Montitor double connection!
I want to connect two lcd monitors to a desktop pc on vista home Prem on the back of the base unit, I have my main monitor in the background vga port and the 2nd monitor plugged the other vga port, 2nd monitor says 'No signal' prospects and the monitors are fine, they have crossed. I have a 2nd vga port for any other reason than to use two monitors? Any suggestions please?
You can also try this:
Right click on the desktop-> graphics options-> output to-> dual display. You can also do it on your graph icon on the Notification area.
Tags: Windows
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Hi masters.
I need display numbers from 1 to 300.
We can achieve this by
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But the need to display table DOUBLE...Try this:
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OF the double
CONNECT BY LEVEL<=>=> -
CONNECTION BY level/prior/root
Hi all
I'm trying to CONNECT BY level/prior/root. But I can barely decipher what it actually does. I think it is a very useful method provided by oracle and can have several uses. can someone help me on this please.
I googled on this topic but everywhere I could find only employee and manager problem that will be solved by query below.
But if we just query as below, we can get the employee and his manage without CONNECT BY.SELECT employee_id, last_name, manager_id FROM employees CONNECT BY PRIOR employee_id = manager_id;
Other queries is obtained to connect by is below, but he could not also include:SELECT employee_id, last_name, manager_id FROM employees;
Please help me.select SYSDATE-41 + level - 1 the_date from dual connect by level <= SYSDATE - SYSDATE-41 + 1
Published by: J2EE_Life on December 6, 2011 08:12J2EE_Life wrote:
Hi allI'm trying to CONNECT BY level/prior/root. But I can barely decipher what it actually does. I think it is a very useful method provided by oracle and can have several uses. can someone help me on this please.
I googled on this topic but everywhere I could find only employee and manager problem that will be solved by query below.
SELECT employe_id, last_name, manager_id
Employees
CONNECT BY PRIOR employee_id = manager_id;But if we just query as below, we can get the employee and his manage without CONNECT BY.
SELECT employe_id, last_name, manager_id
Employees;In fact, those who are not the same.
If you use the standard table of hr.employees, the CONNECT BY query above returns 315 lines, but the secoind query return lines only 107.CONNECTION is useful to show the recursive relationships. It can show you, for example, not only that reports directly to a data manager, but the whole hierarchy of persons under a given head. For example, the following shows the hierarchy starting with an employee named "Rooster":
SELECT employee_id, last_name, manager_id , LEVEL AS lvl , SYS_CONNECT_BY_PATH (last_name, '/') AS path FROM hr.employees START WITH last_name = 'De Haan' CONNECT BY PRIOR employee_id = manager_id; SELECT SYSDATE - SYSDATE-41 + 1 FROM DUAL;
Output:
EMPLOYEE_ID LAST_NAME MANAGER_ID LVL PATH ----------- ---------- ---------- --- -------------------------- 102 De Haan 100 1 /De Haan 103 Hunold 102 2 /De Haan/Hunold 104 Ernst 103 3 /De Haan/Hunold/Ernst 105 Austin 103 3 /De Haan/Hunold/Austin 106 Pataballa 103 3 /De Haan/Hunold/Pataballa 107 Lorentz 103 3 /De Haan/Hunold/Lorentz
Very briefly, here's how it works.
The result set of a query CONNECT BY is the UNION ALL of several queries, all sharing a common SELECT clause.
Any line that meets the conditions of the START WITH clause is supposed to be at LEVEL 1. So you can think of the first branch of the UNION of ALL being (in this case):SELECT employee_id, last_name, manager_id , LEVEL AS lvl , SYS_CONNECT_BY_PATH (last_name, '/') AS path FROM hr.employees WHERE last_name = 'De Haan' UNION ALL ...
Other rows in the result set will be LEVEL = N if the conditions of the CONNECT BY clause, where the PRIOR operator refers to any line level = N - 1.
For example, the line with name = "Hunold" satisfies the condition to connect BY when the FIRST line is the line where last_name = "Rooster", Hunold is in the game with the LEVEL of results = 2.
Another example: the line with name = 'Lorentz' meets the condition to connect BY when the FIRST line is the line where last_name = "Hunold", Hunold is in the result set with LEVEL = 3.
This is a classic example of a tree structure, where the rows in the table are connected to other lines in a parent-child relationship. In a tree, each row has 0 or 1 of the parents, but a line can have any humber children. Haan has 0 parent and 1 child (that is, Hunold). Hunold has 1 parent (De Haan) and 4 children. CONNECT BY queries are useful to deal with the trees like this, especially when the parent-child relationship may extend to a number any levels.Other queries is obtained to connect by is below, but he could not also include:
Select the level - 1 the_date + SYSDATE-41
of the double
connect by level<= sysdate="" -="" sysdate-41="" +="">=>I don't understand whether you.
SYSDATE-SYSDATE is just 0
0 - 41 + 1 is just-40, so you might as well say:select SYSDATE-41 + level - 1 the_date from dual connect by level <= -40;
In addition, LEVEL is always a positive integer, then the CONNECT BY State will never have the value TRUE, and if the CONNECT BY clause can never be TRUE, there is no reason to have a CONNECT BY clause.
A more reasonable request is:SELECT SYSDATE + LEVEL - 1 AS the_date FROM dual CONNECT BY LEVEL <= 4 -- or any positive number ;
which produces this output, the given number of days (4 in this example) from today:
THE_DATE -------------------- 06-Dec-2011 11:08:24 07-Dec-2011 11:08:24 08-Dec-2011 11:08:24 09-Dec-2011 11:08:24
This is a very common way to generate a Counter of Table (a table, or, as in this case, a result set, that matters). For example, if you need for the aggregates per day in a table and you want to show 0 for days that never exist in the table, then you outer join in a table of counter like the one shown above.
This is a common use of CONNECT BY, but this is an unusual exception to the rules that is prohibited govern CONNECT BY queries. I suggest you uderstand how the query on hr.employees, above, the work before you start trying to figure out how it works.Published by: Frank Kulash, December 6, 2011 11:15
The pages below are introductions to CONNECT BY:
http://asktom.Oracle.com/pls/asktom/f?p=100:11:0:P11_QUESTION_ID:489772591421
http://Philip.Greenspun.com/SQL/trees -
Connect by level using the count of the records collection
Hello:
PROBLEM:
...
), (select rownum number months of double connect by level < = Cnt)
Causes not valid ORA-00904 identifier. Why can I not use "Cnt" of my main as request by using a constant in the works?
The value of count is determined for each date range in the section, I return the records that I need?
Thank you, Sidney
BACKGROUND:
I have to be able to display a list of tax returns to my users and the status of these statements. There's no physical feedback so it is necessary to create data dynamically records using appropriate selection. It's not hard and I thought that would be enough to use a connection by level to give me the date, statements of information so that I can calculate and display the individual. However oracle gives me an ORA-00904 when I try to send the "Cnt" value to connect by level. Everything works fine when I provided a constant instead of "CNT". The "CNT" value is determined by a complex process that calculates start and end for several types of return dates, etc as well as the number of periods and frequency of production. The data must be generated dynamically using a master record, which then gives the history of coding in which my collection of basic records is selected. Here is the result of this process:
TaxpayerNo, TaxClass TaxCode, FilingFequency, StartDate, StopDate, Cnt, frequency
10 S 1 M 12-18 6/1/2007-11/30/2008
10 S 2 M 12 10 30/11/2008-9/30/2009
10 S, 2 Q 4 3 11/30/2010-8/18/2011
L 10 8 6/1/2007 9/30/2009 3 1
L 10 8 11/30/1 / 2010 8/18/2011 1
According to the results, I have needs a record for each every month, quarter, etc. ie:
10 S 1 M 6/1/2007 11/30/2008 18 12 6/1/2007
10 S 1 M 6/1/2007 11/30/2008 18 12 7/1/2007
10 S 1 M 6/1/2007 11/30/2008 18 12 8/1/2007
10 S 1 M 6/1/2007 11/30/2008 18 12 9/1/2007
...
10 S 2 M 30/11/2008-9/30/2009 10 12 11/30/2008
10 S 2 M 30/11/2008-9/30/2009 10 12 12/30/2008
...
etc.
DOES NOT WORK
Select y.*, MonthNo, Add_Months(StartDate,MonthNo*Frequency) in)
Select x.*,
(case when FilingFrequency = am' then Ceil (Months_Between (StopDate, StartDate)))
When FilingFrequency = 'Q' then Ceil (Months_Between(StopDate,StartDate)/3)
When FilingFrequency = 'A' Ceil (Months_Between(StopDate,StartDate)/12) then
0 otherwise
end) NTC,
(case when FilingFrequency = am' then 1)
When FilingFrequency = 'Q' then 3
When FilingFrequency = 'A' then 12
end) frequency
de)
... a code complex to calculate values of start and stop dates required above...
) x
), (select rownum number months of double connect by level < = Cnt)
ERROR MESSAGE
The result is ORA-00904: "CNT": invalid identifier. I do not get an error if I use a constant:
WORK WITH THE HELP OF A CONSTANT, BUT MUST HAVE THE VALUE OF THE ACTUAL CNT
... Same code for generating data...
), (select rownum number months of double connect by level < = 3)
How can I get it works using the "CNT" value instead of a constant?A technique like this should solve your problem.
TUBBY_TUBBZ?with data (col1, cnt) as 2 ( 3 select 1, 3 from dual 4 union all 5 select 2, 2 from dual 6 ) 7 select 8 d.col1, 9 t.column_value 10 from 11 data d, 12 table(cast(multiset(select level from dual connect by level <= d.cnt) as sys.OdciNumberList)) t; COL1 COLUMN_VALUE ------------------ ------------------ 1 1 1 2 1 3 2 1 2 2 5 rows selected. Elapsed: 00:00:00.00 TUBBY_TUBBZ?
Contrary to what you have now, which is basically this
TUBBY_TUBBZ?with data (col1, cnt) as 2 ( 3 select 1, 3 from dual 4 union all 5 select 2, 2 from dual 6 ) 7 select 8 d.col1, 9 level 10 from 11 data d 12 connect by level <= d.cnt; COL1 LEVEL ------------------ ------------------ 1 1 1 2 1 3 2 2 1 3 2 1 1 2 1 3 2 2 1 3 10 rows selected. Elapsed: 00:00:00.00 TUBBY_TUBBZ?
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ORA-01436 - connect loop in the user data - only in the database 10G...
Hello
I'm having a problem with a query. First of all I have to say that I choose this query on the internet and has adapted to my worries... so I understand very well the "connection of level" clause... that's why I need help to find out what is happening here...
The query is all ok in a 8i database, but if I took exactly the same query on a 10G database I got the error "ORA-01436 - connect with loop in user data.
This query returns one row for each day between 2 dates passed as parameters. The query takes 4 parameters: a date 'from', date 'for' and 2 other parameters indicating if we want that Saturdays and Sundays (end of week) in the result set.
This is the query:
Select days_between.days
de)
SELECT & date_from + ROWNUM-1 days
DE)
SELECT 1 nothing
OF THE DOUBLE
CONNECTION OF LEVEL < = (nvl(&date_to,&date_from) - & date_from + 1)
)
where & date_from + ROWNUM-1 < = nvl (date_to, & date_from)
) days_between
where (nvl (& exclude_saturdays, 'Y') = ' or replace (to_char (days_between.days, 'DAY'),' ') not in ('SATURDAY', 'SATURDAY'))
and (nvl (& exclude_sundays, 'Y') = ' or replace (to_char (days_between.days, 'DAY'),' ') not in ('SUNDAY', 'SUNDAY'))
For the parameter 'date_from' enter 'to_date('2009-01-01','yyyy-mm-dd')' as a break for the 'date_to' 'to_date('2009-01-07','yyyy-mm-dd')' as a value parameter value. For the other 2 parameters, use 'Y' to exclude this day or "N" to keep this day here in the result set.
So I said earlier, this query runs very well on a 8i database but not on a 10G a where I got the error "ORA01436 - connect with loop in user data.
I have search the Internet but I don't know why it runs on a 8i and not on a 10G... Can someone help me please?Hello
SELECT ROWNUM AS n FROM dual CONNECT BY LEVEL <= x;
is a quick and easy way to generate a table of meters containing all integers from 1 to x. You are the query, it has been changed, not for a list of consecutive integers, but a list of consecutive dates.
This technique only works in Oracle 9 (and more). You did a mistake when you said it works in Oracle 8 but not in Oracle 10? It is the opposite, when I try.
Here is another way to generate a table of counters:
SELECT ROWNUM AS n FROM all_objects WHERE ROWNUM <= x;
This method works in any version of Oracle, but it is slower than the method CONNECT BY and does not work for the great values on x. (this is probably good for x<= 5000,="" depending="" on="" your="">=>
If you can do this:
select days_between.days from ( SELECT &date_from + ROWNUM - 1 as days FROM all_objects WHERE ROWNUM <= (1 + NVL (&date_to, &date_from)) - &date_from ) days_between where ( nvl(&exclude_saturdays,'Y') = 'N' or replace(to_char(days_between.days,'DAY'),' ') not in ('SAMEDI','SATURDAY') ) and ( nvl(&exclude_sundays,'Y') = 'N' or replace(to_char(days_between.days,'DAY'),' ') not in ('DIMANCHE','SUNDAY') ) ;
in any version of Oracle.
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