Need help return correct name of a created the code clip

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• Need help pulling a name string

  Hello I'm on Oracle 11 GR 1 material and have a strings of data like these:
  
  SMITH, KAY C. RN, FNP
  WESTON, DEBRA, L
  ASH, CHRISTOPHER, J., PA - C
  EYEBROWS, CATHERINE J MSN NOCD
  ASH, MICHELLE
  NASH, BOB MC T MD
  BROWN-JONES, LARRY RN
  
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  FIRST NAME
  MI
  CODE (the first one)
  
  So, if we where to watch again the data after it is pulled apart, I would like to see this:

   
  LAST_NAME     FIRST_NAME     MI    CODE 
  SMITH         KAY            C     RN 
  WESTTON       DEBRA          L       
  ASH           CHRISTOPHER    J     PA-C 
  BROW          CATHERINE      J     MSN 
  ASH           MICHELLE 

  That's what I have (this code will be executed on an external Table with 1.5mil lines):

   
  select 
      substr('SMITH, KAY C. RN, FNP',1,instr('SMITH, KAY C. RN, FNP',',')-1) as LAST_NAME, 
      regexp_substr(SMITH, KAY C. RN, FNP', '[^, ]+ ') as FIRST_NAME 
  from dual; 

  I don't know how to get the rest.
  
  Thanks for any help
  
  Published by: Sky13 on September 23, 2011 12:04
  I added a few samples more

  Hello

  Look at the data and try to find some patterns. You will not be able to get everything right, but you may be able to make the most of them.
  I would look for things:
  There always at least 1 comma in the chain? Are you sure that what comes before the (first) comma is always a name?
  When there are 2 commas, codes never come before the 2nd comma?
  Codes always come after the names?
  What parts are sometimes missing? How many times they lack?
  Never just 1 character codes?
  Some codes occur very frequently?
  Is this practice to create a table of the most common codes, or even all the codes?

  It will be much easier in PL/SQL.
  You can write a procedure which takes 1 IN argument (the plain text) and 5 on arguemnts:
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  (2) first name
  (3) other initial
  (4) code
  (5) a number indicating what is the probability that the results are correct. For example, 100 may indicate a very simple string, such as "Dyer, Mary. You can print the with the lowest number for some person to review manually.

  Good luck!

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  Record 2.  ABC1|AVC1|12334|
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  Kind regards
  AAK

  This is because you have not changed the subquery factoring section (aka the WITH clause) properly (I suggest that you are looking for this - it's a very useful piece of syntax to have under your belt). You must change as follows:

  with res as (select rn,
                      txt,
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               from   t), -- assuming that your table is called t.
     final as (select replace(sys_connect_by_path(txt, '$'), '$') full_txt,
                      level
               from   res
               WHERE CONNECT_BY_ISLEAF = 1
               connect by grp = prior grp
               and        rn = prior rn + 1)
  select case when length(full_txt) - length(replace(full_txt, '|')) = 4 then full_txt end full_txt
  from   final
  where  case when length(full_txt) - length(replace(full_txt, '|')) = 4 then full_txt end is not null;
  

  ETA: where 4 appears in my query, you will need to change the number of pipes in your line.
  ETA2: and I suspect that you need to change the 5 in the BluShadow query to 1 + the number of pipes in your line.

  Published by: Boneist on March 23, 2010 17:08

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  Complete recovery manager
  
  SQL >
  
  
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  Best regards

  Hello;

  Have another session with the user of the system will cause rman raise this error. For example another session is used to start the database in nomount is always active mode.

  During the cloning process the rman session must be exclusively connected to the instance auxiliary (no other sessions are allowed).

  Double post

  request for assistance with rman cloning script

  Best regards

  mseberg

  Published by: mseberg on July 31, 2012 05:02

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