Hierarchical queries with Rollup sum (CONNECTED BY GROUP BY ROLLUP)

Similar Questions

• Hierarchical queries - problem with condition "begins by".

  Hi people

  I play with the connection by and start with clause and am faced with a particular problem which I can not solve...

  My data set is:

  Create table dates_q
  (start_date date,
  end_date date)
  /
  

  REM INSERTING into dates_q
  Insert into dates_q ("START_DATE","END_DATE") values (to_date('01-JAN-14','DD-MON-RR'),to_date('10-JAN-14','DD-MON-RR'));
  Insert into dates_q ("START_DATE","END_DATE") values (to_date('11-JAN-14','DD-MON-RR'),to_date('20-JAN-14','DD-MON-RR'));
  Insert into dates_q ("START_DATE","END_DATE") values (to_date('10-MAR-14','DD-MON-RR'),to_date('20-MAR-14','DD-MON-RR'));
  Insert into dates_q ("START_DATE","END_DATE") values (to_date('21-MAR-14','DD-MON-RR'),to_date('31-MAR-14','DD-MON-RR'));
  Insert into dates_q ("START_DATE","END_DATE") values (to_date('01-APR-14','DD-MON-RR'),to_date('10-APR-14','DD-MON-RR'));
  

  Now I basically just want to get your hands on hierarchical queries and working with the syntax of various...

  What I now want is, start with the date of April 1 as my start date and work backward to build my 'tree '. The condition of my tree is between two rows; my start and end dates differ from 1 day. If they do not; I don't want these records in my tree.

  And using sys_connect_by_path, I want to get all the way from the root.

  Thus, for example,.

  SELECT a.*,
         sys_connect_by_path(start_date, '|'),
         LEVEL lvl
    FROM dates_q a
   CONNECT BY PRIOR end_date = (start_date - 1)
  

  I get the following output

  START_DATE	END_DATE	SYS_CONNECT_BY_PATH(START_DATE,'|')	LVL
  01.01.2014	10.01.2014	| 1 JANUARY 14	1
  11.01.2014	20.01.2014	| 1 JANUARY 14 | JANUARY 11, 14	2
  11.01.2014	20.01.2014	| JANUARY 11, 14	1
  10.03.2014	20.03.2014	| MARCH 10, 14	1
  21.03.2014	31.03.2014	| MARCH 10, 14. MARCH 21, 14	2
  01.04.2014	10.04.2014	|10-MAR-14|21-MAR-14|01-APR-14	3
  21.03.2014	31.03.2014	| MARCH 21, 14	1
  01.04.2014	10.04.2014	| MARCH 21, 14. 1 APRIL 14	2
  01.04.2014	10.04.2014	| 1 APRIL 14	1

  But for the moment I did not have any starting point... Now comes the FUN part...

  When I give the State of departure; I get a single row :-(

  Example of

  SELECT a.*,
         sys_connect_by_path(start_date, '|'),
         LEVEL lvl
    FROM dates_q a
   CONNECT BY PRIOR end_date = (start_date - 1)
   START WITH start_date = To_Date('01-apr-2014','dd-mon-yyyy');
  

  The result is

  START_DATE	END_DATE	SYS_CONNECT_BY_PATH(START_DATE,'|')	LVL
  01.04.2014	10.04.2014	| 1 APRIL 14	1

  Just a line...!

  I'm unable to understand this and work more and need help.

  The formation of the tree works only in a 'sense' and I'm going the other way around? Don't know what it means but just something that comes to mind. :/

  Thank you

  K

  P.S. - database is 10g R2.

  Hello

  Thanks for the display of the data of the sample; It is very useful.

  What do you expect the result will be and why?

  LEVEL = 1 contains all rows that meet the condition to START WITH.  The rows that meet the condition

  start_date = To_Date('01-apr-2014','dd-mon-yyyy')

  in this case?  Only the line you actually obtained.

  LEVEL = N (where N > 1) contains all rows that meet the conditions regarding some FRONT CONNECT BY rank level = N - 1.  Since the only line level = 1 to end_date = To_Date('10-apr-2014','dd-mon-yyyy'), lines satisfy the condition

  End_date PRIOR = (start_date - 1).

  ? None.  End_date PREREQUISITE is April 10, while rows with start_date April 11 would fulfill this condition, there is no line on LEVEL = 2 and the query stops there.

  You would have expected this from your previous results.  The line with the start_date April 1 had no children in the previous application, so there no children in any application that has the same State of CONNECT BY.

  Maybe you meant the CONNECT BY condtion to be

  End_date = BEFORE (start_date - 1).

• How to order a tree balanced with SQL hierarchical queries

  by searching the forum I found this
  
  Re: Generate tree balanced with SQL hierarchical queries
  
  is there a way I can order this tree in alphabetical order so that the result looks like
  
  LEVEL INDENTED_ENAME
  ---------- --------------------
  1 KING BED
  2 BLAKE
  3 ALLEN
  3 JAMES
  MARTIN 3
  3 TURNER
  WARD 3
  2 CLARK
  3 MILLER
  2 JONES
  3 FORD
  4 SMITH
  3 SCOTT
  4 ADAMS
  
  -the original query-
  
  SELECT THE LEVEL
  , LPAD (' ', 3 * LEVEL) | Ename AS indented_ename
  FROM scott.emp
  START WITH mgr IS NULL
  CONNECT BY PRIOR empno = mgr
  ;
  
  LEVEL INDENTED_ENAME
  ---------- --------------------
  1 KING BED
  2 JONES
  3 SCOTT
  4 ADAMS
  3 FORD
  4 SMITH
  2 BLAKE
  3 ALLEN
  WARD 3
  MARTIN 3
  3 TURNER
  3 JAMES
  2 CLARK
  3 MILLER

  Hello

  Bodin wrote:
  Hi Frank, I can order it selectively depending on the level, which means that only siblings stopped at third level, but rest of the brothers and sisters remain Nations United ordered

  It's actually quite difficult. You can "ORDER of brothers and SŒURS BY CASE... ', like this:

  SELECT  LEVEL
  ,      LPAD (' ', 3 * LEVEL) || ename     AS indented_ename
  FROM      scott.emp
  START WITH        mgr     IS NULL
  CONNECT BY         mgr      = PRIOR empno
  ORDER SIBLINGS BY  CASE
                 WHEN  job = 'MANAGER'  THEN  ename
                                            ELSE  NULL
               END
  ;
  

  In this case to get desired results in table scott.emp, as the lines are LEVEL = 2 if and only if use = "MANAGER".
  But if you reference LEVEL in the CASE expression (for example, if you replace ' job = 'MANAGER' ' with "2 LEVEL =" above "), then you will get the error" ORA-00976: LEVEL, PRIOR or ROWNUM not allowed here. "
  The best way I can think to do exactly what you asked is to do 2 CONNECT BY queries; one just to get the LEVEL and the other for the brothers and SŒURS ORDER BY:
  {code}
  WITH got_lvl AS
  (
  SELECT LEVEL AS lvl
  Bishop
  empno
  ename
  FROM scott.emp
  START WITH mgr IS NULL
  CONNECT BY PRIOR empno = mgr
  )
  SELECT lvl
  , LPAD (' ', 3 * LEVEL) | Ename AS indented_ename
  OF got_lvl
  START WITH mgr IS NULL
  CONNECT BY PRIOR empno = mgr
  BROTHERS AND SŒURS OF ORDER OF CASES
  ONCE lvl = 2 THEN ename
  ANOTHER NULL
  END
  ;
  {code}
  Why you can't simply "Brothers and SŒURS of ORDER BY ename" at all levels? If all you care is the order of the items of LEVEL = 2, then this is probably the most effective and simplest way. It really hurt anything if nodes on levels 3, 4, 5,... are in order, too?

  Here's something you can do if you want to order by different unique things to different levels:
  {code}
  WITH got_sort_key AS
  (
  SELECT LEVEL AS lvl
  , LPAD (' ', 3 * LEVEL) | Ename AS indented_ename
  empno
  SYS_CONNECT_BY_PATH (LPAD (CASE
  WHEN LEVEL = 2
  THEN ename
  Of OTHER TO_CHAR (empno)
  END
  10
  )
  , ','
  ) AS sort_key
  FROM scott.emp
  START WITH mgr IS NULL
  CONNECT BY PRIOR empno = mgr
  )
  SELECT lvl
  indented_ename
  empno
  OF got_sort_key
  ORDER BY sort_key
  ;
  {code}
  However, all possible values of the CASE expression must uniquely identify the node; otherwise, the output won't necessarily hierarchical order. You can assign arbitrary unique IDS to the lines (using the ROW_NUMBER analytic function, for example), but that requires another subquery and is also complex and perhaps as ineffective as the solution above with 2 garages CONNECT.

• Building the tree balanced with SQL hierarchical queries

  Hi all
  
  I have the following hierarchical data with different levels of subtree:
  
  A0
  -A001
  -A00101
  A1
  -A101
  A2
  -A201
  -A20101
  -A201010001
  
  A0 subtree has 3 levels, A1 subtree has 2 levels and subtree of the A3 is level 4. I want to generate a tree balanced on the data with all levels of the subtree equal to the maximum number of levels available in the whole tree which, in this particular case, is 4.
  
  I don't know that it is possible with SQL. Script to generate the above mentioned are as below:
  
  CREATE TABLE codes_tree
  (node_id VARCHAR2 (10))
  parent_node_id VARCHAR2 (10)
  );
  INSERT INTO codes_tree VALUES ('A0', NULL);
  INSERT INTO codes_tree VALUES ('A001', 'A0');
  INSERT INTO codes_tree VALUES ('A00101', 'A001');
  ---
  INSERT INTO codes_tree VALUES ('A1', NULL);
  INSERT INTO codes_tree VALUES ('A101', 'A1');
  ---
  INSERT INTO codes_tree VALUES ('A2', NULL);
  INSERT INTO codes_tree VALUES ('A201', 'A2');
  INSERT INTO codes_tree VALUES ('A20101', 'A201');
  INSERT INTO codes_tree VALUES ('A201010001', 'A20101');
  
  Any help will be much appreciated.
  
  Thank you... Best regards
  
  Published by: naive2Oracle on May 12, 2011 19:40
  
  Published by: naive2Oracle on May 12, 2011 19:41

  Hello

  Of course, you can do it in SQL.
  One way is to take the normal output of hierarchical and manipulate the result set so that the leaves are repeated as often as necessary to make all branches of the same length. I have Oracle 10.2 available right now, so here's a solution that will work in Oracle 10 (and more):

  WITH     original_hierarchy     AS
  (
       SELECT     node_id
       ,     LEVEL               AS lvl
       ,     CONNECT_BY_ISLEAF     AS isleaf
       ,     ROWNUM               AS rnum
       FROM     codes_tree
       START WITH     parent_node_id     IS NULL
       CONNECT BY     parent_node_id     = PRIOR node_id
  )
  ,     got_max_lvl     AS
  (
       SELECT     o.*
       ,     MAX (lvl) OVER ()     AS max_lvl
       FROM     original_hierarchy     o
  )
  SELECT       LPAD ( ' '
              , 3 * ( ( d.lvl
                   + NVL (c.rnum, 1)
                   - 1
                   )
                 - 1
                 )
              ) || CASE
                 WHEN c.rnum > 1
                 THEN '*' || d.node_id || '*'
                 ELSE        d.node_id
                END          AS display_id
  FROM            got_max_lvl     d
  LEFT OUTER JOIN       got_max_lvl     c  ON     d.isleaf     = 1
                         AND     c.rnum          <= 1 + d.max_lvl - d.lvl
  ORDER BY  d.rnum
  ,       c.rnum
  ;
  

  With the help of Oracle 11.2, it would be preferable to generate original_hierarchy as above, but to manipulate using a WITH recursive clause.
  Analytical functions often interfere with CONNECT BY, so I used a separate subquery to get max_lvl, do CONNECT BY in a sub-querry and analytic function in a separate subquery. I don't know what is needed on all versions.

  Output of your sample data:

  DISPLAY_ID
  -------------------------------
  A0
     A001
        A00101
           *A00101*
  A1
     A101
        *A101*
           *A101*
  A2
     A201
        A20101
           A201010001
  

  Below is a generic version of the same query, which I used to test this on scott.emp:

  DEFINE     table_name     = scott.emp
  DEFINE     id_col          = empno
  DEFINE     parent_id_col     = mgr
  DEFINE     display_col     = ename
  
  WITH     original_hierarchy     AS
  (
       SELECT     &display_col          AS display_txt
       ,     LEVEL               AS lvl
       ,     CONNECT_BY_ISLEAF     AS isleaf
       ,     ROWNUM               AS rnum
       FROM     &table_name
       START WITH     &parent_id_col     IS NULL
       CONNECT BY     &parent_id_col     = PRIOR &id_col
  )
  ,     got_max_lvl     AS
  (
       SELECT     o.*
       ,     MAX (lvl) OVER ()     AS max_lvl
       FROM     original_hierarchy     o
  )
  SELECT       LPAD ( ' '
              , 3 * ( ( d.lvl
                   + NVL (c.rnum, 1)
                   - 1
                   )
                 - 1
                 )
              ) || CASE
                 WHEN c.rnum > 1
                 THEN '*' || d.display_txt || '*'
                 ELSE        d.display_txt
                END          AS display_id
  FROM            got_max_lvl     d
  LEFT OUTER JOIN       got_max_lvl     c  ON     d.isleaf     = 1
                         AND     c.rnum          <= 1 + d.max_lvl - d.lvl
  ORDER BY  d.rnum
  ,       c.rnum
  ;
  

  Output:

  DISPLAY_ID
  -----------------------------
  KING
     JONES
        SCOTT
           ADAMS
        FORD
           SMITH
     BLAKE
        ALLEN
           *ALLEN*
        WARD
           *WARD*
        MARTIN
           *MARTIN*
        TURNER
           *TURNER*
        JAMES
           *JAMES*
     CLARK
        MILLER
           *MILLER*
  

  Published by: Frank Kulash, May 13, 2011 06:38
  Adding the generic version

• Help to combine the two queries with dependencies

  Combining two queries with dependencies:
  First ask: Returns USER_ID that has a type of access to a table with the OWNER (I also shoot the TLA of the USER_ID standard: ' of TLA #)

  Select distinct SUBSTR (DBA_USERS. Username, 2, 3) AS TLA

  DBA_USERS. Username USED_ID

  DBA_TAB_PRIVS. Owner OWNER

  from DBA_USERS

  DBA_ROLE_PRIVS

  DBA_TAB_PRIVS

  where DBA_USERS. Username = DBA_ROLE_PRIVS. Dealer

  and DBA_USERS.default_tablespace not in ('SYSTEM', "SYSAUX")

  and DBA_USERS. Username like would be %'

  and DBA_ROLE_PRIVS. Granted_role = DBA_TAB_PRIVS. Dealer

  and SUBSTR (DBA_USERS. Username, 2, 3) <>DBA_TAB_PRIVS. Owner

  ;

  Example of results (red font used in the last citation):

  TLA USED_ID OWNER

  --- ------------------------------ ------------------------------

  DGTX999 GTX GRR

  DGTX999 GTX ABG

  DGTX999 GTX HTC

  FWS DFWS999 GRR

  OCN DOCN999 GRR

  RHR DRHR999 DAS

  ETM DETM999 DAS

  FWS DFWS995 DAS

  CD DCDS999 DAS

  ABE DABE999 DAS

  
  
  Second request: matches the USER name (same standards as above) and MACHINES (filter PC connections) and the number of connections made of

  Select DBA_USERS. Username

  DBA_HIST_ACTIVE_SESS_HISTORY. Machine

  COUNT (*) AS CONN_COUNT

  of DBA_HIST_ACTIVE_SESS_HISTORY

  DBA_USERS

  where DBA_HIST_ACTIVE_SESS_HISTORY. User_id = DBA_USERS. User_id

  and DBA_USERS. Username like would be %'

  and DBA_HIST_ACTIVE_SESS_HISTORY. Machine not as "WINAD%\%-%".

  Group of DBA_USERS. Username

  DBA_HIST_ACTIVE_SESS_HISTORY. Machine

  order by 1

  3 desc;

  Example of results (red font used in the last citation):

  MACHINE CONN_COUNT USERNAME

  --------------- ------------------------- ----------

  DFWS999 home13e0 7557

  DGAM800 vu1246 37

  DGAM999 vu1246 2558

  DABE999 back18cb 4639

  DINL888 home162f 84

  DFWS999 WINDAD\OMHQ58BF 178

  DCDS999 back18cb 788

  DGTX999 home18c8 7

  DGTX999 home13d3 62

  DOCN999 vu1261 44

  DFWS999 back1976 3

  DCDS999 home18c8 173

  DGTX999 home19c9 13

  What I'd like to have (just made two first USER_IDs from the first query) (COL duplicated for each separate owner 1-4).  So 3 machines and 3 owners would result in 9 lines (I could reorganize the collar and use a 'pause'):

  TLA USED_ID MACHINE CONN_COUNT OWNER

  --- ------------------------------ ------------------------- ---------- ------------------------------

  GTX DGTX999 home13d3 62 GRR

  Home18c8 GTX DGTX999 7 GRR

  DGTX999 GTX home19c9 GRR 6

  GTX DGTX999 home13d3 62 ABG

  DGTX999 GTX home18c8 ABG 7

  DGTX999 GTX home19c9 6 GBS

  GTX DGTX999 home13d3 62 CTH

  DGTX999 GTX HTC 7 home18c8

  DGTX999 GTX home19c9 6 HTC

  FWS DFWS999 home13e0 7557 GRR

  FWS DFWS999 WINDAD\OMHQ58BF 178 GRR

  FWS DFWS999 back1976 GRR 3

  
  So it would be logically read: TLA as USER_ID of MACHINE, CONN_COUNT consultation times: OWNER information.

  Thought as only those with the necessary values. Just try this and let me know in the case of all conflicts in the output.

  WITH T1 AS)

  Select distinct SUBSTR (DBA_USERS. Username, 2, 3) AS TLA

  DBA_USERS. Username USED_ID

  DBA_TAB_PRIVS. Owner OWNER

  ROWNUM RN

  from DBA_USERS

  DBA_ROLE_PRIVS

  DBA_TAB_PRIVS

  where DBA_USERS. Username = DBA_ROLE_PRIVS. Dealer

  and DBA_USERS.default_tablespace not in ('SYSTEM', "SYSAUX")

  and DBA_USERS. Username like would be %'

  and DBA_ROLE_PRIVS. Granted_role = DBA_TAB_PRIVS. Dealer

  and SUBSTR (DBA_USERS. Username, 2, 3) <> DBA_TAB_PRIVS. Owner),

  () AS T2

  Select DBA_USERS. Username

  DBA_HIST_ACTIVE_SESS_HISTORY. Machine

  COUNT (*) AS CONN_COUNT

  of DBA_HIST_ACTIVE_SESS_HISTORY

  DBA_USERS

  where DBA_HIST_ACTIVE_SESS_HISTORY. User_id = DBA_USERS. User_id

  and DBA_USERS. Username like would be %'

  and DBA_HIST_ACTIVE_SESS_HISTORY. Machine not as "WINAD%\%-%".

  Group of DBA_USERS. Username

  DBA_HIST_ACTIVE_SESS_HISTORY. Machine

  order by 1

  3 desc)

  SELECT T1. TLA

  ,         T1. USED_ID

  ,         T2. MACHINE

  ,         T2. CONN_COUNT

  ,         T1. OWNER

  FROM T1

  T2

  WHERE T1. USED_ID = T2. USER NAME;

• Reg: Prior in hierarchical queries:

  Hi Experts,
  
  A little doubt - I've been working on the requests, but it still haunts me... Hierarchical queries
  One thing I am more confused about is the prior clause.
  
  I'll try to explain my concern below.
  Here, the tree yesterday gets reversed by changing the clause PRIOR to 'Manager Id' to 'Employee Id' and vice versa.
  
  Exactly how to understand where to put FORWARD... which column?
  I can get my results just double check... but I just want to know the concept. So stupid right... but do not want to take this doubt more far. ;)
  

  ranit@XE11GR2>> select * from
    2  emp;
  
       EMPNO ENAME      JOB              MGR HIREDATE         SAL       COMM     DEPTNO
  ---------- ---------- --------- ---------- --------- ---------- ---------- ----------
        7369 SMITH      CLERK           7902 17-DEC-08        800                    20
        7566 NORGAARD   MANAGER         7839 01-APR-07       2975                    20
        7654 MARTIN     SALESMAN        7698 28-SEP-07       1250       1400         30
        7698 BLAKE      MANAGER         7839 01-MAY-09       2850                    30
        7782 FOOTE      MANAGER         7839 09-JUN-08       2450                    10
        7788 SCOTT      ANALYST         7566 19-APR-87       3000                    20
        7839 ELLISON    PRESIDENT            17-NOV-06       5000                    10
        7844 TURNER     SALESMAN        7698 08-SEP-08       1500          0         30
        7876 ADAMS      CLERK           7788 18-JUN-07       1100                    20
        7900 JAMES      CLERK           7698 03-DEC-07        950                    30
        7902 LOFSTROM   ANALYST         7566 04-DEC-08       3000                    20
        7934 MILLER     CLERK           7782 23-JAN-08       1300                    10
  
  12 rows selected.
  
  Elapsed: 00:00:00.04
  ranit@XE11GR2>> select * from
    2  emp
    3  connect by empno  = prior mgr
    4  start with empno = 7698;
  
       EMPNO ENAME      JOB              MGR HIREDATE         SAL       COMM     DEPTNO
  ---------- ---------- --------- ---------- --------- ---------- ---------- ----------
        7698 BLAKE      MANAGER         7839 01-MAY-09       2850                    30
        7839 ELLISON    PRESIDENT            17-NOV-06       5000                    10
  
  Elapsed: 00:00:00.01
  ranit@XE11GR2>> select * from
    2  emp
    3  connect by prior empno = mgr
    4  start with empno = 7698;
  
       EMPNO ENAME      JOB              MGR HIREDATE         SAL       COMM     DEPTNO
  ---------- ---------- --------- ---------- --------- ---------- ---------- ----------
        7698 BLAKE      MANAGER         7839 01-MAY-09       2850                    30
        7654 MARTIN     SALESMAN        7698 28-SEP-07       1250       1400         30
        7844 TURNER     SALESMAN        7698 08-SEP-08       1500          0         30
        7900 JAMES      CLERK           7698 03-DEC-07        950                    30
  
  Elapsed: 00:00:00.07

  Please help guys.

  Oracle Database 11g Express Edition Release 11.2.0.2.0 - Production
  PL/SQL Release 11.2.0.2.0 - Production
  "CORE     11.2.0.2.0     Production"
  TNS for 32-bit Windows: Version 11.2.0.2.0 - Production
  NLSRTL Version 11.2.0.2.0 - Production

  Thank you
  Vanessa B.

  I know the feeling!

  START WITH gives you the first line of the result set.

  CONNECT BY gets you the next row. At this point, you already have is the "before" line and the line that you get is the current line.

  If the current line is supposed to be the Manager of the previous line, this means that Bishop PREREQUISITE = empno.

  If the previous line is supposed to be the Manager of the current line, which means PRIOR empno = mgr.

  Think AHEAD as referring to the line that you just received and "without any preconditions" as the line you want.

  Another way of thinking that is to ask "what new information I receive?

  If you say "Bishop PREREQUISITE = empno", you already know the Director of the previous row. New information will be the Director of the current line. As you continue, you will learn step by step who are managers.

  If you say "PRIOR empno = mgr", you already know that the employee of the previous row. New information will be the new empno. So step by step, you will find the empnos.

  You always ' move to before current. "Of mgr to empno" descends from the string, "empno to Bishop" goes to the top of the chain.

  Published by: stew Ashton on February 16, 2013 11:57

• Gites join vs hierarchical queries

  Hello
  
  Please tel me who must use a 1?
  I have to get job list of the simple Manger, should I use self-join or hierarchical queries (CONNECT BY and earlier versions)?
  
  Yours sincerely

  Hello

  944768 wrote:
  Hello

  Please tel me who must use a 1?
  I have to get job list of the simple Manger, should I use self-join or hierarchical queries (CONNECT BY and earlier versions)?

  It depends on your data and your needs.

  Whenever you have a question, please post a small example of data (CREATE TABLE and INSERT statements) for all the tables involved, so people who want to help you can recreate the problem and test their ideas. Also post the results you want from this data, as well as an explanation of how you get these results from these data.
  Explain, using specific examples, how you get these results from these data.
  If you show what the problem using commonly available tables (suc as scott.emp, who has a hierarchy of level 4), then you do not have ot post sample data, just the results and explanations.
  Always say what version of Oracle you are using (for example, 11.2.0.2.0).
  See the FAQ forum {message identifier: = 9360002}

  If your hierarchy consists only of 2 levels, then a self-join will be probably more effective, simpler code and easier to maintain.

  If you don't know how many levels in the hierarchy, then self-join is not an option. Use CONNECT BY or, if you have Oracle 11.2, a WITH recursive clause.

  If you have a fixed number of levels (or an upper limit) greater than 2, then CONNECT BY (or a WITH recursive clause) will probably be the best.

• Slow hierarchical queries

  Hello
  I wrote an application that allows the user to filter the data displayed based on several parameters, for example one of the parameters (b) is hierarchical, each element (with the exception of the root element) has a father and several sons, the hierarchy is managed by a specific table (LINKS), I need when the user selects b the result will include also all his descendants.
  
  This is the query:
  
  SELECT *.
  R
  JOIN IN-HOUSE RT ON R.A = RT. A
  WHERE (R.B IN (select sub_id
  the beginning of LINKS with father_id =: id
  Connect prior sub_id = father_id)
  or R.B =: id or: id = 0)
  AND (R.A =: GOLD: a = 0)
  ORDER OF R.B, R.A
  
  The problem is that the query is so slow, it allows the application of stuck, when I've omitted the line: ' or R.B =: id or: id = 0 ' he not stuck but this line is necessary because the user may also fill the filter field or try to filter b himself and not his descendants.
  
  Is it possible to improve the performance of this query or write it better?

  You can move the logic on r.b in the subquery.
  There is a small chance that it could accelerate the entire query.
  not tested

  SELECT *
  FROM R
  JOIN RT ON R.A = RT.A
  WHERE R.B IN (select sub_id
                     from LINKS
                     start with father_id = :id
                     connect by prior sub_id= father_id
                     UNION ALL
                     select :id sub_id from dual
                     UNION ALL
                     select sub_id
                     from LINKS
                     where :id = 0
                     )
  AND (R.A=:a or :a=0)
  ORDER BY R.B, R.A
  

  Also see the ecexution use it and explain how to call the select statement.
  A goal of optimization often used is wo writing several queries and call the right according to the parameters.
  Different queries may be optimized independently of each other and hence faster query where everything is condensed into one big.

  pls/sql example

  if :a=0 and :b=0 then
     SELECT *
     into...
     FROM R
     JOIN RT ON R.A = RT.A
     ORDER BY R.B, R.A;
  elsif :b=0 then
     SELECT *
     into...
     FROM R
     JOIN RT ON R.A = RT.A
     where R.A=:a
     ORDER BY R.B, R.A;
  elsif :a=0 then
     SELECT *
     into...
     FROM R
     JOIN RT ON R.A = RT.A
     WHERE R.B IN (select sub_id
                     from LINKS
                     start with father_id = :id
                     connect by prior sub_id= father_id
                     UNION ALL
                     select :id sub_id from dual)
     ORDER BY R.B, R.A;
  else /* both parameters are selected */
     SELECT *
     into...
     FROM R
     JOIN RT ON R.A = RT.A
     WHERE R.B IN (select sub_id
                     from LINKS
                     start with father_id = :id
                     connect by prior sub_id= father_id
                     UNION ALL
                     select :id sub_id from dual)
     and R.A=:a
     ORDER BY R.B, R.A;
  end;
  

• Problem with "vpn sysopt connection permit.

  Hi all

  I would like to ask you for advice with "vpn sysopt connection permit". I have a problem with by-pass-access list (acl) in the INSIDE interface. As I understand it and I'm going to use this command, there is no need to especialy allow traffic in the access list for the INSIDE and I can control the filter-vpn traffic. But in my case it's quite the opposite, I want particularly to this INTERIOR acl traffi. When I allow this traffic inside acl L2L tunnel rises, hollow traffic flow vpn-fltr ane acl that everything is OK. But when I do not allow that this traffic is inside of the rule with Deny statement in acl INSIDE block traffic and tunnel goes ever upward. Part of the configuraciton which you can view below.

  Please let me know if I'm wrong, or what I did wrong?

  Thank you

  Karel

  PHA-FW01 # view worm | Worm Inc

  Cisco Adaptive Security Appliance Software Version 4,0000 1

  PHA-FW01 # display ru all sys

  No timewait sysopt connection

  Sysopt connection tcpmss 1380

  Sysopt connection tcpmss minimum 0

  Sysopt connection permit VPN

  Sysopt connection VPN-reclassify

  No sysopt preserve-vpn-stream connection

  no RADIUS secret ignore sysopt

  No inside sysopt noproxyarp

  No EXT-VLAN20 sysopt noproxyarp

  No EXT-WIFI-VLAN30 sysopt noproxyarp

  No OUTSIDE sysopt noproxyarp

  PHA-FW01 # display the id of the object-group ALGOTECH

  object-group network ALGOTECH

  object-network 10.10.22.0 255.255.255.0

  host of the object-Network 172.16.15.11

  PHA-FW01 # show running-config id of the object VLAN20

  network of the VLAN20 object

  subnet 10.1.2.0 255.255.255.0

  L2L_to_ALGOTECH list extended access permitted ip object object-group VLAN20 ALGOTECH

  extended access list ACL-ALGOTECH allow ip object-group object VLAN20 ALGOTECH

  Note EXT-VLAN20 of access list =.

  access list EXT-VLAN20 allowed extended ip object VLAN20 ALGOTECH #why object-group must be the rule here?

  access list EXT-VLAN20 extended permitted udp object VLAN20 object-group OUT-DNS-SERVERS eq field

  EXT-VLAN20 allowed extended VLAN20 object VPN-USERS ip access list

  EXT-VLAN20 extended access list permit ip object VLAN20 OPENVPN-SASPO object-group

  EXT-VLAN20 allowed extended object VLAN10 VLAN20 ip access list

  deny access list extended VLAN20 EXT ip no matter what LOCAL NETS of object-group paper

  EXT-VLAN20 allowed extended icmp access list no echo

  access list EXT-VLAN20 allowed extended object-group SERVICE VLAN20 object VLAN20 everything

  EXT-VLAN20 extended access list deny ip any any newspaper

  extended access list ACL-ALGOTECH allow ip object-group object VLAN20 ALGOTECH

  GROUP_POLICY-91 group policy. X 41. X.12 internal

  GROUP_POLICY-91 group policy. X 41. X.12 attributes

  value of VPN-filter ACL-ALGOTECH

  Ikev1 VPN-tunnel-Protocol

  tunnel-group 91.X41. X.12 type ipsec-l2l

  tunnel-group 91.X41. X.12 General attributes

  Group Policy - by default-GROUP_POLICY-91. X 41. X.12

  tunnel-group 91.X41. X.12 ipsec-attributes

  IKEv1 pre-shared-key *.

  PHA-FW01 # show running-config nat

  NAT (EXT-VLAN20, outdoors) static source VLAN20 VLAN20 static destination ALGOTECH ALGOTECH non-proxy-arp-search to itinerary

  network of the VLAN20 object

  dynamic NAT interface (EXT-VLAN20, outdoors)

  group-access to the INTERIOR in the interface inside

  Access-group interface VLAN20 EXT EXT-VLAN20

  Hello

  The command "sysopt connection permit-vpn" is the default setting and it applies only to bypass ACL interface to the interface that ends the VPN. It would be connected to the external network interface. This custom has no effect on the other interfaces ACL interface.

  So if you initiate or need to open connections from your local network to remote network through the VPN L2L connection then you will need to allow this traffic on your LAN interface ACL networks.

  If the situation was that only the remote end has launched connections to your network then 'sysopt permit vpn connection' would allow their connections around the external interfaces ACL. If If you have a VPN configured ACL filter, I think that the traffic will always accompany against this ACL.

  Here are the ASA reference section to order custom "sysopt"

  http://www.Cisco.com/en/us/docs/security/ASA/command-reference/S21.html#wp1567918

  -Jouni

• Add vNIC PortGroup scope with the REST API security group

  I created a security group within the reach of a PortGroup via the REST API. Now, I'm trying to add a vNIC, also via the REST API.

  To help illustrate, I have a JMTest1 VM with 1 vNIC connected to the PortGroup which is the scope of the security group. When I change this group the first item in the list that could be added to the security group is the first (and only) JMTest1 vNIC.

  

  To add it via the REST API, I need to provide the following:

  https://192.168.x.x/API/2.0/services/SecurityGroup/SecurityGroup-XX/members/ < member-moref >

  for example I need to understand what the < member-moref > for the vNIC to JMTest1 and this is what I have a problem with.

  If I add the vNIC through the user interface and then interrogate the security group it gives me below the answer:

  < securitygroup >

  < objectIdobjectId > securitygroup-xx < / objectId >

  < type >

  < typeName > SecurityGroup < / typeName >

  < / type >

  < name > JMTest7 < / name >

  < description / >

  < revision > 9 < / revision >

  < objectTypeName > SecurityGroup < / objectTypeName >

  < scope >

  < id > dvportgroup-xxxxx / < ID >

  < objectTypeName > DistributedVirtualPortgroup < / objectTypeName >

  < name > dv-xxxxx < / name >

  < / scope >

  < extendedAttributes / >

  < inheritanceAllowed > false < / inheritanceAllowed >

  < member >

  500758f6-b97b - 7A 79 - 0c < objectId > 04 - 996f53edf3f0.000 < / objectId >

  < type >

  Vnic < typeName > < / typeName >

  < / type >

  < name > JMTest1 - NIC 1 < / name >

  < revision > 6 < / revision >

  < objectTypeName > Vnic < / objectTypeName >

  < scope >

  < id > vm-xxxxx / < ID >

  < objectTypeName > VirtualMachine < / objectTypeName >

  < name > JMTest1 < / name >

  < / scope >

  < extendedAttributes / >

  < / member >

  < / securitygroup >

  It seems that the < member-moref > for the JMTest1 vNIC is < objectId > 500758f6-b97b - a 7, 79 - 0c 04 - 996f53edf3f0.000 < / objectId >

  If I run now:

  https://192.168.x.x/API/2.0/services/SecurityGroup/SecurityGroup-XX/members/500758f6-b97b-7a79-0c04-996f53edf3f0.000

  then the vNIC is successfully added to the security group. (yay!) So I am now left with the task of how to get

  500758f6-b97b - 7A 79 - 0c < objectId > 04 - 996f53edf3f0.000 < / objectId >

  of a vNIC?

  I have looked at the object in the Mob vCenter and via PowerCLI, but cannot see how to derive from it.

  Anyone know the answer to that?

  The uuid vnic is created by concatenating the vm instanceUuid + '. ' + the last three digits of the vnic device key.  (The vnic is located in the area of the config.hardware.device of the virtual machine and the key will be to shape 4xxx, where xxx represents the 3 numbers you need).

• Need help with query SQL Inline views + Group

  Hello gurus,
  
  I would really appreciate your time and effort on this application. I have the following data set.
  
  Reference_No---Check_Number---Check_Date---description---Invoice_Number---Invoice_Type---Paid_Amount---Vendor_Number
  1234567 11223 - 05/07/2008 -paid for cleaning- 44345563-I-* 20.00 *---19
  1234567 11223 - 05/07/2008 - 44345563 -a--10,00---19 ofbad quality adjustment
  7654321 11223 - 05/07/2008 - setting the last billing cycle - 23543556 - A - 50.00 - 19
  4653456 11223 - 05/07/2008 - paid for cleaning - 35654765 - I - 30, 00-19
  
  Please ignore '-' added for clarity
  
  I'm writing a paid_amount based on Reference_No, Check_Number, Payment_Date, Invoice_Number, aggregate query Invoice_Type, Vendor_Number and display description with Invoice_type 'I' when there are multiple records with the same Reference_No, Check_Number, Payment_Date, Invoice_Type, Invoice_Number, Vendor_Number. When there are no more records I want to display the respective Description.
  
  The query should return the following data set
  
  Reference_No---Check_Number---Check_Date---description---Invoice_Number---Invoice_Type---Paid_Amount---Vendor_Number
  1234567 11223 - 05/07/2008 -paid for cleaning- 44345563-I-* 10.00 *---19
  7654321 11223 - 05/07/2008 - setting the last billing cycle - 23543556 - A - 50.00 - 19
  4653456 11223 - 05/07/2008 - paid for cleaning - 35654765 - I - 30, 00-19
  Here's my query. I'm a little lost.
  
  Select b., A.sequence_id, A.check_date, A.check_number, A.invoice_number, A.amount, A.vendor_number
  de)
  Select sequence_id, check_number, check_date, invoice_number, sum (paid_amount) sum, vendor_number
  of the INVOICE
  Sequence_id group check_date, check_number, invoice_number, vendor_number
  ) A, B OF INVOICE
  where A.sequence_id = B.sequence_id
  
  
  Thank you
  Nick

  It seems that this is a duplicate thread - correct me if I am wrong in this case->

  Need help with query SQL Inline views + Group

  Kind regards.

  LOULOU.

• Started at Mo and not charging with the charger connected. Charger works. Keyboard not workin except power button / stop. Restarted using ex in car without success. SW

  Started MacBook and not charging with the charger connected. Charger works. Keyboard does not not except the power button / stop. Restarted ex drive no available help hoping that it was a matter of SW. SW and the operating system works very well. Read some info online. Tried to reset the SMC. Now, the MacBook does not start. Can U help me please. Thanks in advance.

  MacBook, 2010, Mac OS X 10.6.8

  Hi Veronica Steward,.

  I understand that you have turned into a series of questions about your MacBook and want help getting the computer to turn on. Here is an article that can help you through the steps to fix this problem:
  

  If your Mac will not turn on - Apple Support

  Let us know how it goes and thanks for coming to Apple Support communities.

  See you soon.

• Once a problem with a mobile connection, whenever I try to open a specific site mozilla redirects me to the support of vodafone page, how can I have access to nooz.gr

  After a problem with a mobile connection, I tried with mozilla to connect to nooz.gr , but I've redirected the page services of vodafone, everytime I try again to open this site specific mozilla still redirects me vodafone support page, how can I regain access to nooz.gr?

  Could clear you cookies and cache and check it out.

  • https://support.Mozilla.org/en-us/KB/how-clear-Firefox-cache

  The problem happened when you connect your mobile connection he tries to display the service vodafone page, and it is not updated because of cookie issue.

  Try in safe mode

  • https://support.Mozilla.org/en-us/KB/troubleshoot-Firefox-issues-using-safe-mode

• Seeing orange blinking after that stop with the charger connected.

  Hello

  I'm new here and I have the following problem.

  Four months after buying the PC (Satellite-Z930-103) I had a battery problem. Suddenly the orange led blinking and the laptop could not be launched. Toshiba service replaced the battery and everything worked fine for about two months. Then the same thing happened again. Because I was working in China, I opened the laptop and disconnected the battery and can be used with the charger connected.

  The PC was sent to a point of service when I arrived at home, where they still indicated a battery problem and offered to change the battery. Because the warranty was expired, I had to pay for it. I refused, because the price they were charging was 300 euros.

  To the surprise... when I received it from the point of service, they have reconnected the battery and the service report said "computer does work well, no fault found '...

  Since I started my fight with Toshiba support and tried to find me a solution. However, the problem was not resolved until today and I have to disconnect the battery and plug it in again after waiting a day every time I forgot to unplug the charger when the shutdown or when he goes into sleepmode) I became an expert at opening and closing of the laptop...

  In any case, maybe someone has the same problem and found a solution, I suppose that it may be a software problem, but Toshiba has not solved until today.

  To describe the problem even once:

  Orange (power) led starts flashing as soon as the computer is powered down (or "standby mode") with the charger connected.
  If this happens, I opened the laptop and disconnect the battery (so I can work with feeder pugged in)
  Then the next day I open the laptop again and re-connect the battery. It works fine until I still forget to unpug the charger, turn off or restart the laptop.

  I'm guessing it's a problem of software and a few simple arrangements or a re-installation of something, it can be solved.

  Because I travel a lot, I love the little thing but I got frustrated at the moment.

  It would be great if I'm right, and someone already had this thing resolved!
  THX advance for any help!

  Peter

  Satellite Z930 is very nice machine designed for mobile use and I am really sorry to hear that you have such problems. I imagine that you can't find some identical threads on this forum so I hope this isn't a "general problem" with this machine.

  I am not a technician but I can't imagine this problem described has something to do with the settings of the software. In the BIOS, you cannot change a large part and in windows, there is a standard Windows power settings and several Toshiba avancΘs.
  Electronic power placed in the motherboard has a few 'standard' functions and switch automatically between battery and power running.

  I can't say for sure, but I guess there must be some problem with electronic power supply. It is not easy to say what the problem is here, and I really wonder that Toshiba service provider was not able to identify the reason why all this is happening.

  Let's see what the other members of the forum think problem described.

• Loading slow web page and with Airport Extreme connection speeds

  About 5 days ago, I noticed a significant slow down the loading of web pages. In some cases, I see a blank white screen for up to a minute before the page is loaded. In others, the page never loads at all. And sometimes they load very quickly as expected. This happens with my iMac that is connected to a router via ethernet, as well as my Macbook Air connected via Wifi to Airport Extreme.

  I have a high-speed internet connection by cable Comcast/Xfinity: Blast 250Mbps.

  I tried to connect my iMac directly on the model of cable (Arris Surfboard SB6183), and there is no problem. Download speed was 30Mbps 300Mbps and upload.

  Then, I plugged my Airport Extreme router again and connected the iMac to the router via Ethernet. Download speed dropped to 100 Mbps!

  This suggests that the problem may be with the Airport Express. It is not a wireless problem, because as you can see the download speed went from 300Mbp/s connected directly to the model 100 Mbps when connected to the Airport Extreme.

  How do I troubleshoot/fix this?

  One last thing: I did a speed test with my Macbook Air that is connected via Wifi and the Airport Extreme router. Download speed dropped to 35 MB/s.

  Direct connection to the modem is so very fast, suggesting the internet connection Comcast isn't the issue. Speed falls even with ethernet to the Airport Extreme router connection, then decreases even more with the Wifi connection.