Displaying lines in columns

Similar Questions

• How to view the line of columns without using the pivot keyword

  Hello
  could someone help me how to display lines in columns without using the keyword pivot and actuall is my scenario, iam having two tables with names and examples of data is shown below
  
  MIDDLE MINAME TASKID TASKNAME IDENTIFICATION PROJECT
  
  1 PROJ1 1 AA 100 PR1_TASK1
  1 PROJ1 3 CC PR1_TASK3 102
  1 PROJ1 DD 4 103 PR1_TASK4
  1 PROJ1 EE 5 104 PR1_TASK5
  1 PROJ1 6 105 FF PR1_TASK6
  2 PROJ2 EE 5 114 PR2_TASK1
  2 PROJ2 6 115 FF PR2_TASK2
  2 PROJ2 GG 7 116 PR2_TASK3
  2 PROJ2 HH 8 117 PR2_TASK4
  2 PROJ2 9 118 PR2_TASK5 JJ
  2 PROJ2 KK 10 119 PR2_TASK6
  2 PROJ2 1 AA PR2_TASK7 120
  
  
  The output should show the project and County of tasks at a given stage as shown below
  
  project AA BB CC DD EE FF GG HH JJ KK
  1 2 0 1 5 3 2 0 2 1 0
  2 1 2 0 2 1 0 2 4 3 1
  
  
  Thanks in advance,
  VVR

  CREATE TABLE pivot_test (
  ID           NUMBER,
  PROJECT      VARCHAR2(10),
  MID          NUMBER,
  MINAME       VARCHAR2(5),
  TASKID       NUMBER,
  TASKNAME     VARCHAR2(10)
  );
  
  INSERT INTO pivot_test VALUES (1, 'PROJ1', 1,  'AA', 100, 'PR1_TASK1');
  INSERT INTO pivot_test VALUES (1, 'PROJ1', 3,  'CC', 102, 'PR1_TASK3');
  INSERT INTO pivot_test VALUES (1, 'PROJ1', 4,  'DD', 103, 'PR1_TASK4');
  INSERT INTO pivot_test VALUES (1, 'PROJ1', 5,  'EE', 104, 'PR1_TASK5');
  INSERT INTO pivot_test VALUES (1, 'PROJ1', 6,  'FF', 105, 'PR1_TASK6');
  INSERT INTO pivot_test VALUES (2, 'PROJ2', 5,  'EE', 114, 'PR2_TASK1');
  INSERT INTO pivot_test VALUES (2, 'PROJ2', 6,  'FF', 115, 'PR2_TASK2');
  INSERT INTO pivot_test VALUES (2, 'PROJ2', 7,  'GG', 116, 'PR2_TASK3');
  INSERT INTO pivot_test VALUES (2, 'PROJ2', 8,  'HH', 117, 'PR2_TASK4');
  INSERT INTO pivot_test VALUES (2, 'PROJ2', 9,  'JJ', 118, 'PR2_TASK5');
  INSERT INTO pivot_test VALUES (2, 'PROJ2', 10, 'KK', 119, 'PR2_TASK6');
  INSERT INTO pivot_test VALUES (2, 'PROJ2', 1,  'AA', 120, 'PR2_TASK7');
  
  SELECT ID as PROJECT,
         SUM(DECODE(miname, 'AA', 1, 0)) AS AA,
         SUM(DECODE(miname, 'BB', 1, 0)) AS BB,
         SUM(DECODE(miname, 'CC', 1, 0)) AS CC,
         SUM(DECODE(miname, 'DD', 1, 0)) AS DD,
         SUM(DECODE(miname, 'EE', 1, 0)) AS EE,
         SUM(DECODE(miname, 'FF', 1, 0)) AS FF,
         SUM(DECODE(miname, 'GG', 1, 0)) AS GG,
         SUM(DECODE(miname, 'HH', 1, 0)) AS HH,
         SUM(DECODE(miname, 'JJ', 1, 0)) AS JJ,
         SUM(DECODE(miname, 'KK', 1, 0)) AS KK
  FROM   pivot_test
  GROUP BY ID;
  
  PROJECT AA BB CC DD EE FF GG HH JJ KK
  ------- -- -- -- -- -- -- -- -- -- --
        1  1  0  1  1  1  1  0  0  0  0
        2  1  0  0  0  1  1  1  1  1  1 
  

• P7-1298cb: Multi-color flickering lines in columns displayed on the screen after upgrade Windows 10.

  I upgraded Windows Windows 8.1 1O.  I've updated the drivers.  The monitor multicolored poster of fine lines in columns.  The lines of twinkle randomly.  The monitor is a diagonal LED of 2711 x 27 inch HP (XP600A) screen.  It is not that there is a specific monitor for Windows 10 driver.  Any suggestions on how to fix this?

  HI @TLL2016,

  Thanks for getting back to me.

  There is no update BIOS, but there is more recent graphics driver.

  Here is a link the download AMD UMA Graphics Driver.

  Just to check the monitor, here is a document for display quality problems.

  Please keep me informed of the progress of things.

  If you need help, let me know and I will gladly make all that I can to help you.

  Please let me know if that solves the problem by marking this post as "accept as a Solution.
  To simply say thank you, click the Thumbs up below!

  Thank you.

• Display lines of dates in the column

  Hello

  I use 12 c DB.

  Database Oracle 12 c Enterprise Edition Release 12.1.0.1.0 - 64 bit Production

  PL/SQL Release 12.1.0.1.0 - Production

  "CORE 12.1.0.1.0 Production."

  AMT for 64-bit Windows: Version 12.1.0.1.0 - Production

  NLSRTL Version 12.1.0.1.0 - Production

  I wrote under request, I want to display these lines in columns... How can I do?

  Select to_date (1 January 2013 "") + level 1 double dte

  connect by to_date (January 1, 2013 ',' MON-DD-YYYY') + level 1 < = last_day (to_date (January 31, 2013 ',' MON-DD-YYYY ""));

  Thank you.

  As already suggested by
  

  
  

  Select *.

  from (select level lvl, dates "2013-01-01' + level - 1 dte)

  of the double

  connect by level<= last_day(date="" '2013-01-01')="" -="" date="" '2013-01-01'="" +="">

  )

  Pivot (max lvl in (d1, d2, d3, d4, d5, d6, d7, d8, d9, d10, 10 9 8 7 6 5 4 3 2 1 (dte)

  11 as d11, d12, d13, d14, d15, d16, d17, d18, d19, d20, 20 19 18 17 16 15 14 13 12

  21 as d21, d22, d23, d24 24 23, 25 as d25, 26 as d26, d27 27, 28 d28, d29 29, 30 as d30, 22

  31 as d31

  )

  )

  Concerning

  Etbin

• How to write express line and column of the tables headers to a file

  HI guys, I work with that express table and display data using the express table. What I want to do, is that when I press save button results data in the specific table must be written to a text file. I am able to write the text file, but only the data is written. Y at - there a possiblity that I can also write lines and column headers and the data in the text file. Kindly guide me in this regard as soon as possible. I enclose the image also. Please watch this and guide me.

  Cordially Ehtisham Safdar.

  Hello

  Sorry for the late reply. Here is the VI, I hope it works for you. Rather than each element of the index and the addition of the row header, take advantage of the available icons and play with the nodes of property for a good solution.

  Concerning

  Gaze

• Display a time column value

  Hey,.
  I'm trying to display a column value only once for a folder, not a static value. Changes in value and it can be a lot of values. I don't think that grouping will work since the Date value is dynamic. I use Oracle for Toad 10.5. There are 4 files with data from this trial.
  

  select Date, Person, Language, Country
  from TableA

  TableA
  Date            Person  Language   Country
  01/25/2013       James   English
  12/20/2012       James   English
                                       US
                                       AF

  Want to display only

  Date            Person  Language   Country
  01/25/2013       James   English
  12/20/2012  
                                       US
                                       AF

  Thanks for reading this thread!
  
  Published by: Nikki on January 7, 2013 13:08

  Hello

  You can use the ROW_NUMBER analytic function to see if a given line is the 1st row in a group and display only the columns of the person and the language when it is:

  WITH     got_r_num     AS
  (
       SELECT       dt          -- DATE is not a good column name
       ,       person, language, country
       ,       ROW_NUMBER () OVER ( PARTITION BY  person
                                    ,          language
                             ORDER BY          dt
                           )  AS r_num
       FROM      table_x
  )
  SELECT       dt
  ,       CASE WHEN r_num = 1 THEN person   END)     AS person
  ,       CASE WHEN r_num = 1 THEN language END)     AS language
  ,       country
  FROM       got_r_num
  ORDER BY  person, language, dt     -- If wanted
  ;
  

  Your front end, perhaps as a way of hiding these values when you want to. PAUSE function in SQL * more to it; I don't know if toad has nothing comparable.

  I hope that answers your question.
  If not, post a small example data (CREATE TABLE and only relevant columns, INSERT statements) where the query above generates erroneous results, and also after the good results you want from this data.
  Explain, using specific examples, how you get these results from these data.
  Always say what version of Oracle you are using (for example, 11.2.0.2.0).
  See the FAQ forum {message identifier: = 9360002}

• Help: java.sql.SQLException: ORA-06550: line 1, column 7:, PLS-00201:

  Who can give me a hand to settle the question below? I use the db 11G for two or three days. This works. But now it displays information below, it blocks my server needs to be in place. Can anyone help to take a look? And explain to me what is meaning with below question?
  
  Thank you
  
  
  java.sql.SQLException: ORA-06550: line 1, column 7:
  PLS-00201: identifier ' INVALIDHTOMEH. KEEP ' should be declared
  
  oracle.jdbc.driver.DatabaseError.throwSqlException(DatabaseError.java:138)
  11/08/05 02:18:17-oracle.jdbc.driver.T4CTTIoer.processError(T4CTTIoer.java:316)
  11/08/05 02:18:17-oracle.jdbc.driver.T4CTTIoer.processError(T4CTTIoer.java:282)
  11/08/05 02:18:17-oracle.jdbc.driver.T4C8Oall.receive(T4C8Oall.java:639)
  11/08/05 02:18:17-oracle.jdbc.driver.T4CCallableStatement.doOall8(T4CCallableStatement.java:184)
  11/08/05 02:18:17-oracle.jdbc.driver.T4CCallableStatement.execute_for_rows(T4CCallableStatement.java:873)
  11/08/05 02:18:17-oracle.jdbc.driver.OracleStatement.doExecuteWithTimeout(OracleStatement.java:1161)
  11/08/05 02:18:17-oracle.jdbc.driver.OraclePreparedStatement.executeInternal(OraclePreparedStatement.java:3001)
  11/08/05 02:18:17-oracle.jdbc.driver.OraclePreparedStatement.execute(OraclePreparedStatement.java:3093)
  11/08/05 02:18:17-oracle.jdbc.driver.OracleCallableStatement.execute(OracleCallableStatement.java:4286)
  11/08/05 02:18:17-com.agile.pc.cmserver.util.OracleIDGenerator.pinSequence(OracleIDGenerator.java:245)
  11/08/05-02:18:17-com.agile.pc.cmserver.util.OracleIDGenerator. < init > (OracleIDGenerator.java:62)
  11/08/05 02:18:17-com.agile.pc.cmserver.util.CMUtilReflection.getOracleIDGenerator(CMUtilReflection.java:79)
  11/08/05 02:18:17-com.agile.util.dao.IDGenerator.getNewInstance(IDGenerator.java:78)
  11/08/05 02:18:17-com.agile.util.dao.IDGenerator.getInstance(IDGenerator.java:66)
  11/08/05 02:18:17-com.agile.util.dao.IDGenerator.getNextID(IDGenerator.java:91)
  11/08/05-02:18:17-com.agile.util.AppServerId. < clinit > (AppServerId.java:14)
  11/08/05 02:18:17-com.agile.startup.PCMStartupImpl.start(PCMStartupImpl.java:115)
  11/08/05 02:18:17-com.agile.ui.pcm.InitServlet.init(InitServlet.java:63)
  11/08/05 02:18:17-com.evermind.server.http.HttpApplication.loadServlet(HttpApplication.java:2379)
  11/08/05 02:18:17-com.evermind.server.http.HttpApplication.findServlet(HttpApplication.java:4830)
  11/08/05 02:18:17-com.evermind.server.http.HttpApplication.findServlet(HttpApplication.java:4754)
  11/08/05 02:18:17-com.evermind.server.http.HttpApplication.initPreloadServlets(HttpApplication.java:4942)
  11/08/05 02:18:17-com.evermind.server.http.HttpApplication.initDynamic(HttpApplication.java:1144)
  11/08/05-02:18:17-com.evermind.server.http.HttpApplication. < init > (HttpApplication.java:741)
  11/08/05 02:18:17-com.evermind.server.ApplicationStateRunning.getHttpApplication(ApplicationStateRunning.java:431)
  11/08/05 02:18:17-com.evermind.server.Application.getHttpApplication(Application.java:586)
  11/08/05 02:18:17-com.evermind.server.http.HttpSite$ HttpApplicationRunTimeReference.createHttpApplicationFromReference (HttpSite.java:1987)
  11/08/05 02:18:17-com.evermind.server.http.HttpSite$ HttpApplicationRunTimeReference. < init > (HttpSite.java:1906)
  11/08/05 02:18:17-com.evermind.server.http.HttpSite.initApplications(HttpSite.java:643)
  11/08/05 02:18:17-com.evermind.server.http.HttpSite.setConfig(HttpSite.java:290)
  11/08/05 02:18:17-com.evermind.server.http.HttpServer.setSites(HttpServer.java:270)
  11/08/05 02:18:17-com.evermind.server.http.HttpServer.setConfig(HttpServer.java:177)
  11/08/05 02:18:17-com.evermind.server.ApplicationServer.initializeHttp(ApplicationServer.java:2493)
  11/08/05 02:18:17-com.evermind.server.ApplicationServer.setConfig(ApplicationServer.java:1042)
  11/08/05 02:18:17-com.evermind.server.ApplicationServerLauncher.run(ApplicationServerLauncher.java:131)
  
  Published by: user774630 on November 4, 2008 18:57

  # com.agile.pc.cmserver.util.OracleIDGenerator.pinSequence(OracleIDGenerator.java:245)

  This method tries to pin a sequence in the Shared Pool so that it is not recharged. Reloading can cause sequence numbers to be ignored, if I remember correctly.
  Pinning is done using packed the INVALIDHTOMEH procedure. KEEP. The error is reported because either the package INVALIDHTOMEH is not created in the database (the $ORACLE_HOME/rdbms/admin/dbmspool.sql script creates) or the user who connects to the database have not run privilege for the package.

  Note that the package has access to the shared swimming pool. Execute privilege to grant only trusted users.

  -Sergiusz

• Matrix - vector lines and columns

  M1 (3,2) gives the element of line 3, column 2

  M1 (2) gives the second row of a matrix (as a vector line)

  Is there a way to return a column (other than transpose, store again and using the method above on the transposed matrix)?

  Tim Wessman wrote:
  

  Assuming that first here...

  Col(M1,1)

  Row(M1,1)

  @ Tim,.

  As Mmmm - created a post on the 39gii and commented on a post on the 39gii, this one is perhaps more likely to be on the 39gii?

  I think that your presumption re - expresses my presumption that the 39gii becomes brother forgot the premium?

  @ Mmmm.

  Try M1 (-c), where C is desired column number. For example M1(-2) for column 2.

• How would add labels to lines and columns of a spreadsheet?

  I got some data of an oscilloscope, which has about 500 lines I want to the label at the time of measurement (1ms, 2ms, 3ms...) and about 10 columns I want to mark it with a corresponding wavelength (800 nm, 805nm, 810nm...). Any idea or links to examples would be appreciated.

  Gregory

  Before you write data in your spreadsheet file, write a line of column names.  Just make a table 1 d of strings with column names.  Write the 1 d array to the worksheet.  If you want labels on each line, you will need to convert your data into strings.  So, you will have a table 2D-string data.  Create a table 1 d of your line labels.  Insert in the table to insert your picture label in the data table, making sure to wire a 0 in the index of the column, not the index of the row.  This will put your labels in the first column.  Then write the 2D table in the spreadsheet file.

• I still have not found "help" to tell me how to remove all the lines and columns beyond those needed for my spreadsheet.

  I used several worksheets.  More allows me to specify the rows/columns and then delete them.  This is to remove all the lines/columns beyond those set up and formatted for my spreadsheet.   I tried many ways to remove all additional lines/columns, but without success.  I even took the time to scroll down/on to highlight all the unnecessary lines and columns, but they do not remove it.
  Any suggestions?  I used spreadsheets most allow me to specify the number of rows/columns for my worksheet

  You can ask your question in the office | Excel Forum because it is not really a problem of Windows XP performance and maintenance.

  Office | Excel

  http://answers.Microsoft.com/en-us/Office/Forum/Excel

  Also, providing specific information may help to get a faster response or better, such as the version of Office or Excel? version of Windows XP? Home, Pro, 32-bit or 64-bit.

  I hope this helps.

• How to display the comments column in Windows Media Player 12?

  WMP12 - how to display the comments column?

  I want to see the Cooments ColonneB in my WMP ads, but it is not giving me the option.

  Hello

  1. What do you mean exactly by the column comments?
  2. are you referring to in Windows Media Player?

  If you want to change the information contained in the Windows Media Player, you can follow the steps in this article.

  http://Windows.Microsoft.com/en-us/Windows7/add-or-edit-media-information-in-Windows-Media-Player

• Sort sort the columns number of lines n columns in the RTF PivotTable but hide them.

  Hello

  I'm trying to sort on the columns number of sort for lines n columns in the PivotTable but hide them. Any help appreciated.

  Attached model RTF, XML and output required. Thank you

  Please check your email that I have forwarded to update the model.

  by default, it performs a sort on the column, we used to pivot rows and columns. If we need custom sort, we must specify that column in the logic that was present in the C form field.

  by default, you are as below

  Custom sort

  {INDUSTRY_sort, o = a, t = n} « ; » MONTHS {Month_sort, o = a, t = n} '; SALES '; "' sum '? >

• Write a SQL query with lines in columns

  All the

  I need help in writing a SQL query with lines in columns, let give u an example...

  drop table activity;

  CREATE TABLE 'ACTIVITY '.

  (

  "PROJECT_WID" NUMBER (22.0) NOT NULL,

  VARCHAR2 (150 CHAR) "PROJECT_NO."

  VARCHAR2 (800 CHAR) 'NAME '.

  );

  Insert in the ACTIVITY (PROJECT_WID, PROJECT_NO, NAME) values (1683691, '10007', 12-121');

  Insert in the ACTIVITY (PROJECT_WID, PROJECT_NO, NAME) values (1684994, '10008', 12-122');

  Insert in the ACTIVITY (PROJECT_WID, PROJECT_NO, NAME) values (1686296, '10009', 12-123');

  Insert in the ACTIVITY (PROJECT_WID, PROJECT_NO, NAME) values (2225222, '9040', 12-124');

  drop table lonet;

  CREATE TABLE 'LONET.

  (

  VARCHAR2 (150 CHAR) "NAME."

  NUMBER OF THE "ROOT."

  VARCHAR2 (150 CHAR) "ENTRYVALUE".

  );

  INSERT INTO LONET (NAME, ROOT, ENTRYVALUE) VALUES ("GAC", 1683691, "LDE");

  INSERT INTO LONET (NAME, ROOT, ENTRYVALUE) VALUES ('NAM', 1683691, 'LME');

  INSERT INTO LONET (NAME, ROOT, ENTRYVALUE) VALUES ('BAG', 1683691, 'ICE');

  INSERT INTO LONET (NAME, ROOT, ENTRYVALUE) VALUES ('PAP', 1683691, 'IKE');

  INSERT INTO LONET (NAME, ROOT, ENTRYVALUE) VALUES ('NAM', 1686291, "QTY");

  INSERT INTO LONET (NAME, ROOT, ENTRYVALUE) VALUES ('PAP', 1686291, 'MAX');

  INSERT INTO LONET (NAME, ROOT, ENTRYVALUE) VALUES ("GAC", 1684994, "MTE");

  INSERT INTO LONET (NAME, ROOT, ENTRYVALUE) VALUES ('PAP', 1684994, 'MAC');

  INSERT INTO LONET (NAME, ROOT, ENTRYVALUE) VALUES ('FMT', 1684994, 'NICE');

  INSERT INTO LONET (NAME, ROOT, ENTRYVALUE) VALUES ('FMR', 1684994, 'RAY');

  INSERT INTO LONET (NAME, ROOT, ENTRYVALUE) VALUES ('BAG', 1686296, "CAQ");

  INSERT INTO LONET (NAME, ROOT, ENTRYVALUE) VALUES ("PAP", 1686296, "QAQ");

  INSERT INTO LONET (NAME, ROOT, ENTRYVALUE) VALUES ("VANESSA", 1686296, "THEW");

  INSERT INTO LONET (NAME, ROOT, ENTRYVALUE) VALUES ("ANDR", 1686296, "REYL");

  commit;

  Link: activity.project_wid = lonet.root

  look like output

  Project_wid	Project_no	NAME	GAC	NAM	BAG	RAC
  1683691	10007	12-121	LDE	LME	LCE	LKE
  1684994	10008	12-122	MTE	null	null	MAC
  1686296	10009	12-123	null	null	CAQ	QAQ
  2225222	9040	12-124	null	null	null	null

  two problems, in that I am running

  1. I dono how simply we can convert rows to columns

  2. for root = 1683691, there are double NAM and RAC in lonet table... ideally these data should not be there, but since its here, we can take a MAX so that it returns a value

  3. There are undesirables who should be ignored

  Once again my thought process is that we join the activity and 4 alias table lonet.

  ask for your help in this

  Thank you

  Hello

  This is called pivoting.

  Here's a way to do it:

  WITH relevant_data AS

  (

  SELECT a.project_wid, a.project_no, b.SID

  , l.name AS lonet_name, l.entryvalue

  Activity one

  LEFT OUTER JOIN lonet l.root = a.project_wid l

  )

  SELECT *.

  OF relevant_data

  PIVOT (MAX (entryvalue)

  FOR lonet_name IN ("GAC" IN the gac

  "NAM" AS nam

  'BAG' IN the bag

  "RAC" AS cars

  )

  )

  ORDER BY project_wid

  ;

  Output:

  PROJECT_WID PROJECT_NO GAC NAM BAG RAC NAME

  ----------- ---------- ---------- ---------- ---------- ---------- ----------

  1683691 12 - 10007 121 LDE LME LCE LKE

  1684994 MAC MTE 10008 12-122

  1686296 12 - 10009 123 QAC QAQ

  2225222 9040 12 - 124

  To learn more about swivel, see the FAQ in the Forum: Re: 4. How can I convert rows to columns?

  Thanks for posting the CREATE TABLE and INSERT statements; It's very useful!

• error handle output line 45 / column 9 / errors/warnings - tag must be associated, missing: [&lt; /li &gt; &lt; /li &gt; &lt; /li &gt; &lt; /li &gt;]

  I get this error using DW cc 2015 "error manage output line 45 / column 9 / errors/warnings - tag must be associated, missing: [/li > < /li > < /li > < /li > <]" How can I fix?

  Add one or more closing tags.

  Without seeing the code, it is impossible to tell where exactly, but a list item must be closed...

  • point 1
  • point 2
  • point 3
  • point 4

• How to display line breaks in vCO-WebView?

  Hello

  I just want to know how I can make it possible to display line breaks in a workflow with vCO-WebOperator-WebView presentation in the new vCO-Version 4.2.1?

  In the old version, it was easy, I just use the HTML < br > tag, but in the new version, it will be write it in text form, as you can see here:

  

  When I use the vCO Client it will work when \n is used as you can see below, but not in the WebWiew (see above):

  

  Can you please give me a hint.

  Best regards

  Rainer

  Set this property: com.vmware.o11n.webview.htmlescaping.disabled = true

  As described in the vCO 4.2.1 release notes.

  Christophe.