NUMBER based on the elements implemented.

Hi all

Sorry I cound not think of a better.

I've been hitting my head against the wall, all that for about a week and the only thing I have to show that it is a headache.

My table examples

WITH tests,)
SELECT 1 AS 'ID', 'Reading' AS 'TEST_TTILE', TO_DATE (null) AS 'EFFECTIVE_DATE', TO_DATE (null) AS "Correspondents" OF the DOUBLE
UNION ALL
SELECT 2, 'Writing', TO_DATE (null), (null) TO_DATE FROM DUAL
UNION ALL
SELECT 3, 'Arithmetic', TO_DATE (null), (null) TO_DATE FROM DUAL
UNION ALL
4. SELECT "basket weaving 101", TO_DATE('01-FEB-2009'), TO_DATE (null) FROM DUAL.
UNION ALL
SELECT 5, "basket weaving 102", TO_DATE('01-FEB-2009'), TO_DATE('28-FEB-2009') FROM DUAL
UNION ALL
SELECT 6, 'prehistoric history', TO_DATE (null), TO_DATE('31-JAN-2009') FROM DUAL
)
SELECT * FROM test


WITH STUDENTS HAVE)
SELECT 1 AS ID, 'Read' AS 'TEST_TTILE', TO_DATE('01-JAN-2009') AS 'TEST_DATE' OF the DOUBLE
UNION ALL
SELECT 1, 'Writing', TO_DATE('02-JAN-2009') OF the DOUBLE
UNION ALL
SELECT 1, 'Arithmetic', TO_DATE('03-JAN-2009') OF the DOUBLE
UNION ALL
SELECT 1, 'prehistoric history', TO_DATE('04-JAN-2009') OF the DOUBLE
UNION ALL
SELECT 2, 'Read', TO_DATE('01-JAN-2009') OF the DOUBLE
UNION ALL
SELECT 2, 'Writing', TO_DATE('02-JAN-2009') OF the DOUBLE
UNION ALL
SELECT 2, 'Arithmetic', TO_DATE('03-JAN-2009') OF the DOUBLE
UNION ALL
SELECT 3, 'Read', TO_DATE('15-FEB-2009') OF the DOUBLE
UNION ALL
SELECT 3, 'Writing', TO_DATE('15-FEB-2009') OF the DOUBLE
UNION ALL
SELECT 3, 'Arithmetic', TO_DATE('15-FEB-2009') OF the DOUBLE
UNION ALL
SELECT 3, 'Basket weaving 101', TO_DATE('15-FEB-2009') OF the DOUBLE
UNION ALL
SELECT 3, 'basket weaving 102', TO_DATE('15-FEB-2009') OF the DOUBLE. "
UNION ALL
Select OPTION 4, 'Writing', TO_DATE('01-MAR-2009') OF the DOUBLE
UNION ALL
Select OPTION 4, "Arithmetic", the DOUBLE TO_DATE('01-MAR-2009')
UNION ALL
4. SELECT "basket weaving 101", TO_DATE('01-MAR-2009') OF the DOUBLE ".
UNION ALL
SELECT 5, 'Read', TO_DATE('15-FEB-2009') OF the DOUBLE
UNION ALL
SELECT 5, 'Writing', TO_DATE('01-MAR-2009') OF the DOUBLE
UNION ALL
SELECT 5, "Arithmetic", the DOUBLE TO_DATE('01-MAR-2009')
UNION ALL
SELECT 5, "Basket weaving 101", the DOUBLE TO_DATE('01-MAR-2009')
UNION ALL
SELECT 5, "basket weaving 102', TO_DATE('01-MAR-2009') OF the DOUBLE".
)
SELECT * FROM STUDENTS


Students take tests in a certain order,
but the existence of a test in a date selection will trigger the search for all the tests in force.

"In force" is
WHERE STUDENTS. TEST_DATE BETWEEN TESTS. TESTS AND EFFECTIVE_DATE. CORRESPONDENTS.
AND THE STUDENTS. TEST_TITLE IS TESTING. TEST_TITLE

What is in effect is always subject to change at the whim of those in "userland".

Date selection could be as close as a day or as wide as infinity.
but the outcome of each student in the trials should be counted only once and
counted as 1 no matter how much testing is in effect at the time.

It is possible for the same student to do the same test several times, but all the tests in force is supposed to be counted.

TESTS of null. EFFECTIVE_DATE indicates the date of entry into force is the beginning of time.
TESTS of null. EFFECTIVE_DATE indicates the expiry date is the end of time.

Charges will be consolidated on MAX (STUDENTS. TEST_DATE) AS "COMPLETION_DATE" for STUDENTS.ID.

Student 1 is counted because all tests in force have been taken.
Student 2 is not counted as test "Prehistoric history" was in force but not taken.
Student 3 is running out because all the tests in force have been taken.
4 student is not counted because test in force, but not 'Read' was taken.
5 student is counted for all the tests in force have been taken.

Can someone show me how to go in the right direction please?

I tried to clarify this but if it does not please let me know.

Thanks in advance for your help,

Lou

Published by: wind on May 11, 2009 14:16

Published by: wind on May 11, 2009 14:20

Hey, Lou,

I'm still not clear about the criteria of selection.
I understand that each student must have completed all the tests that were in force for a certain period, but I don't know what it is from the period.
After reading your last post, I guess the time is actually just a point in time, to the point where the student took his last test (i.e. MAX (test_date).
If I guessed wrong, you may only change the definition of begin_date in the subquery student_date_range, below.

If this query gets good results of your test data, but I don't know it's for the right reason, and this is why I'm not sure that it will work on all the data.

WITH     student_date_range  AS
(
     SELECT       id
     ,       MAX (test_date)     AS begin_date
     ,       MAX (test_date)     AS end_date
     FROM       students
     GROUP BY  id
)
SELECT     end_date
,     COUNT (*)     AS total
FROM     student_date_range     m
WHERE     NOT EXISTS (
                 SELECT  test_ttile
             FROM        tests
             WHERE   NVL (effective_date,  m.begin_date) <= m.end_date
             AND        NVL (expiration_date, m.end_date)   >= m.begin_date
             MINUS
             SELECT  test_ttile
             FROM        students
             WHERE   id     = m.id
                 )
GROUP BY  end_date
ORDER BY  end_date;

As you can see, it's just a matter of seeing if there are all the exams the student should have taken, but did not.
I looked in the NOT EXISTS subquery
b - tests to find which tests the student should have taken, then I looked
(b) to students to see those who take the student.
Find if there is in the first peloton which are not in the second one is simply an operation LESS: (a) (b).

Published by: Frank Kulash, May 11, 2009 18:43

Tags: Database

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