UNPIVOT day after day in the data range

Hi all, I am new to this forum. I have this table

name	startDT	endDT	value
car	1 January 14	January 3, 14	10
boat	2 January 14	5 January 14	11
plane	7 January 14	7 January 14	12

and I want this result:

day	name	value
1 January 14	car

102 January 14car10January 3, 14car102 January 14boat11January 3, 14boat11January 4, 14boat115 January 14boat117 January 14plane12

As many tanks

I give you one example. Use the query like this

Select t.nom,

t.startdt + Level-1,

t.Valeur

of t

connect by level<=>

and first name = name

and prior sys_guid() is not null

----

Ramin Hashimzade

Tags: Database

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< cfset variables.getdate = DateAdd (would be ',-30, now()) >

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of tabletest
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the sql stmt above does not work.
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Ken

SUM (case use this structure to get average values on the date range

I use:

Oracle SQL Developer (3.0.04) build hand - 04.34 Oracle Database 11 g Enterprise Edition 11.2.0.1.0 - 64 bit Production

How do we use the function sum with a structure of matter inside.

so I gave that looks like have an ID, date and value. I'm looking to get the day 7 medium for the date range of 04/01/2013 to 20/04/2013

with t as (
select 1 ID_Key,to_date('4/1/2013','mm-dd-yyyy') date_val, 10 Value_num from dual union all
select 1 ID_key,to_date('4/2/2013','mm-dd-yyyy'), 15 from dual union all
select 1 ID_key,to_date('4/3/2013','mm-dd-yyyy'), 20 from dual union all
select 1 ID_key,to_date('4/5/2013','mm-dd-yyyy'), 0 from dual union all
select 1 ID_key,to_date('4/8/2013','mm-dd-yyyy'), 12 from dual union all
select 1 ID_key,to_date('4/9/2013','mm-dd-yyyy'), 8 from dual union all
select 1 ID_key,to_date('4/10/2013','mm-dd-yyyy'), 6 from dual union all
select 1 ID_key,to_date('4/12/2013','mm-dd-yyyy'), 10 from dual union all
select 1 ID_key,to_date('4/13/2013','mm-dd-yyyy'), 0 from dual union all
select 1 ID_key,to_date('4/14/2013','mm-dd-yyyy'), 0 from dual union all
select 1 ID_key,to_date('4/15/2013','mm-dd-yyyy'), 10 from dual union all
select 1 ID_key,to_date('4/16/2013','mm-dd-yyyy'), 5 from dual union all
select 1 ID_key,to_date('4/17/2013','mm-dd-yyyy'), 2 from dual union all
select 1 ID_key,to_date('4/20/2013','mm-dd-yyyy'), 3 from dual union all
select 2 ID_key,to_date('4/3/2013','mm-dd-yyyy'), 12 from dual union all
select 2 ID_key,to_date('4/5/2013','mm-dd-yyyy'), 15 from dual union all
select 2 ID_key,to_date('4/6/2013','mm-dd-yyyy'), 5 from dual union all
select 2 ID_key,to_date('4/7/2013','mm-dd-yyyy'), 7 from dual union all
select 2 ID_key,to_date('4/9/2013','mm-dd-yyyy'), 10 from dual union all
select 2 ID_key,to_date('4/11/2013','mm-dd-yyyy'), 5 from dual union all
select 2 ID_key,to_date('4/12/2013','mm-dd-yyyy'), 0 from dual union all
select 2 ID_key,to_date('4/13/2013','mm-dd-yyyy'), 0 from dual union all
select 2 ID_key,to_date('4/15/2013','mm-dd-yyyy'), 6 from dual union all
select 2 ID_key,to_date('4/16/2013','mm-dd-yyyy'), 8 from dual union all
select 2 ID_key,to_date('4/17/2013','mm-dd-yyyy'), 0 from dual union all
select 2 ID_key,to_date('4/18/2013','mm-dd-yyyy'), 10 from dual union all
select 2 ID_key,to_date('4/19/2013','mm-dd-yyyy'), 5 from dual
)

* Please let me know if the table does not load.

I would get the average of 7 days, as long as there is date for the rank of enough previous dates, is it not, then it returns a null value.

the results should look like this

ID_Key      date_val     Value_num     7Day_Avg     7Day_Avg2
1     4/1/2013     10          null          null
1     4/2/2013     15          null          null
1     4/3/2013     20          null          null
1     4/5/2013     0          null          null
1     4/8/2013     12          6.71          11.75
1     4/9/2013     8          5.71          10.00
1     4/10/2013     6          3.71          6.50
1     4/12/2013     10          5.14          9.00
1     4/13/2013     0          5.14          7.20
1     4/14/2013     0          5.14          6.00
1     4/15/2013     10          4.86          5.67
1     4/16/2013     5          4.42          5.17
1     4/17/2013     2          3.85          4.50
1     4/20/2013     3          2.86          4.00
2     4/3/2013     12          null          null
2     4/5/2013     15          null          null
2     4/6/2013     5          null          null
2     4/7/2013     7          5.57          9.75
2     4/9/2013     10          7.00          9.80
2     4/11/2013     5          6.00          8.40
2     4/12/2013     0          3.86          5.40
2     4/13/2013     0          3.14          4.40
2     4/15/2013     6          3.00          4.20
2     4/16/2013     8          2.71          3.80
2     4/17/2013     0          2.71          3.17
2     4/18/2013     10          3.43          4.00
2     4/19/2013     5          4.14          4.83

As you can see, there are gaps in the dates, the value is then processed by zeros for the 7Day_Avg and then ignored for the 7Day_Avg2 (not counted in the number of days on average do to no valu_num line)
I tried something like this at first, but becomes "missing keyword" error

select
t.*/,
sum(
      case 
        when date_val between :day2 - 6 and :day2
        then value_num between date_val - 6 and date_val
        else null
        end
        )
        as 7Day_avg

form t

Should I have the structure outside the sum function?

Any thoughts?

Published by: 1004407 on June 7, 2013 11:06

Hello

If you want to calculate the average of the last 7 days, including the current day, then then RANGE should be 6 PRIOR, not 7.

Try this:

WITH got_min_date_val AS

(

SELECT id_key, date_val, value_num

MIN (date_val) compared to (AS min_date_val)

WHERE the date_val BETWEEN TO_DATE (April 1, 2013 ', "dd-mm-yyyy")

AND TO_DATE (April 20, 2013 ', "dd-mm-yyyy")

)

SELECT id_key, date_val, value_num

CASE

WHEN date_val > = min_date_val + 6

THEN SUM (value_num) OVER (PARTITION BY id_key

ORDER BY date_val

PRIOR TO TIER 6

)

/ 7

END AS avg_7_day

CASE

WHEN date_val > = min_date_val + 6

THEN AVG (value_num) OVER (PARTITION BY id_key

ORDER BY date_val

PRIOR TO TIER 6

)

END AS avg_7_day_2

OF got_min_date_val

ORDER BY id_key

date_val

;

Output:

ID_KEY DATE_VAL VALUE_NUM AVG_7_DAY AVG_7_DAY_2

---------- --------- ---------- ---------- ------------

1 1 APRIL 13 10

1 2 APRIL 13 15

1 APRIL 3, 13 20

1 5 APRIL 13 0

1 APRIL 8, 13 12 6.71 11.75

1 APRIL 9, 13 8 5.71 10.00

1 APRIL 10 13 6 3.71 6.50

1 12 APRIL 13 10 5.14 9,00

1 13 APRIL 13 0 5,14 7.20

1 14 APRIL 13 0 5,14 6.00

1 15 APRIL 13 10 4.86 5.67

1 16 APRIL 13 5 4.43 5.17

1 APRIL 17, 13 2 3.86 4.50

1 APRIL 20, 13 3 2.86 4.00

2 APRIL 3, 13 12

2 5 APRIL 13 15

2 6 APRIL 13 5

2 7 APRIL 13 7 5.57 9.75

2 9 APRIL 13 10 7,00 9.80

2 11 APRIL 13 5 6.00 8.40

2 12 APRIL 13 0 3.86 5.40

2 13 APRIL 13 0 3.14 4.40

2 15 APRIL 13 6 3.00 4.20

2 16 APRIL 13 8 2.71 3.80

2 17 APRIL 13 0 2.71 3.17

2 18 APRIL 13 10 3.43 4.00

2 APRIL 19, 13 5 4.14 4,83

Post edited by: FrankKulash

Sorry; I wanted to respond to OP, not Greg

Get number of records in the date range - IDE: PLSQL Developer
I want to count the number of records of members who register within a date range specified, based on effective and expiration dates and their "elg_code". I posted the SQL code for some examples of data. What I would like to see returned is in three columns of the counties where the eff_date date_exp members fall within the date range specified by the SQL and have an Elg_code of ' ' (space).

So what I would like is all members with elg_code ' ' where he eff_dt and exp_dt range is April 2012, 2012 MAY & JUN 2012. Thus, according to data from the sample I posted, Mark, where his elg_code record is ' ', his eff_dt is 01/01/2011 and April 2012 (30/04/2012) is his exp_dt. Range of the brand statement may 2012, but not MAY or JUNE of 2012. Marty would tally for the APR and MAY because his eff_dt is before MAY 2012 and his exp to MAY 2012. etc...

According to the data below, the results should resemble:

APR MAY JUN
4-3-2

APR should have FRANK, MARK, MARTY, MARY.
MAY should have FRANK, MARTY, MARY
JUN should have FRANK and MARIE

NOAM and JOHN should not appear as his records with elg_code ' ' have no documents eff_dt and exp_dt which are April-June 2012.

So what I tried without success as it appears that I have a kind of Cartesian question (?), is:

Select count (m1.mbr_name) APR,
Count (m2.mbr_name) MAY,
Count (m3.mbr_name) JUN
mbr2 M1,
mbr2 m2,
mbr2 m3
"where m1.eff_dt < ' 01 - may - 2012"
"and m1.exp_dt > ' 01-Apr-2012.
and m1.elg_code = ' '
"and m2.eff_dt < 1 June 2012"
"and m2.exp_dt > ' 01 - may - 2012"
and m2.elg_code = ' '
"and m3.eff_dt < 1 July 2012"
"and m3.exp_dt > 1 June 2012"
and m3.elg_code = ' '

Here's the DML

Thanks for any help!

create table mbr2 (mbr_name varchar (10), varchar (1) grpid eff_dt date, date of exp_dt elg_code varchar (1))
Commit

insert into mbr2 values ('BRAND', 'A', to_date (January 1, 2011 ',' DD-MM-YYYY '), to_date (April 30, 2012 ',' DD-MM-YYYY '), ' ')
insert into mbr2 values ('BRAND', 'A', to_date (May 1, 2012 ',' DD-MM-YYYY '), to_date (31 December 2013 ',' DD-MM-YYYY '), 'C')

insert into mbr2 values ('MARTY', 'A', to_date (January 1, 2011 ',' DD-MM-YYYY '), to_date (May 31, 2012 ',' DD-MM-YYYY '), ' ')
insert into mbr2 values ('MARTY', 'A', to_date (June 1, 2012 ',' DD-MM-YYYY '), to_date (31 December 2013 ',' DD-MM-YYYY '), 'C')

insert into mbr2 values ('FRANK', 'B', to_date (January 1, 2011 ',' DD-MM-YYYY '), to_date (June 30, 2012 ',' DD-MM-YYYY '), ' ')
insert into mbr2 values ('FRANK', 'B', to_date (July 1, 2012 ',' DD-MM-YYYY '), to_date (31 December 2013 ',' DD-MM-YYYY ""), 'C')

insert into mbr2 values ('MARY', 'B', to_date (January 1, 2011 ',' DD-MM-YYYY '), to_date (June 30, 2012 ',' DD-MM-YYYY '), ' ')
insert into mbr2 values ('MARY', 'B', to_date (July 1, 2012 ',' DD-MM-YYYY '), to_date (31 December 2013 ',' DD-MM-YYYY ""), 'C')

insert into mbr2 values ('JOHN', 'C', to_date (January 1, 2011 ',' DD-MM-YYYY '), to_date (July 1, 2011 ',' DD-MM-YYYY '), ' ')
insert into mbr2 values ('JOHN', 'C', to_date (July 1, 2011 ',' DD-MM-YYYY '), to_date (1 January 2012 ',' DD-MM-YYYY ""), 'C')

insert into mbr2 values ("NOAM" 'd', to_date (July 1, 2012 ',' DD-MM-YYYY '), to_date (31 December 2013 ',' DD-MM-YYYY '), ' ' ")

Commit
This gives you a report for the current month and the two front. Column header must be adjusted ;-)
```
select
  count(
  case
  when
    eff_dt < add_months(trunc(sysdate,'MM'), -1)
    and
    exp_dt >= add_months(trunc(sysdate,'MM'), -2)
  then 1
  end) April
, count(
  case
  when
    eff_dt < add_months(trunc(sysdate,'MM'), 0)
    and
    exp_dt >= add_months(trunc(sysdate,'MM'), -1)
  then 1
  end) May
, count(
  case
  when
    eff_dt < add_months(trunc(sysdate,'MM'), 1)
    and
    exp_dt >= add_months(trunc(sysdate,'MM'), 0)
  then 1
  end) June
from mbr2
where
elg_code = ' '
and
eff_dt < add_months(trunc(sysdate,'MM'), 1)
and
exp_dt >= add_months(trunc(sysdate,'MM'), -2)

APRIL     MAY     JUNE
4     3     2
```

On the date ranges in search of oracle forms
I use service number, name, type person and date as search criteria in the custom form ranges.
When I enter the employee number, press the search button, I get the exact info in the block of result.
Result block contains
name of the employee, personid, emp numbed, org, start_date.
Similarly when I enter the employee number, dept, I get the correct values.
My question is, when I enter the date range. IAM unable to filter the data.
When I enter START_DATE between nvl(:BLOCKNAME.) Start_date, 1 January 1901 ') and nvl(:BLOCKNAME.) End_date, 31-DEC-4712') where block clause in the result. I had data for the range of dates also.

If I give condition in where clause results take so long when I search with the name of the employee, number, dept, person type.

If I have a query with the date, the persormance is good.

Think you know everything, how it prevents START_DATE between nvl(:BLOCKNAME.) Start_date, 1 January 1901 ') and nvl(:BLOCKNAME.) End_date, 31-DEC-4712') when look us with the employee's name, number, dept, person type.
So leave the WHERE clause of your empty block and put something like the following in your search button:
```
IF    :BLOCK.START_DATE IS NOT NULL
   OR :BLOCK.END_DATE IS NOT NULL THEN
  SET_BLOCK_PROPERTY('YOURBLOCK', ONETIME_WHERE, 'START_DATE between nvl(:BLOCKNAME.START_DATE,TO_DATE(''01-JAN-1901'', ''DD-MON-YYYY'')) and nvl(:BLOCKNAME.END_DATE,TO_DATE(''31-DEC-4712'', ''DD-MON-YYYY''))');
END IF;
```

by selecting specific days of the week for the date range?
I have a table with a number of clients for about a year, but I want to only select Wednesday and Thursday of
every week, since the beginning of the dates. Table is simple and has two columns. Each line is separate from a Date
There is no duplicate of Date, it is counted for every day of the year.

column 1: number of clients, count (customer_id)
column 2: Date

Need help with the best way to achieve this.

Not sure if it is even possible to select a date in the name of the day?

Basically, I want to select every Wednesday and Thursday of each week and compare the counts during the week, the week during
week for the whole week see if charges go upwards or downwards, to get trends, thank you!
Hello

Kodiak_Seattle wrote:
I have a table with a number of clients for about a year, but I want to only select Wednesday and Thursday of
every week, since the beginning of the dates. Table is simple and has two columns. Each line is separate from a Date
There is no duplicate of Date, it is counted for every day of the year.

column 1: number of clients, count (customer_id)
column 2: Date

Need help with the best way to achieve this.

Not sure if it is even possible to select a date in the name of the day?

Sorry, we don't know what you want.

To see if a date given (dt) is a Wednesday or Thursday, you can use:
```
WHERE   TO_CHAR ( dt
          , 'DY'
          , 'NLS_DATE_LANGUAGE=ENGLISH'     -- If necessary
          )  IN ('WED', 'THU')
```
I hope that answers your question.
If not, post a small example data (CREATE TABLE and only relevant columns, INSERT statements) for all of the tables involved and also publish outcomes from these data.
Explain, using specific examples, how you get these results from these data.
Always say what version of Oracle you are using (for example, 11.2.0.2.0).
See the FAQ forum {message identifier: = 9360002}

Can I remove the day of the date of blog?

Hello, can someone help with this? I went through the documentation and google, I can't find an answer.
How can I remove the day of the blog post so that the date reads simply "18 March 2015' and not 'Wednesday, 18 March 2015? '"
I use this {tag_blogpostdate}, none of the other tags of here give me that http://docs.businesscatalyst.com/dev-assets/reference#! / tag-reference/Articles/blog-post-deta they - layout.html And I can't find anywhere that shows me how to customize IT.

You can not, you have all the options except if you activate beta liquid markup and BC.next and then use the liquid and then apply the date filter. A little a lot right now, if you're not familiar, and it's the only thing you want to change at this point.

Validate the difference in days between the dates in a table

Greetings,

I have a tabular form and date on each line. When the user saves the form, I want to sort the rows by chronological order of these dates, then go get the first and last date, calculate the difference between them and validate it.

Does anyone know how to do?

From now on, I came up with this:

1. a PL/SQL Page process "before the calculations and Validations' which creates a collection and inserts lines in my tabular form (p_c004 being the date field):

begin   
  if apex_collection.collection_exists('UPDATE_DATES') then
    apex_collection.delete_collection('UPDATE_DATES');
  end if;

  apex_collection.create_or_truncate_collection('UPDATE_DATES');

  for i in 1..apex_application.g_f04.count
  loop
      apex_collection.add_member(
          p_collection_name => 'UPDATE_DATES',
          p_c002            => htmldb_application.g_f02(i),
          p_c003            => htmldb_application.g_f03(i),
          p_c004            => htmldb_application.g_f04(i),
          p_c005            => htmldb_application.g_f05(i),
          p_c006            => htmldb_application.g_f06(i),
          p_c007            => htmldb_application.g_f07(i));
  end loop;
end;

and

2. a "PL/SQL Error: Validation

DECLARE
  l_count NUMBER;
BEGIN
  apex_collection.sort_members('UPDATE_DATES', 4);
  l_count := apex_collection.collection_member_count('UPDATE_DATES');

  SELECT
  to_date(c004(l_count),'DD/MM/YYYY') - to_date(c004(1),'DD/MM/YYYY') Difference 

  FROM 
  apex_collections 

  WHERE 
  collection_name = 'UPDATE_DATES'
  and to_date(c004(l_count),'DD/MM/YYYY') - to_date(c004(1),'DD/MM/YYYY') < 30;

EXCEPTION
  WHEN NO_DATA_FOUND THEN
    raise_application_error(-20101, 'Error');
END;

In my understanding, the validation must sort the collection in chronological order of the dates entered, calculate the difference in days between the nearest and farthest date and return it if it's less than 30 years (the difference in days allowed). If it's more than 30 years, the SELECT statement does not return anything and my block of exceptions raises a custom error that will trigger the validation "process of refusal."

But when I try this, it tells me c004 does not exist and if I drop the parentheses, it works, but of course, it does not give the desired result.

Any ideas?

Best regards
Mathieu

Assuming that your domain is c004 then I don't see the need for the sorting of the collection.

You can write a simple SQL select that sent you the desired result.

Maybe something like this not tested

SELECT
  max(to_date(c004,'DD/MM/YYYY')) - min(to_date(c004,'DD/MM/YYYY') ) Difference
  FROM apex_collections
  WHERE collection_name = 'UPDATE_DATES';

The test if the result is > 30 days. If that's what you want to know.

find the days from the date of...
Hi all

I have a date saying (06-mar-2009), then how do you know what day is the same day as today (Friday)... and I need to create a table based on another table and must include all dates it's Saturday...

If someone can help me...

Thank you
Pankaj
If you are looking for the week then->
```
CREATE TABLE test
AS
  SELECT *
  FROM emp
  where to_char(hiredate,'DY') NOT IN ('SAT','SUN');
```
Another thing,
```
CREATE TABLE test
AS
  SELECT *
  FROM emp
  where to_char(hiredate,'DY') IN ('SAT','SUN');
```
Alternatively,.

Please post your desired output of your sample data.

Kind regards.

LOULOU.

The smart Albums based on the date range cause app Crash Photos

While I'm setting up a new Smart Album based on day of photos between 12/01/2015 and 31/12/2015 the Photos app closes with a crash. Cannot set the second date (the end date for this album). However, I can easily create a new Smart Album for next month (01/01/2016 and 01/31/2016). I create smart Albums, because the new Photos app does not like the old iPhoto does with my Photos from the photo gallery.

How can I solve this? I don't have an album of December...? !

You are in an area where the date format is different from the United States? Earlier this year, we have seen small business issues have reported that rules for smart albums date range do not work with the primary language set to French or German.

Try to change the primary system language to English with an English date format. Photos could be trying to read the 12/31/2015 as the 12th day of the month 31.

Or use a different date based on 'before' rule and after.

Get the date range min/max for consecutive events.

Hi all...
I am fairly new to the programming of the DB and is working on some examples I picked up a few places. The database version is 10g R2.
I would like to configure the data here and I can explain my requirement.
```
create table table_1
(product_id varchar2(25),
region_id  number,
event_id number
event_date date,
event_status number(1))
/
```
Now the data because it is->
```
insert into table_1 values ('Prod-1',10, null, to_date('01-feb-2014','dd-mon-yyyy'),null)
/
insert into table_1 values('Prod-1',10, 1001, to_date('10-mar-2014','dd-mon-yyyy'), 1)
/
insert into table_1 values('Prod-1',10, 1001, to_date('20-mar-2014','dd-mon-yyyy'), 3)
/
insert into table_1 values('Prod-1',10,1002, to_date('01-apr-2014','dd-mon-yyyy'), 1)
/
insert into table_1 values('Prod-1',10, 1002, to_date('10-apr-2014','dd-mon-yyyy'), 3)
/
commit
/
```
If the table now contains the following data
```
select * from table_1; 
```
PRODUCT_ID REGION_ID EVENT ID EVENT_DAT EVENT_STATUS
------------------------- ---------- -------- --------- ------------
Prod-1 10 1 February 14
Prod-1 10 1001 10 March 14 1
Prod-1 10 1001 20 March 14 3
Prod-1 10 1002 1 April 14 1
Prod-1 10 1002 April 10, 14 3
Now, the condition is as follows:
Above is the dates start and end for the tests on a product in a given region. The event_status column indicates the dates of beginning and end. Event_status = 1, for the date of beginning and the event_status = 3 of the end date.
A new event is now coming from March 21 and ending on March 31.
The power required is a product identifier / region; If there are events that are ending and then count the days, for example, 1001 to end on March 20, but now the new event begins on 21 March... and the new event ends on 31 March and event 1002 begins 01 - Apr... and so on.
The output required for this is as follows:
PRODUCT_ID REGION_ID EVENT_MIN_DATE EVENT_MAX_DATE
------------------------- ---------- -------------- --------------
Prod-1 10 10 14 March 10 April 14
The output should give a product identifier / region, when events are immediately after the other, out the min date of beginning and end of max for all these manifestations of "back to back".
Now I wrote the code for this, but it goes into a purely 'loop' for application in PLSQL... But my head tells me that if the results are correct. the PLSQL implementation is not the most efficient and effective way.
Can someone help me to form the query? I tried to use functions analytical min/max but it gives me the start and end dates back even if my events are not "back to back" or previous/succeed each other... so my query result is not quite correct.
Am reading on the TYPE clause but would be grateful if someone could help me with this query... or any other form better to implement this event so PLSQL can be used. The database version is 10g R2.
Thank you
K
PS - The number of such events back to back is limited to 4 and the events could be created in any order. But if someone could help me with the scenario above; am sure I could make a request addressed to any change in the order. :-)

No this isn't a recursive with clause, perhaps the UNION ALL you got confused. She will work with 10g.

Since there are 2 tables that you said, the block all_data brings together only the lines of the two tables. table_1 start_date and end_date are built from the event_status (where the max in group by).

How to pass the date range as in URL filter go
Hello

I am trying to build a Url go that has two filters, date range & text. I built the url below, but he continues to throw an error. The url is not from the date max and the app starts following error:

Error: Status: HY000. Code: 10058. [NQODBC] [SQL_STATE: HY000] [nQSError: 10058] A general error occurred. [nQSError: 46048] Month DateTime value 0 0000-00-00 is off limits. (HY000)

Go to Url: https:companyUrl? GB & Options = rfd & Path = / shared/CompanyID/link & P0 = 2 & P1 = eq & P2=CustomObject4.%22Indexed%20Pick%201%22 & P3 = Leasing & bet = P4 & P5 = ""-CustomObject4 Custom Attributes '. " ZDate_26 & P6 = 2 + Date % 20'2014-08-01'+ day % 20'2014-12-31'

Please suggest.

Thank you
Kiran.
It seems that you convert the data type of char to date in the URL, I don't think that this is possible.
Your code is like
& P6 = 2 + Date % 20'2014-08-01'+ day % 20'2014-12-31'

It suppose to be & P6 = 2 + 2014-08-01 + 2014-12-31

I suggest doing the formatting for this filed using column properties and try.

Hope this help, pls mark if yes ;)

Registration form of timesheet that auto-remplit the date ranges?

I currently have a need to add a "picker of the week' drop-down menu above my table & ColdFusion form as:
-When the week is selected in the dropdown menu, (how to generate these values in list dropdown weeks?)
-the correct dates are added to the date in the form fields... (how to fill the text boxes)
-Once the user chooses the week, update Sun - Sat dates, so he spends his time for each day...
-Choose the week-> Nov 3 thru Nov 9 <--(menu déroulant)
Sun---Mon---Tue---Wed---Thu---Fri---Sat (static labels)
---------------------------------------
11/03/11 04 11/05 11/06 11/07 11/08 11/09 (text boxes to dynamic dates)
0 8 8 8 8 8 (text boxes to the entrance of the hours)
Here is an example image of what I'm trying to reproduce roughly:
------------------------------------------------------------------------------
Note: This message of the UDF by Ben Nadel looks promising: ldFusion.htm http://www.bennadel.com/blog/719-Ask-Ben-Getting-The-Date-Based-On-The-Year-And-Week-In-Co

OK, here's my current page until now:

-With the help of this calendar weekly jq: http://jsfiddle.net/manishma/AVZJh/light/ I am able to select the week and have it update of my 'start the end thru' dates of text boxes.

- But how to upgrade the JavaScript (code below) to "fill" the week column headers (highlighted in yellow) also with mm/dd?

-Finally, I don't know how to make the INSERT SQL through three rows of data (highlighted in yellow)?

Here are my updated code to fill in the tags with the dates:
------------------------------------------------------------------------

And then I used in my HTML page:

-------------------------------------------

Type Mon Tue Wed Thu Fri Sat Sun Totals Description

Post edited by: jlig

Recover data to leave the date range Table
Hi all

We leave detail table for each employee contains information of beach to leave as follows.
EmpID, leaveFromDt, leaveToDt

We must identify no.. sheets for each employee from the date of the day & current date + group 2 weeks per each week.

If data should look like,

Name of the EMP of leaves
Week 1 semaine2
0 5 emp1
3 2 EMP2

How can this be achieved?

Here are the possible scenarios assuming
Date of the day = 10 may 2012
Current date plus 2 weeks is 24 may 2012

(1) absent from = 20 may 2012
Missing = may 25, 2012

(2) absent from = May 16, 2012
Missing = may 20, 2012

(3) = 6 may 2012 absent
Absent to = 30 may 2012

(4) missing = may 8, 2012
Absent in = 12 may 2012
Hello

The preliminary motion should be changed to the definitions of the new week.

The main request must add the number of days, rather than counting sheets.
To include employees who did not leave during these 2 weeks, you should do an outer join:
```
WITH     got_weeks     AS
(
     SELECT     1 AS week_num, TRUNC (SYSDATE) AS from_dt, TRUNC (SYSDATE) + 6 AS to_dt          FROM dual     UNION ALL
     SELECT     2,               TRUNC (SYSDATE) + 7,        TRUNC (SYSDATE) + 13             FROM dual
)
SELECT       e.emp_id
,      SUM ( CASE
                WHEN w.week_num = 1
                    THEN 1 + LEAST    (w.to_dt,   e.leave_to_dt)
                    - GREATEST (w.from_dt, e.leave_from_dt)
             ELSE 0
            END
          )          AS &week_1
,      SUM ( CASE
                WHEN w.week_num = 2
                    THEN 1 + LEAST    (w.to_dt,   e.leave_to_dt)
                    - GREATEST (w.from_dt, e.leave_from_dt)
             ELSE 0
            END
          )          AS &week_1
FROM              empleavedtls        e
LEFT OUTER JOIN       got_weeks        w  ON   w.from_dt     <= e.leave_to_dt
                       AND  w.to_dt     >= e.leave_from_dt
GROUP BY  e.emp_id
ORDER BY  e.emp_id
;
```
Instead to make 2 essentially the same CASE expressions, with FEWER and more calculations in each of them, you could do that once, in a subquery, and then, since you have Oracle 11, you can use SELECT... PIVOT function to get the totals in two columns. This would make it easier to add additional weeks. This is another good exercise.

UNPIVOT day after day in the data range

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