LV PDA 8: Ungroup by name Bug

Similar Questions

• Generates names for "ungroup by name.

  Hello

  I love function cluster "ungroup by name. Yes, it costs a little space in the block diagram, but clearly immediately shows which element is extracted from the most important clusters.

  But sometimes it does not, for example in the case of joint.

  Is there an easy way to give names to the entries? I tried writing in and reading local variables before you consolidate items, but this seems not really effective.

  Yes you can by using beam by name: http://zone.ni.com/reference/en-XX/help/371361M-01/glang/bundle_by_name/

• The enum element chain on ungroup by name

  Hi all

  I have an array of clusters. In these summarize are ENUM constant battery.

  Out of my picture, I can ungroup by name. Then I would get the string name of the element in this enum.

  How is that possible?

  Thank you, Alec

  

• $$cpInfoCourseName$ $ allways gives "Course name" - bug?

  I put the name of my training in the file > settings dialog box as the project name. (I have a German copy, so I don't know the exact English element names)

  When I use $$cpInfoCourseName$ $ within a TextField I allways get "Course name" instead of my own title of training.

  * Where should I set the value of this variable?

  * Is this a bug or I do something wrong?

  Sincerely, Ingo

  Forget this system Variable.  He's going nowhere.

  You can set the name of the route to the file > Info project > project name and use cpInfoProjectName to pick up for display.

• Impossible to change the display name - Bug?

  For the last few weeks, I was able to change my display name. I currently have an invisible name. When I try to click where my name would be to change it, there is nothing there to click. It's for Skype Desktop, I tried on the Skype web and mobile application to change my name, but nothing works.

  Any help is appreciated.

  See you soon

  HS

  Hello

  You can modify you profile - first name and last name that make up your display name in the customers - in my account. Simply log in with your credentials of Skype and go to "Edit profile." Here's a guide: https://support.skype.com/en/faq/FA12314/how-do-i-update-my-skype-profile-information

• Ungroup by name stops at 8 names?

  This is the limit? I have 10 or even 16 channels sometimes connected and I want to split them up to different graphs. What is the unbundle by Cape name to 8 names? I'd be better off using the option to split signals instead?

  
  

• Why my outgoing emails tell me instead of my name

  I noticed that my emails from 'me' instead of Michael that I have in my settings. I don't know where he got the 'me' instead of 'Michael' and can't seem to get his amendment

  Try this info:

  • https://support.Mozilla.org/en-us/KB/names-bug-no-email-addresses-are-displayed

• Build the name of guard of the table of the last element, but not the others. Workaround solution?

  Hello

  Sorry if this has been posted before, I did the search first, but can't find anything.

  Problem is that I have two configurations which are identical and must be ordered by a single vi. Given that they are the same, they are configured with the same sets of parameters so I decided to create a cluster of these and then build an array of clusters. In this way I need to use only a thread and if I need a given parameter I can get it easily from here (or so I thought) and also because I need to see if anything changes I can compare a thread instead of each of the parameters.

  The gui has the list of parameters, then in the block diagram I group them appropiately, using "Bundle name" and then each bundle in a table by using "build the table. Problem is when I have the index in the array for the first place of the configuration and usage to unbundle the parameters I need, using "ungroup by name" (although if I use "Unbundle" the same thing happens) and lo and behol, the output names come from the configuration of the second, not the first.

  Here's the curious thing, though, even if the names are all wrong, that the values are correct. I could live with that, but it's more boring it will be another very difficult user to understand the schema more this is just a proof of principle to test with two, eventually there will be eight or more and who's going to get really confusing.

  Is there a way to get around this? Even if it is to change the names after unbundling.

  Check the attached vi to see what I mean.

  I think you forget an important point on the tables.  The only thing that may be different between each element of a table is its value.  The elements in the array must all share the same properties.  This would therefore include the names of the different elements that make up the cluster that is a table element.

  It seems that the last group that builds in the table is the one that defines the names of the items that are in the element of the cluster.  You must give all elements of the array with the same name within the cluster.  Or use a cluster of clusters rather than a table of cluster to create your data structure.

• Add an element to a cluster without updating all users of the cluster

  I have a cluster that is sent to many different vi. Whenever I have added to this cluster, I need to change every vi that uses it to fix the various controls of input terminals and ungroup by names.

  I'm not change or remove existing items in the source cluster. just to add another element that one worries of the vi "shipwreck" for others, it is simply one don't care. Is it possible to avoid having to fix each "sink" vi when I do this? I would only need to update the vi that uses the new element (which of course, I do anyway).

  In C, I can update, add a member to a typedef'd struct and everything is fine - no problems; How can I do something similar in LV?

  If you branch out a cluster then all sinks must be the same. You should do your cluster a typedef and use the typedef on your screws in this way that you change only one place. Even with the a typedef in C.

  LabVIEW manual contains instructions on how to create and use of typedefs.

• Compare sizes of many paintings

  Background: I made a program that takes 12 inputs and produces a particular movement in my engine based on these values. Now, I want to be able to run a sequence of these motions specified, with different inputs.

  I currently have a version where each of the 12 entries are separate tables. If the program is running in what concerns the scalar version with all the elements of the first and then second everything etc. I have do this a little cleanly by building a table of all tables 1 d 2D. The problem is that if the user forgets to enter any cell or one of the paintings is shorter or longer than the other (due to user error), then the gaps are filled with zeros. It's really bad for my program.

  Go, I thought to prevent it was ensuring that each table entry is the same size and if they are not then raise an error. It would also be good if not the table 2D fill with zeros, that he might fill it with the default value for each input array.

  QUESTION: Is there an easy way to compare the sizes of many tables?

  

  Clearly this always returns true because when I built the table he fills zeros everywhere where a cell was missing.

  I would say that your data structure is wrong.  What you need to do, is have a cluster to contain all the settings for one step.  Then you put it in a table.  This ensures that you have a value for each parameter for each step and makes it easier to the bottom of the line becaue you can use ungroup by name instead of having to the index of the right parameter and you keep the correct data type.

  

• How to access a control known in one reference VI?

  Hello.

  I want to open a Subvi, which is one of the many slot - VI with the same input and output.  But I can't seem to find a way to go directly to one of the terminals.  I think I found a part of the solution in this thread (http://forums.ni.com/t5/LabVIEW/How-can-i-get-the-reference-to-Controls-from-VI-reference/m-p/510319...), but I'm kind of stuck right before the finish line, I think. -Can someone help me with this?

  Below you can see what I have so far.  The path will be changed runtime based on the config files, but controls entry and exit in VI will always be the same.  As you can see, I tried wiring in the type of the VI to the open reference VI block.  I've also attached the sub - VI which indicates what controls and indicators that are used.

  Specifically, I want to be able to enter a number for the control of the input buffer and to be able to read all the flags in the cluster of Test data (preferably using for example. Ungroup by name).

  Thanks a bunch for all help!

  

  If all the SubVIs have the same connector component, you can use the call made by the reference node.

  

• How to pin "Info button" Boolean values of the input data to acquire?

  I am a newbie to LabVIEW. I did this VI referring to this ARTICLE http://digital.ni.com/public.nsf/allkb/CA411647F224787B86256DD000669EFE
  I have problems with taking the values of these pines "Info"... As the functions of 32 buttons, 4 Directions, 8 info axis are wired to 3 Pins?...
  In fact, the goal of my project would be this...
  1 initialize the Joystick
  2. reading axis and Info button
  3 assign characters for each button (a Boolean value) and the axis (-32768 or 32767) as button 1 = Servo1, button 2 = Servo2, Y-Axis(-32768) = MF, Y - Axis (32767) = MB,
  X Axis(-32768) = ML, X-Axis (32767) = Mr... etc...
  4 send the characters to an Xbee Pro connected to the PC with a USB Dongle of Xbee.

  I know it's simple, but such things of convertion and the 'thing' entire component is really confusing... Kindly help me out to the point 3 & 4

  These are clusters.  You can simply use the Ungroup by name in order to leave the values of the components.

• Synchronization of 2 loops while one with a structure of the event.

  Hi fellow users of LabVIEW

  I try to incorporate a structure of the event in my current exisiting VI to Save certain values of control as shown in this post

  http://forums.NI.com/T5/LabVIEW/using-the-quot-make-current-values-default-quot-as-a-control-on/TD-p...

  It's the VI that I use as model with my exisiting VI.

  http://forums.NI.com/NI/attachments/NI/170/547715/1/defaults%20Demo.LLB

  In case the 'stop, change the value' I use in the main VI and a 'real' constant instead of Boolean control of wire structure. While the loops are not connected. The table that I use in my exisiting VI (another while loop) is indexed and unbundled to be used here.

  The work combined well screw and it gives me the results, my question is, in the long run it will give me issues. Do I still need to synchronize?

  Thanks for all the help.

  There's no problem because loop additional lower with the structure of the event.

  Personally, I worry about the top loop. Why so complicated? Why so much duplicate code? Why all these hidden indicators serve as local variables?

  Why don't simply place you the table in the entire cluster in a shift register and the index and ungroup by name wharever value, that you need to access. No hidden local variables or indicators.

• An array of doubles of unbundling

  Hi Forum,

  I need to measure current of 20 channels, so I combined the values of shared variables (one for each channel) 20 tabular, then send to a network variable to transfer data of A.i to B.vi. And then on B.vi, I use 'ungroup by name' to unbundle the cluster in the twenty individual values and indicate one by one.

  My question is, how do I know what value that is out of the twenty variables? I have connected 20 variables shared in the table in a particular sequence, and when I use "ungroup by name' the sequence would be compatible?

  I have attached a screenshot just to explain things better.

  Any help is greatly appreciated!

  Batistuta002

  Yes, it's the same as the first element of the array.

  But you shouldn't be the conversion to a cluster of unbundling.  It's a Rube Goldberg.

  You should use Index Array to get the individual items.

• If I rearrange items in a cluster typedef will all beams and separate also be rearranged?

  I have a fairly large project that is more and more big and I need to add some more to my cluster type-def. I want to reorganize the cluster, mainly for cleanliness but also so similar thing are grouped. If I do this will each bundle by name and ungroup by name also be re-ordered? Or do I go through each subvi and fix all the broken wires and the clusters that are now connected to the wrong items manually?

  If you are using only group by name and unbundled by name, you don't have any problems. I did it several times. I always generally work by using a project if the screws are loaded, but I did it even in the case when the elements are not responsible and have not run into any problems. If you use the Basic Pack and unbundle you can run into trouble. BTW, I certainly have not be as careful as nathand.