Samples and sample FREQ. / Chan

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• Motorcycle G 2nd Gen global and French freq.

  I plan to use a soon-to-be purchased Moto G 2nd gen Global and leave me puzzled the frequency and speed of the network are compatible (I watch but my sources seem to be mixed).

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• Alternating - Signal Express sampling frequency

  Hi, Im trying to get data using Signal Express + NOR USB-6211, I put the sample rate to 44100 Hz. and everything seems to be ok, but when I checked the data I realized this time column does not increase in a period time constant (ie. sample FREQ not fixed).

  For example:

  1 / (Time (1) - Time (2)) = 43478,26 Hz.

  1 / (Time (2) - Time (3)) = 45454,54 Hz.

  and it constantly alternates between the two frequencies. I have to perform an FFT and Im not sure what is the actual frequency and which continues.

  I appreciate any help on this issue.

  Kind regards.

  This seems to be a bug that NEITHER should be aware of if they are not already.

  If you set the frequency of sampling to 44100, the actual sampling frequency will be (20 MHz / 453) or ~44.150 kHz.  The USB-6211 case has a basis of TIME 20 MHz (±50 ppm) and this clock is divided by an integer to derive the sample clock.  The sampling frequency is always be forced to match to the top if you choose a rate that can only be achieved with a wide divider.  Regardless of what the file shows, map DAQ itself samples at a uniform rate (unless you use an external clock, or something like that...).

  As for the behavior in the column duration... I know exactly how you look at it but I get the same behavior is written my data using 'absolute time' for the time column to an ASCII file (or by using a file LVM, which always uses the absolute time).  With the help of 'on time' however gives me a correct result.  I can't speculate on the cause... it seems likely to me that there is a comma floating rounding error (absolute time is in terms of seconds since 1904, so the software works with a large number at the same time requiring great precision).

  Best regards

• 6036E PCMCIA + DAQmx (analog input) seems to only read in blocks of 512 samples of data

  Hello people,

  I ask this question before I post any code or software versions etc to see if there is a simple answer.

  I use a PCMCIA card 6036E to read an analog input channel (DAQmx... i. e create task, create the channel, set the altimeter (continuous samples), task, read in a programmed software loop while (ASAP)).  No matter how I put my sample rate, number of samples per channel (i.e. size of buffer), or the number of samples to be read, it looks like I can get multiples of 512 samples.

  Here are some samples freq (Fs), the 'number of samples to read' asked and the actual number of samples read:

  FS numberOfSamplesRequested numberOfSamplesActuallyRead

  200Hz   20                                                 512

  1000 1024 5000Hz

  2000 2048 5000Hz

  QUESTIONS RELATING TO THE:

  1 is this 'normal' behavior a 6036E PCMCIA card?

  2. in the case, has anyone who may have seen this problem determined the cause and how to "fix it"?

  Best regards

  Chris

  chassan wrote:

  Hello people,

  QUESTIONS RELATING TO THE:

  1 is this 'normal' behavior a 6036E PCMCIA card?

  Sort of.

  2. in the case, has anyone who may have seen this problem determined the cause and how to "fix it"?

  Best regards

  Chris

  Systems PCI DMA is used to transfer
  the data, daqmx and receive messages when the number of samples are
  acquis. Now on PC-card that does not work and the data is transferred
  When the edge buffer is full (after 2 k of data) to 2 channels
  10 Hz, it can take some time.
  There is a work-around, there is a property where you can set the transfer mechanism (I have not daqmx on this PC), or the daqmx polling mechanism. Try these.

  Found a document KB.

  Tone

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  This VI convolves the signal of impulse response of a simulated servomotor which is essentially a damped sine the input pulse which is a step function.  The signal resulting convolved should be IDENTICAL to that of the step response of the engine which is RED on the display 1.  As you can see the convolution that results in table 2 shows the same structure of frequency, but its magnitude is INCORRECT.  As you can see in the catches of 2 screen sizes differ by a factor of 2 & done the sampling frequency of the wave.  Why the sampling frequency, impact on the scale is also very strange & disturbing.

  Would appreciate any corrections & explanations so that I trust the convolution of the other wave forms of entry than just the step function.

  OK, I think I have it working now.  Your premise on the effect of sampling on the derivative is not the issue.  Does it affect what the FREQ of levy is the basis of time of convolution.  As the convolution product is not continuous but discrete the length of the array should be taken into account & the sampling frequency must be consistent with this length of array as well as 1 second corresponds to 1 second.  If sampling freq is 2 kHz & the length of the array is 1000 then to get the correct time base by a factor of 2 must be taken into account.  In addition, to take account of the DC, shift of the ZERO gain factor must be added to the convolved signal to get the correct size.

  Thanks for making me think more deeply.

• Cross spectral power and consistency of the 2 signals

  Hello

  I try to get the cross-spectral power and consistency of the two signals. I should be able to get this:

  "The cross-spectral power and consistency of these 2 signals have been calculated on a window (8.5 minutes) 1024-sample using the fast Fourier transform applied to the 3 overlapping of the panes of 512-sample in the window of 1024 consistency." In each pane, the data were the first linear straightened and with windows by using the Hanning (cosine) function before the calculation of the Fourier transform. The 1024 coherence window was so advanced by 256 samples (2.1 minutes), and the calculation repeated until all BDUS/interval of N - N series have been analyzed.

  We used the product of consistency and the cross-spectral energy to weight these 2 effects in order to quantify the degree of the hitch.

  I should get this chart type

  

  The RR signal I straightened before that trying to get the power crossed with sampling freq = 2. And I put 2 ways to get it.

  consistency too and later the product of the two. Im trying to get the spectrogram and watch later 3d like picture.

  I have attached the vi.

  Consistency is perhaps badly fixed.

  Thanks for the help, guys.

  Kind regards.

  you made a few mistakes, example en by overhauling it you can't do the segments overlap, that's why you should go with a loop and the creation of a subset (and this is why I suggested para window ASD)

  You must also set the indexing of the product release and do not concatenate, penny you released 2d end that you can use for 3d graphics

  FS in the mathscipt should also be in hz, not in seconds, I told you the last time (he is shown in the help)

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  Hello

  I am using NI Multisim 13.0.I want to generate a signal similar to that illustrated in the accessories acquired using labview that is the output of a phototransistor. The output image contains 10 signals each containing each acquired using 1 k samples and below freq images shows signal components only 1 freq 1 k sample. From the images, it can be analyzed that she has a volatge of 2 DC, 6V, but I'm confused because it contains different frequenices and most (many) frequencies is lying under approximately 1 Hz and some are lying about 135 and 275 to 300 number and very less other frequency components.

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  Hi guys,.

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  Hello Ipaza,

  I watched your VI and found that there are has some problems in the architecture of your consumer producer loops.

  You can get a pre built loop producer consumer using the templates on the start screen.

  I copied the majority of your code in such a model. Could you test this and let me know if this solves some of the question.

  With regrads,.

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  Hi Sbao26975,

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  You can use the link as a reference below: http://social.technet.microsoft.com/Forums/en/itprovistaprinting/thread/460f297a-dd66-4476-a176-542e1519ca3e

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  Bindu S - Microsoft Support
  Visit our Microsoft answers feedback Forum and let us know what you think

• How to get a regular clock (100 MHz, 10 MHz to 20 MHz) of the NI 4462 PCI?

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  Nick Dear,

  Thanks a lot for your help. As you say, this confirms what I already knew.

  But we really need keep everything in harmony. So, here is what I did, which should hopefully help someone else in the same position.

  The circuit is very simple, using a FIN1001 LVDS line driver. It is a SOT-23 package. Connections are the following:

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  * Gnd connects to the Earth (C210, lower)

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  * FIN1001 food is decoupled with a 0.1uF adjacent capacitor.

  * Dout + and Dout-are connected to a short (30cm long) of the unshielded, twisted pair made of wire 0.7 mm PTFE. (Z ~ 110 ohms)

  Photograph is attached. The SOT-23 package is physically secure, with a tiny drop of cyano, C210 and mounted on his back.

  The receiver uses a FIN1002 receiver, finished with 100 ohm twisted pair and uses a 74VHC04 to convert 3.3V 5V TTL.

  It is mounted on a 14 pin DIL socket, to plug directly into the socket on the other card PCI which normally has its own oscillator module.

  Result: everything works, and I have a 100 MHz clock available to drive the other timing card.

• Playback options

  I connected a signal Signal Express. The recorded signal was acquired of sound spectrum of a NI DAQ system. I want to select only part of the spectrum, do a mean quadratic value and then create a snapshot of that part of the sound spectrum medium to export to Excel. This is the step I did:

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  Thank you

  Aitor Aramburu

  The following equation can help you understand your FFT resolution.

  

  Delta-f - resolution FFT

  FS - sampling freq

  N - length of FFT

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• Average of ADC signal

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  Hi sanju,.

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  Sincerely,

  Ray I. Jason Crispo

  jyang72211 wrote:

  1. to increase the resolution, you look at the formula of resoluation, Delta f = (sampling freq) / (number of sample read).  For you, the result is 1 k / 20 k = 20.  You can increase the number of samples read to increase the resolution.

  2. Yes, you must rename the axis.

  3. I think it's just an artifact of the FFT.  Tent to subtract the mean of your data and see you always get the point or not.  Maybe someone can share more about this?

  @jyang, thank you very much for this. I didn't know the formula for resolution. That's why I like forums. I would have never thought than mine.

  I'll try what you say on #3 and post back the result here.

• Cannot hear sound on Adobe Audition CS5.5

  Hi all, I am having trouble with Adobe Audition CS5.5.

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  ASUS P8P67 PRO

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  Master clock: output: Realtek Digital Output (Realtek High Definition Audio)

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  Sampling freq: 44100 Hz

  Post edited by: Harlandraka94

  Harlandraka94 wrote:

  I don't know that my sound card works because I can hear all the sounds windows

  This is almost certainly the root of your problem. Whenever Windows plays a sound, it resets the audio device to its own ridiculous parameters and does not return them later. As it says in the installation instructions very clearly - turn Windows all sounds OFF firmly.

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• Research of two different elements of excel

  Hi all

  I have an excel file and its voltage Freq, DOA, -1, 2, 3 & 4.

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  For clarity, please find sheet excellent the closed.

  If it is not to repeat the means we can easily find but here the value repeat and I am not capable of matching the two line markings.

  Please provide the solution for this case.

  Thank you best regards &,.

  Chick S

  Your data consists of 6 columns laid out like a header line and the lines of several 'data', where all data are numbers (integers, in fact).

  You can easily read all tier 2 on in a 2D array.  To simplify sorting and research you need to do, I counsel created a Cluster of 6 I32s (or slna), called Freq, DOA, 1 Chan, Chan, Chan 3, 2and 4 Chan, then (in a loop For), make it a TypeDef ('My Data') and change the I32s 2D array in a 1 d of my table data.

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