sqlldr - replace "NULL" string value NULL?

Similar Questions

• Replace the string value of table

  with cte as)

  Select val '123', 'abwec' double val1

  Union of all the

  Select "456" val, "mowerw" double val1

  Union of all the

  Select val '709', 'wkwere' double val1

  Union of all the

  Select val '078', 'awerwewerwreq' double val1

  )

  Select * from cte;

  -incoming string

  "asdasd123ewrwer@87w8eopiu456werwer@asdwer709@ewrwerewrwqqwezxder078 @..."

  need to replace like 'abwec' 123 and 456 as "mowerw" and 709 as wkwere and 078 as 'awerwewerwreq '.

  How to replace the string value of the string

  I'm going to the table which will have mapping information I need to see the incoming string and replace the appropriate value of the val to val1

  something like

  Of

  "asdasd123456werwer@asdwer709@ewrwerewrwqqwezxder078ewrwer@87w8eopiu @..."

  TO

  "asdasdabwecewrwer@87w8eopiumowerwwerwer@asdwerwkwere@ewrwerewrwqqwezxderawerwewerwreq@..."

  By using the TYPE clause.

  with cte as

  (

  Select val '123', 'abwec' double val1

  Union of all the

  Select "456" val, "mowerw" double val1

  Union of all the

  Select val '709', 'wkwere' double val1

  Union of all the

  Select val '078', 'awerwewerwreq' double val1

  ),

  input_tbl

  as

  (

  Select "asdasd123ewrwer@87w8eopiu456werwer@asdwer709@ewrwerewrwqqwezxder078 @..." input_str

  of the double

  )

  Select max (input_str) Dungeon (first order by desc NWR dense_rank) input_str

  de)

  Select rno, input_str

  de)

  Select rownum NWR

  val

  val1

  input_str

  count (*) over() cnt

  from cte

  Cross

  Join input_tbl

  )

  model

  dimension (NWR)

  measures (val, val1, cnt, CAST (input_str AS VARCHAR2 (4000)) input_str)

  (

  input_str [any] = replace (nvl (input_str [cv () - 1], input_str [cv ()]), val [cv ()], val1 [cv ()])

  )

  )

• Replace NULL values with 0 to Pivot

  Hi all
  
  I use a union query, I need to display 0 instead of NULL values. I tried various methods such as ifnull(), case; I could see in the table, but not in pivot of 0.
  I tried and succeeded in placing '-' instead of null. If I put a line chart the chart seems meaningless.
  Can someone suggest me this chart & pivot.
  
  Thanks in advance,
  Jerome

  Hi Leila,

  Hope this link helps you

  [http://total-bi.com/2010/10/replace-nulls-in-obiee-pivot-table/]

  By,.
  KK

• Find and replace the delimited string value by the

  Hi all

  I have a requirement where I need to find and replace the delimited string values.

  For example, the string is "GL ~ 1001 ~ 157747 ~FEB-13~ CREDIT ~ A ~ N ~ US ~ NULL ~". The 4th column gives the month and year. I need to replace it with the name of the previous month. For example: "GL ~ 1001 ~ 157747 ~JAN-13~ CREDIT ~ A ~ N ~ US ~ NULL ~". I need to do the same thing for the past 12 months.

  I thought initially divide the values and store it in a variable and then after him substituting the value required, join the return.

  I just wanted to know if there is a better way to do it?

  Like this:

  with a model like

  (select "GL ~ 1001 ~ 157747 ~ FEB-13 ~ CREDIT ~ A ~ N ~ $ ~ NULL ~' double UNION ALL data")

  Select ' GL ~ 1001 ~ 157747 ~ JAN-13 ~ CREDIT ~ A ~ N ~ US ~ NULL ~' double data)

  Select

  REPLACE (DATA, TO_CHAR (to_date (substr (data, 16.6), "MON-RRRR"), 'MON - RR'), TO_CHAR (to_date (substr (data, 16.6), "MON-RRRR")-1, 'MON - RR'))

  modeling;

  GL ~ 1001 ~ 157747 ~ JAN-13 ~ CREDITS ~ HAS ~ N ~ US ~ NOTHING ~

  GL ~ 1001 ~ 157747 ~ DEC-12 ~ CREDITS ~ HAS ~ N ~ US ~ NOTHING ~

  Ishan

• RTF model - replace null with 0

  Hello
  
  I created an RTF model for burst into BI Publisher. For specific fields I use COUNT/SUM functions, I find here where there is no value returned in a calculation does not return NULL (Blank). Is is possible to replace with 0 instead? I am also using a conditional region where point is equivalent to... and using a COUNT/SUM function to roll up the data.
  
  I just want to replace NULL values with 0
  
  Can anyone help?
  
  Thank you

  Were you able to solve this problem?
  If not send an email with your sample xml and RTF

• How to use CFPARAM with a list of string values

  Hi all

  I have a field value that can be stored with multiple values for a single record: Work_Order = '555555,666666,111111' (note that these are actually stored as a single string value in the comics with commas.)

  I need to analyze this field and enter a new query clause where the string values:

  < CFSET WOIDS = CapProjects.Work_Order >

  < cfloop condition = "#find(',,',WOIDS) #" >

  < cfset WOIDS = "#rereplace (WOIDS, ',',', null, ',' ALL') #" > < br >

  < / cfloop >

  < cfquery name = "CapProjectsWOIDS" datasource = "#URL. DB #">"
  SELECT [ENGOPSMTRLSID]
  [Work_Order]
  OF ENGOPSMTRLS
  WHERE
  < CFOUTPUT >
  ENGOPSMTRLSID = #URL. INDEX #.
  < / CFOUTPUT >
  AND
  < CFOUTPUT >
  Work_Order in (< cfloop index = list "idx" = "#variables.) WOIDS #">"
  < cfqueryparam
  value = #WOIDS #.
  cfsqltype = "cf_sql_varchar".
  list = 'true '.
  (/ > < / cfloop >)
  < / CFOUTPUT >
  < / cfquery >

  I'm doing this right? I get the following error: error running query database. [Macromedia] [SQLServer JDBC Driver] [SQL Server] Incorrect syntax near '@P4 '. What's the length of the loop? How do I drop?

  Thank you

  John

  First of all, you need not use CFOUTPUT in a CFQUERY (or most / all other CFtags)-CF knows.

  Second, you need not complete a list for an 'IN '.  Unless you use a dark database is not MS - SQL, MySQL or Oracle.  And you already know that CFQUERYPARAM has an attribute from the list.

  NOTE: This assumes that the Work_Order data type is char or varchar, not whole.

  
    SELECT [ENGOPSMTRLSID]
        ,[Work_Order]
    FROM ENGOPSMTRLS
    WHERE  ENGOPSMTRLSID = #URL.INDEX# /* <--- I didn't see URL anything, before this.  And I REALLY cannot stress how bad of an idea it is to use a URL variable for your DSN.  Just sayin'.  */
  AND
    Work_Order in  ()
  
  

  Given that you use for the varchar type, you must put quotation marks around the value (line 08), as I have demonstrated.

  HTH,

  ^_^

• Replace the text values

  Hello.

  I have problem with replacement of values in text strings and I can't find a solution.

  I have two or three channels filled with only 2 values: OK and NOK. How can I replace these values with for example 1 for OK and 0 for NOK?

  This replacement is necessary for drawing a chart. I can't draw the chart because the tiara do not accept the values of text like a ladder with the current values.

  Thanks in advance :-)

  Hello Domin,

  replaces a substring in a text with another text can be done with VBS 'Replace' function

  The execution of a function on an entire channel can be made using ChnCalculate.

  Combine the two and you get:

  ("ChnCalculate ("ch ()"" statistics text"" "") = Replace (ch ("' statistics text" "" '), '' value' ', "" LLL"") ")

  It is a channel in the DIAdem example data set. The above command executes the command "Replace" for each value of the text string "text of statistics". He replaces each occurrence of 'value' by 'LLL '.

  Hope this helps

  Andreas

• splitting the query string values

  all,
  I do not remember this, but my problem is that I have a collection of forwarded to my query as string values "X 234234: 23466 X: X 03287: X 457675 ', so my request should be able to divide each data value and use in the filter as below,
  
  Select * from emp where EmpID in ("X 234234: 23466 X: X 03287: X 457675")
  
  so, how can I divide each individual value and pass through the filter?
  
  Thank you.

  SELECT trim(x.column_value.extract('e/text () ')) CLO
  Of
  TABLE (XMLSEQUENCE (XMLTYPE (""
  || REPLACE ('1:2:3:4:6:7:8',': ','')
  || ((("").extract('e/e'))) x

  Try customizing the syntax above using the column in the function replace instead of my hard-coded string and pass it to the filter predicate using an in operator.

  Edited by: Chandrakaanth Ramamurthy on April 25, 2013 16:29

• Find + replace text (string constant) does not work for screw Statechart module

  Hello

  I tried to do a mass find + replace a string in my code. Using Ctrl + F, LabVIEW 2012 correctly locates all the places where this string exists, including within the States transitions guards who have paths in this form:

  XYZ.lvsciagram.vi / Transition: Guard - diagram, Transition, data/part

  However, when I've specified that a replacement string, then click on 'Replace all', only 'normal' instances of screws replaced - instances in my diagrams had not changed.

  What is going on? Is there anything else I need to do?

  Thanks in advance.

  Looks like those that does not include how to find and replace is implemented in LabVIEW. You can try to replace just the statechart and see if that makes a difference, but it may simply not work.

• How to use a String function Find() during a Test of a string value?

  Hello

  I intend to match a substring of the string returned by my USE when the use of a string value test - call of VI.

  I write the string returned for a string variable local (Locals.data_read) and tab limits - under the expected string value using Find (Locals.data_read, 'Connected'). When I check the expression to find errors - I get a warning "expected a string number found {comma floating 64}.» This value will cause a runtime error. »

  What Miss me?

  Thank you

  Kech

  Here is an example showing both.

• Save the alphanumeric string value

  Hello!
  How to save a value to a variable so that I can use it in the future? I have a string of output of a case structure proposed by an OK botton. I want to save the string value when I press the ok botton...
  Thanks in advance
  GM

  Just write the string in a text file.  When you want to use it later, to read the text file.

• Search and replace the string formatting

  Hello

  I try to do a search and replace the formatting of a string.

  In the example, I'm looking for the string 'SUCCESSFUL', but it must also begin by usbflash and some number + PASSED.

  I can't get the format to have a number between 1 and 99. The number of replacements should add up to 6 in this case. I tried with \d for any number, and I also tried [1-99].

  Make a right-click on the function search and replace the string.  There is an option to use regular Expressions.  Then give it a try.

  

  EDIT: You need to set the entry replace all to TRUE.

• Have to reset the flag of string value

  Hello everyone

  I'm trying to reset the flag of string value.

  I use node string indicator property to change the color, its evolution, but when the program runs again it should start default how to do it. Thanks in advance

  Here, it's in 2009

• Put the string value in a table

  Hello

  Probably an easy question, but I am reading data of a RFID reader that returns a string value of 12 bytes. Whenever a RFID reads, I want the tag to be inserted in a string table on the front panel. So, basically, a newspaper of the each tag [read-> Insert row 0] then [read-> Insert level 1] and so on. I work RFID reader, I don't know how to put the string in the table.

  

  I'm not sure of the steps necessary to achieve control of the table (or if the table control is the right thing to use).

  Any help would be greatly appreciated. Thank you.

  
  

• replace a string

  is it possible to replace a string? I mean, as in any programming language when you:

  String data = "abc";

  data = 'zxc ';

  I am trying to get the substrings of an initial string like '123.456.789.432.567' separated by the "." character, and when I get "123" at the first iteration, I do not know how to init the second iteration with "456.789.432.567" that I can't change the original string the process gets.

  Thank you

  A quick detour to the String\ vi.llb\Advanced might help a little to that.

  

  but the Crossrulz method has merit too.

  

  This period can be a delicate delimiter!