHAR2(20),
  STATUS         VARCHAR2(20),
  PROJET_CODE    VARCHAR2(50),
  TACHE_ID       VARCHAR2(100),
  TACHE_DESC     VARCHAR2(250),
  RAF            NUMBER,
  JOUR1          NUMBER,
  JOUR2          NUMBER,
  JOUR3          NUMBER,
  JOUR4          NUMBER,
  JOUR5          NUMBER,
  JOUR6          NUMBER,
  JOUR7          NUMBER,
  IMPORT_DATE    DATE
);

(2) the CTL:

LOAD DATA
CHARACTERSET WE8ISO8859P1
   APPEND INTO TABLE IMPORT_PRJ_TIMESHEETS
-- Pour eliminer la ligne d'en-tete
WHEN PROJET_CODE != 'ID projet'
   FIELDS TERMINATED BY '*-*' OPTIONALLY ENCLOSED BY '"'
( RESSOURCE_CODE       CONSTANT '!RESSOURCE_CODE!'
, REFERENCE_DATE       CONSTANT '!REFERENCE_DATE!'
, STATUS               CONSTANT '!STATUS!'
, PROJET_CODE          CHAR
, TACHE_ID             CHAR
, TACHE_DESC           CHAR
, RAF                  CHAR "TO_NUMBER( :RAF, '999G999D99')"
, JOUR1                CHAR
, JOUR2                CHAR
, JOUR3                CHAR
, JOUR4                CHAR
, JOUR5                CHAR
, JOUR6                CHAR
, JOUR7                CHAR
, IMPORT_DATE          SYSDATE
)
{code}


3) the datafile :
{code}
ID projet*-*ID tâche*-*Tâche/Description*-*RàF*-*lun. 13/07*-*mar. 14/07*-*mer. 15/07*-*jeu. 16/07*-*ven. 17/07*-*sam. 18/07*-*dim. 19/07*-*
FR-FR-NT2300135*-* *-*GAMMAWEB - Coordination*-*0,00*-* *-* *-* *-*8,00*-*8,00*-* *-* *-*
 *-* *-*Holiday*-* *-* *-*8,00*-* *-* *-* *-* *-* *-*
 *-* *-*Special leave*-* *-*8,00*-* *-* *-* *-* *-* *-* *-*
 *-* *-*Vacation*-* *-* *-* *-*8,00*-* *-* *-* *-* *-*

{code}

- As you can see, the datafile delimiter is "*-*" .... there's no pb about this.

- Also, there are 5 lines in the datafile. Currently, the _*load status*_ is :
   - Line 1 is the header  >>> not loaded, and that's fine with me.
   - Line 2 is successfully loaded
   - Line 3 / Line 4 / Line 5 : are not loaded .. but I need these lines ...

*What I'd like to get is to successfully load lines 3 to 5 with a default values for the first 3 columns (project/task ID/ task desc)*

I hope it's clear enough and that you will be able to provide a good answer ..

Thanks in advance,
  Olivier

In your example, the only ranked with value on all lines is TACHE_DESC.
If this field is always filled, try this:
WHEN TACHE_DESC! = "Task/Description".

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Hi, I look at previous posts that are similar to my question, but nothing helps.

I have a column called incident_date that is in this format and comes from the Nov_Final table

01-JUL-2009 20.10
04-NOV-2009 17.00
16-DEC-2009 16.00

In Nov_Final, I created a column called weekend

What I want to do is to perform an update, something like this:

Update Nov_Final

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Oracle Database 11 g Release 11.2.0.2.0 - 64 bit Production
PL/SQL Release 11.2.0.2.0 - Production
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AMT for Linux: Version 11.2.0.2.0 - Production
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Weekend would be Saturday or Sunday. 
In short I need to find out if the incident_date falls on a weekend and if it does update the weekend column as 'Y' else 'N' if it's not.

You can use TO_CHAR function with a format mask as "fmDAY" to your needs:

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as
(
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)
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------------------------- --------------------------- -----------
08-NOV-11 07:54:12        TUESDAY                     N
09-NOV-11 07:54:12        WEDNESDAY                   N
10-NOV-11 07:54:12        THURSDAY                    N
11-NOV-11 07:54:12        FRIDAY                      N
12-NOV-11 07:54:12        SATURDAY                    Y
13-NOV-11 07:54:12        SUNDAY                      Y
14-NOV-11 07:54:12        MONDAY                      N           

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Hi experts,

I'm building a report to display the number of orders per channel / day / hour.

Since a few days one or several channels may not all orders placed against them in which case my report shows empty values in the report.

Ideally, I would have zero in these columns rather than an empty cell.

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Select
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Thanks in advance.
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You run query sqlplus, or Toad or sqldevloper and you can see for yourself that the count is 0.

See you soon.
VIN.

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user12850338 wrote:
Hi BluShadow,
Thanks for your reply.
I confess that if we would have used type xml in the first place, things would have been easier.
For example, I mentioned three tags in the xml file, but my real data contains some hundreds of tags... :( So it will always be a good idea with this approach.

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SQL> ed
Wrote file afiedt.buf

  1  WITH t as (select XMLTYPE('
  2  
  3    
  4      1
  5      1800
  6      
  7        1
  8        28
  9        6
 10        12
 11      
 12      
 13        5
 14        19
 15        1
 16        90
 17      
 18    
 19    
 20      2
 21      2400
 22      
 23        3
 24        14
 25        7
 26        5
 27      
 28    
 29  ') as xml from dual)
 30  -- END OF TEST DATA
 31  select x.country, x.point, y.user_id, y.target, y.state, y.task
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 35                PASSING t.xml
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 42                PASSING x.user_info
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 46                       ,task    NUMBER PATH '/aa:USER_INFO/aa:TASK'
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---------- ---------- ---------- ---------- ---------- ----------
         1       1800          1         28          6         12
         1       1800          5         19          1         90
         2       2400          3         14          7          5

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Hello
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SQL> ed
Wrote file afiedt.buf

  1  select deptno, ename
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SQL> /

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---------- ----------
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        30 SM0
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           ALLEN
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           PAV
           BAR

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In SQL, you must use an analytic function

SQL> ed
Wrote file afiedt.buf

  1  select (case when deptno = prior_deptno
  2               then null
  3               else deptno
  4            end) deptno,
  5         ename
  6    from (select deptno,
  7                 lag(deptno) over (order by deptno, ename) prior_deptno,
  8                 ename
  9            from emp
 10*          order by deptno, ename)
SQL> /

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        10 CLARK
           KING
           MILLER
        20 ADAMS
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           JONES
           SCOTT
           smith
        30 ALLEN
           BLAKE
           MARTIN
           SM0
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           WARD
           BAR
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Justin

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Robyn
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Displays the empty columns instead of data

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