Find the missing values in the third from the two other tables table

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  Hello
  
  I want to compare two tables each of RECON_APPEND_01 table contains 375 million and RECON_VS_24082011 450 million records.
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  )

  Explain the Plan:
  

  --------------------------------------------------------------------------------------------------------------------------
  | Id  | Operation                    | Name            | Rows  | Bytes |TempSpc| Cost (%CPU)|    TQ  |IN-OUT| PQ Distrib |
  --------------------------------------------------------------------------------------------------------------------------
  |   0 | CREATE TABLE STATEMENT       |                 |   378M|  6451M|       |  1398K (43)|        |      |            |
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  |   3 |    LOAD AS SELECT            | RECON_APPEND_03 |       |       |       |            |  Q1,02 | PCWP |            |
  |   4 |     MINUS                    |                 |       |       |       |            |  Q1,02 | PCWP |            |
  |   5 |      SORT UNIQUE             |                 |   378M|  4336M|  7255M|   775K  (4)|  Q1,02 | PCWP |            |
  |   6 |       PX RECEIVE             |                 |   378M|  4336M|       |   114K  (3)|  Q1,02 | PCWP |            |
  |   7 |        PX SEND HASH          | :TQ10000        |   378M|  4336M|       |   114K  (3)|  Q1,00 | P->P | HASH       |
  |   8 |         PX BLOCK ITERATOR    |                 |   378M|  4336M|       |   114K  (3)|  Q1,00 | PCWC |            |
  |   9 |          TABLE ACCESS FULL   | RECON_APPEND_01 |   378M|  4336M|       |   114K  (3)|  Q1,00 | PCWP |            |
  |  10 |      SORT UNIQUE             |                 |   184M|  2115M|  3539M|   538K  (3)|  Q1,02 | PCWP |            |
  |  11 |       PX RECEIVE             |                 |   184M|  2115M|       |   216K  (1)|  Q1,02 | PCWP |            |
  |  12 |        PX SEND HASH          | :TQ10001        |   184M|  2115M|       |   216K  (1)|  Q1,01 | P->P | HASH       |
  |  13 |         PX BLOCK ITERATOR    |                 |   184M|  2115M|       |   216K  (1)|  Q1,01 | PCWC |            |
  |  14 |          INDEX FAST FULL SCAN| SYS_C002617302  |   184M|  2115M|       |   216K  (1)|  Q1,01 | PCWP |            |
  --------------------------------------------------------------------------------------------------------------------------
   

  Another alternate query:
  

  CREATE TABLE recon_append_02
  PARALLEL 3
  NOLOGGING
  AS
  SELECT   *
  FROM   RECON_APPEND_01 a
  WHERE   NOT EXISTS (SELECT  'X'
  FROM   RECON_VS_24082011 b
  WHERE   b.SERIAL_NUMBER = a.SERIAL_NUMBER)

  Explain the Plan:
  

  ------------------------------------------------------------------------------------------------------------
  | Id  | Operation              | Name            | Rows  | Bytes | Cost (%CPU)|    TQ  |IN-OUT| PQ Distrib |
  ------------------------------------------------------------------------------------------------------------
  |   0 | CREATE TABLE STATEMENT |                 |   378M|    26G|   450K (10)|        |      |            |
  |   1 |  PX COORDINATOR        |                 |       |       |            |        |      |            |
  |   2 |   PX SEND QC (RANDOM)  | :TQ10000        |   378M|    26G|   153K (28)|  Q1,00 | P->S | QC (RAND)  |
  |   3 |    LOAD AS SELECT      | RECON_APPEND_02 |       |       |            |  Q1,00 | PCWP |            |
  |   4 |     NESTED LOOPS ANTI  |                 |   378M|    26G|   153K (28)|  Q1,00 | PCWP |            |
  |   5 |      PX BLOCK ITERATOR |                 |       |       |            |  Q1,00 | PCWC |            |
  |   6 |       TABLE ACCESS FULL| RECON_APPEND_01 |   378M|    22G|   116K  (5)|  Q1,00 | PCWP |            |
  |   7 |      INDEX UNIQUE SCAN | SYS_C002617302  |     1 |    12 |     0   (0)|  Q1,00 | PCWP |            |
  ------------------------------------------------------------------------------------------------------------

  Based on the plan I've run the second query, but it's taking a lot of time around 4 hours and still running.
  Please suggest.
  
  With respect,
  Adeline Faure

  Look carefully at the request of Tubby. Your problem in your test is with b.val = null. You can't compare anything on a null using normal operators.

  SQL> select * from target_tab;
  
         VAL
  ----------
           1
           2
           3
           4
           5
           6
           7
           8
           9
          10
  
  SQL> select * from source_tab;
  
         VAL
  ----------
           6
           7
           8
           9
          10
  
  SQL> select a.*
    2  from target_tab a, source_tab b
    3  where a.val = b.val(+) and
    4        b.val is null;
  
         VAL
  ----------
           5
           1
           4
           2
           3
  

  John

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  I have 2 tables:
  
  with stud_courses as
  (
  Select studentid 111, 2, 2201 coursecategory courseid, 'A' GRADE of double
  Union
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  Union
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  Union
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  Union
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  Union
  Select 4 coursecategory, 2121 courseid double
  Union
  Select 4 coursecategory, 2122 courseid double
  Union
  Select 4 coursecategory, 2123 courseid double
  )
  
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  My end result would be something like:
  
  StudentID, courseid, coursecategory, grade
  111,2,2201, "A".
  111,2,2201, '
  111,2,2203, 'B '.
  111,2,2201, '
  111,4,2120, '
  111,4,2121, "A".
  111,4,2122, '
  111,4,2123, '
  222,3,1110, '
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  I know how to do it with a Union and not exists, but I was wondering if I could do it with an outer join.
  
  I would appreciate your help.
  
  Thank you

  Hello

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  WITH     all_students     AS
  (
       SELECT DISTINCT     studentid
       FROM          stud_courses
  )
  ,     got_category_cnt     AS
  (
       SELECT     all_s.studentid
       ,     c.coursecategory
       ,     c.courseid
       ,     NVL ( s.grade
                , 'M'
                )               AS grade
       ,     COUNT (s.grade) OVER ( PARTITION BY  all_s.studentid
                                   ,          c.coursecategory
                           )      AS category_cnt
       FROM           all_students         all_s
       CROSS JOIN      course_categories  c
       LEFT OUTER JOIN      stud_courses         s  ON    s.studentid     = all_s.studentid
                                           AND   s.courseid          = c.courseid
  )
  SELECT       studentid
  ,       coursecategory
  ,       courseid
  ,       grade
  FROM       got_category_cnt
  WHERE       category_cnt     > 0
  ORDER BY  studentid
  ,       coursecategory
  ,       courseid
  ,       grade
  ;
  

  The results I get are:

  `STUDENTID COURSECATEGORY   COURSEID G
  ---------- -------------- ---------- -
         111              2       2201 A
         111              2       2202 M
         111              2       2203 B
         111              2       2204 M
         111              4       2120 M
         111              4       2121 A
         111              4       2122 M
         111              4       2123 M
         222              3       1110 M
         222              3       1111 A
         222              3       1112 A
         222              3       1113 M
  

  These are a little different from what you have posted.

  user9207291 wrote:
  ...
  StudentID, courseid, coursecategory, grade
  111,2,2201, "A".
  111,2,2201, '
  111,2,2203, 'B '.
  111,2,2201, '
  111,4,2120, '
  111,4,2121, "A".
  111,4,2122, '
  111,4,2123, '
  222,3,1110, '
  222,3,1111, "A".
  222,3,1112, "A".
  222,3,1113, '

  Is it because there are errors in what you posted? Do you really want to have three lines of output for the same studentid (111) and courseid (2201)?

  Looks like there should be a slick way to do this with a partitioned outer join.
  A partitioned outer join matches each row of table A with the lines in table B, but, if there is no correspondence between a given A line and a line to a given partition of B, that the rank of A and the B partition is included in the game anyway. Here, we want the two partition tables.

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