Special characters not showing does not correctly

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  Rothrock,

  With your help, I was able to determine exactly what was going on. You hit the nail head when you mentioned the police include parameters. The people who originally created the file not selected one of the Latin glyphs or no matter what foreign glyphs, so I changed it and republished.

  Another problem was that the XML of files that I saved in Homsite were detects not properly register with the UTF - 8 encoding as default does not read Homesite file encoding when you open a file. I changed the setting and now correctly saves it in a file encoded in UTF - 8. (for those who need to know how to change this setting, go to the top in the Options > settings > file settings > check the box ' Enable non ANSI file encoding. ")

  Thanks for your help, might not have thought of it otherwise!

  Edit: This accidentally marked as the answer, but Rothrock was indeed the answer n the post above...

• special characters not available in interactive pdf format

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  I can't choose the police so I'm stuck with this game?

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  TIA
  Steve42
  
  Published by: Steve42 on May 13, 2013 15:19

  Hello Steve,.

  This is the forum for the tool {forum: id = 260}.
  Please mark this question as answered, while others know that they can ignore it. Then validate again in {forum: id = 75}.

  Concerning
  Marcus

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  Is there some sort of boolean, or function to tell if a character is a member of the Group of SpecialCharacters?

  I need to test if a range of text ends with a carriage return & had used a loop that proved the last character of the items found with myFoundItems [i] .characters [-1].contents.charCodeAt () == 13, which was fine except when the last character is be a special character. Because special characters not properly return a character code, script errors on. I have seen useful messages on filtering & translation of the characters special unicode, but nothing on a simple test.

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  1. to check if the myChar.contents is an element of SpecialCharacters , I think that you can just use the test

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  @+

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• Does not not special characters in the password

  Here's the function I used to apply the oracle password. I can able to use all the numbers, characters, but when I use special as cat (punctarray: ='!) » #$% & ()'' * +,-/ : ; <>=? _';) I can able to use only the characters # when I'm with all the other amazing it gives me an error
  
  
  SQL > alter user u1 identified by nira86 #* wad456j;
  change the u1 user identified by nira86 #* wad456j
  *
  ERROR on line 1:
  ORA-00922: missing or not valid option
  
  
  
  Here's the function
  
  FUNCTION to CREATE or REPLACE verify_function
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  RETURNS boolean IS
  Boolean n;
  whole m;
  different integer;
  Boolean IsDigit;
  because Boolean;
  ispunct Boolean;
  digitarray varchar2 (20);
  punctarray varchar2 (25);
  CharArray varchar2 (52);
  
  BEGIN
  digitarray: = "0123456789";
  CharArray: = 'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ ';
  punctarray: ='! » #$% & ()'' * +,-/ : ; <>=? _';
  
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  IF (password) length < 15 THEN
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  -Check if the password contained at least a letter, a number and a
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  -- 1. Check for the digit
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  m: = length (password);
  FOR I IN 1.10 LOOP
  FOR j IN LOOP 1.m
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  GOTO findchar;
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  END LOOP;
  END LOOP;
  IF IsDigit = FALSE THEN
  raise_application_error (-20003, 'password must contain at least one digit, a character and a punctuation');
  END IF;
  -- 2. Check the character
  < < findchar > >
  car: = FALSE;
  FOR i IN 1.length (chararray) LOOP
  FOR j IN LOOP 1.m
  IF substr (password, j, 1) = substr(chararray,i,1) THEN
  car: = TRUE;
  GOTO findpunct;
  END IF;
  END LOOP;
  END LOOP;
  Because IF = FALSE THEN
  raise_application_error (-20003, ' password must contain at least one------)
  Figure, a character and a punctuation ');
  END IF;
  -- 3. Search for punctuation
  < < findpunct > >
  ispunct: = FALSE;
  FOR i IN 1.length (punctarray) LOOP
  FOR j IN LOOP 1.m
  IF substr (password, j, 1) = substr(punctarray,i,1) THEN
  ispunct: = TRUE;
  GOTO endsearch;
  END IF;
  END LOOP;
  END LOOP;
  Ispunct IF = FALSE THEN
  raise_application_error (-20003, ' password must contain at least one------)
  Figure, a character and a punctuation ');
  END IF;
  
  < < endsearch > >
  -Check if the password is different from the previous password at least
  -3 letters
  Old_password past IF IS NOT NULL THEN
  differ: = length (old_password) - length (password);
  
  IF abs (differ) < 3 THEN
  IF (password) length < length (old_password) THEN
  m: = length (password);
  ON THE OTHER
  m: = length (old_password);
  END IF;
  
  differ: = abs (differ);
  I'm IN 1.m LOOP
  IF substr (password, i, 1). = substr(old_password,i,1) THEN
  differ: = differ + 1;
  END IF;
  END LOOP;
  
  IF different < 3 THEN
  raise_application_error (-20004, ' password should differ by to)
  (minimum 3 characters);
  END IF;
  END IF;
  END IF;
  -Everything all right; Return TRUE;
  RETURN (TRUE);
  END;
  /

  What version of Oracle are you using? Before 11 g I think only allowed special characters were '_', ' $' and ' # '.

  And 11 g, you need to put the password in quotation marks and must not use comma, backslash or double quote.

• validation to check him point does not contain any special characters except ' - '.

  Hi all
  
  I have a question and the need to create a validation so that the item does not contain special characters (or numbers or spaces) other than salvation fen. That is to say, the element must contain only alphabets or ' - '. Tried to use the Is_Alpha function, but do not know how to handle this exception to the use of '-' in validation. So please, can someone suggest me a solution.
  
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  You can create Validation based on return Boolean and returns a False when the element has charecters other than 'A - Z' (charecters upper and lower) and - (hifen).

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  Based on the following sql instructions...

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    3     from dual;
  
  NVL(TRIM(T
  ----------
  Null Value
  
  sql> ed
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    1  select nvl(trim(translate(upper('9999Asf---'), 'ABCDEFGHIJKLMNOPQRSTUVWXYZ-',
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    3*    from dual
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  NVL(
  ----
  9999
  

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  Follow these steps to change the print settings by default for all printing from the desktop of Windows 8.

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  }
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      }
  ]
  

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