How to find the difference between related areas

Similar Questions

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  How to find the difference between oracle database standard edition and standard edition one 64 bit
  
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  How to find the difference between oracle database standard edition and standard edition one 64 bit

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  Select * the option of $ v;

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  opatch lsinventory-details

• How to find the difference between two dates in time except Sunday

  Hi all
  
  I have a table, as shown below.

  SQL> select * from test;
  
  TR_ID                                              CREATE_TIME                                                                       CODE
  -------------------------------------------------- --------------------------------------------------------------------------- ----------
  S12341                                             05-JUN-12 12.20.52.403000 AM                                                      1003
  S12342                                             11-JUN-12 11.15.33.182000 AM                                                      1003
  S12342                                             07-JUN-12 12.00.36.573000 PM                                                      1002
  S12343                                             20-JUN-12 12.34.37.102000 AM                                                      1003
  S12343                                             15-JUN-12 11.34.27.141000 PM                                                      1002
  S12344                                             01-JUL-12 10.01.06.657000 PM                                                      1002
  S12344                                             06-JUL-12 12.01.04.188000 AM                                                      1003
  S12341                                             31-MAY-12 11.20.38.529000 PM                                                      1002

  I would like to know the difference between same tr_ids create_time, which should give out in hours except Sunday.
  
  For example:
  
  TR_ID: S12344
  1002_Create_time: July 1, 12 PM 10.01.06.657000 (i.e. Sunday)
  1003_Create_time: 12.01.04.188000 AM 6 July 12
  
  1002 create time is 22:00 Sunday.
  
  If the query must exclude only the hours of Sunday which is 10 p.m. to Monday 00 h which is 2 Hrs.
  
  I tried the sub query after doing a search on this forum but I am not getting the desired output.
  

  SELECT count(*) FROM (SELECT ROWNUM RNUM,tr_id,create_time CT_1002 FROM test c WHERE c.tr_id='S12344' and 
  ROWNUM <= (select (cast(a.create_time as date)-cast((select create_time from test b where a.tr_id=b.tr_id and code=1002) as date)) 
  from test a where a.code=1003 and a.tr_id=c.tr_id) + 1) d 
  WHERE to_char(cast((select create_time from test e where e.tr_id=d.tr_id and code=1002) as date) + RNUM - 1, 'DY') NOT IN('SUN');

  Need help to get the desired o/p

  Hello

  If I unederstand the problem correctly, that's what you want:

  WITH       got_extrema     AS
  (
       SELECT       tr_id
       ,       CAST (MIN (create_time) AS DATE)     AS start_date
       ,       CAST (MAX (create_time) AS DATE)     AS end_date
       FROM       test
       GROUP BY  tr_id
  )
  SELECT       tr_id
  ,       start_date, end_date          -- If wanted
  ,       24 * ( ( ( TRUNC (end_date,   'IW')          -- Count -1 day for every full week
                      - TRUNC (start_date, 'IW')
               )
             / -7
                )
              + LEAST ( end_date               -- If end_date is a Sunday
                          , TRUNC (end_date, 'IW') + 6     -- consider it 00:00:00 on Sunday
                   )
              - CASE
                        WHEN  start_date >= TRUNC (start_date, 'IW') + 6     -- If start_date is a Sunday
                 THEN  TRUNC (start_date, 'IW') + 6               -- consider it 00:00:00 Sunday
                 ELSE  start_date
                    END
              )     AS total_hours
  FROM      got_extrema
  ;
  

  I guess that you don't need to worry about fractions of a second. As you did in the code you have posted, I am to convert the TIMESTAMP to date values, because of DATE arithmetic and functions are so much better than what is available for timestamps.

  Basically, it's just to find the number of days between start_date and end_date and multiplying by 24, with these twists:
  (a) 1 day is deducted for each week between start_date and end_date
  (b) if End_date is a Sunday, none of the end_date himself hours are counted
  (c) If start_date is a Sunday, then all the start_date himself hours are counted. Why these hours should be counted? Because 1 day is already being deducted for the week which includes start_date, which contains only this Sunday.

  TRUNC (dt, 'IW') is the beginning of the ISO week containing dt; in other words, 00:00:00 the or before the dt last Monday. This is not the NLS parameters.

  Of course, I can't test without some sample data and the exact results you want from these data. You may need a little something more If start_date and end_date are both on the same Sunday.
  Whenever you have a problem, please post a small example of data (CREATE TABLE and only relevant columns, INSERT statements) of all of the tables involved.
  Also post the results you want from this data, as well as an explanation of how you get these results from these data, with specific examples.
  Always tell what version of Oracle you are using.
  See the FAQ forum {message identifier: = 9360002}

• How to find the difference between two dates in the presentation layer

  Hi gurus,
  
  Hello to everyone. Today, I came with the new requirement.
  
  
  I need to know the difference between a date and the current date in the formula column application presentation layer.by.
  
  
  
  Thank you and best regards,
  Prates

  Hi Navin,

  TIMESTAMPDIFF function first determines the timestamp component that corresponds to the specified interval setting. For example, SQL_TSI_DAY corresponds to the day component and SQL_TSI_MONTH corresponds to the component "month".

  If you want to display the difference between two dates in days using SQL_TSI_DAY, unlike butterflies SQL_TSI_MONTH and so on...

  hope you understand...

  Award points and to close the debate, if your question is answered.

  See you soon,.
  Aravind

• How to find the difference between the two timestamp columns

  Dear all,
  Please solve my problem,
  I have Table name of the folder that has the following columns,
  EmpID in the number column, timestamp dat
  who has the following values
  Expand | Select | Wrap | Line numbers
  EmpID dat
  ====== ====
  101 4/9/2012 09:48:54
  101 4/9/2012 09:36:28
  101 4/9/2012 18:16:28
  101 4/10 / 2012 09:33:48
  101 4/10 / 2012 12:36:28
  101 4/10 / 2012 20:36:12
  101 4/11 / 2012 09:36:28
  101 4/11 / 2012 16:36:22
  Here, I need to display the following columns
  
  EmpID, min (DAT) as start, max (dat) as end and difference (max (dat) - min (dat) for each day,
  for example,.
  End difference EmpID Strart
  101 4/9/2012 09:48:54 09/04/2012 18:16:28 8.28
  Like this.
  3 days different here is so it should return 3 discs with the mentioned columns above,
  Please help me find it.
  
  Thank you
  Kind regards
  Gurujothi
  
  Published by: Gurujothi on April 25, 2012 04:45

  Gurujothi wrote:
  Dear Alex,
  Thank you for your reply,
  Depending on whether you are your quesy showing it in hour and minutes format its right but you mention all rows of the query
  If the table has more than 3000 lines then how it is possible to write this much higher request,
  my table with almost 3500 lines.

  You can make a few changes in the above query I posted the last I mentioned?

  Thank you.

  Published by: Gurujothi on April 25, 2012 23:18

  Hello

  You don't need to write whole records 3000 it... alex just wrote that for example have no table as your table...
  so just use the under part of this query as in the previous post, alex:

  select empid, trunc(dat),
         min(dat) as start_dat,  to_char(min(dat), 'hh24:mi:ss') as start_dat_part,
         max(dat) as end_dat, to_char(max(dat), 'hh24:mi:ss') as end_dat_part,
         max(dat)-min(dat) diff, to_char(max(dat)-min(dat), 'hh24:mi:ss') diff_part,
         extract(day from max(dat)-min(dat)) || ' days'
         || ':' ||  extract(hour from max(dat)-min(dat)) || ' hours'
         || ':' ||  extract(minute from max(dat)-min(dat)) || ' mins'
         || ':' ||  extract(second from max(dat)-min(dat)) || ' sekas'
  from trans
  group by empid, trunc(dat)
  

  hope this fixes your need

• How to tell the difference between recommended, and optional updates long after they have installed bene?

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  In the past, I've confirmed that optional udates be installed. Please help: now I want to uninstall optional updates because my computer is slow.  How to tell the difference between recommended, and optional updates long after they have installed bene?

  Hey monkey 44,

  I suggest you view the history in Windows Update:

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  Those listed as recommended is technically optional.

  Before you delete updates the computer, I suggest you try the steps from the following link to improve performance and check if that helps:

  http://Windows.Microsoft.com/en-us/Windows-Vista/ways-to-improve-your-computers-performance

  I hope this helps.

• How to find the difference in date in years, months and days

  Hello
  I need to find the difference between 2 dates in the following way "years months days". "
  Please can help me, how can I achieve this.
  
  for example, in the scott schema emp table, I need to find the difference in date between sysdate and hiredate for an employee in the following way.
  
  12 years 7 months 4 days.

  Hello

  Please, see this post to AskTom [difference between 2 dates | http://asktom.oracle.com/pls/asktom/f?p=100:11:0:P11_QUESTION_ID:96012348060]. There is good information in this forum, for example you can also see this thread [calculation of years, months & days | http://forums.oracle.com/forums/thread.jspa?messageID=3115216�]

  Kind regards

  Published by: Walter Fernández on November 30, 2008 08:58 - adding another link

• Find the difference between two numbers (DBL)

  Hi all

  Is there a function in labview other than the subtraction function that can find the difference between the two numbers given?

  Thank you

  Davidson

  
  

• How to find the library files that are not due to problems of indexing

  I need help to know how to find the library files that are not as a result of indexing problems?

  I use Windows 7

  Thank you

  Charlene

  Try to open the folder that the library uses directly.  For example, if it is your Documents folder, open C:\Users\Charlene\Documents

• How to store the difference between two timestamps as a number?

  Hello
  I need to find the difference between 2 variables of timestamp and the result will be stored as a number in minutes?
  as
  declare
  timestamp (7) of the fir_timestamp: = 1 January 2012 13:30 ';
  timestamp (7) of the sec_timestamp: = 1 January 2012 14:00 ';
  c number;
  Start
  c:=((sec_timestamp-fir_timestamp)/(24*60));
  dbms_output.put_line (c);
  end;

  962813 wrote:
  declare

  -fir_timestamp timestamp (7): ='01 - jan - 2012 13:30 ';
  timestamp (7) of the sec_timestamp: = 1 January 2012 14:00 ';  Incorrect type declaration

  fir_timestamp timestamp: = 1st January 12 01.30.00.000000 PM';
  sec_timestamp timestamp: = 1st January 12 02.00.00.000000 PM';
  c number;
  Start
  c: = ABS ((extrait (HEURE de sec_timestamp) - extract (fir_timestamp TIME)) * 60) +.
  ABS ((extrait (MINUTE de sec_timestamp) - extract (fir_timestamp MINUTE)));
  dbms_output.put_line (' interval Min Total:-' | c);
  end;
  /
  declare
  *
  ERROR on line 1:
  ORA-01830: date format picture ends before converting all of the input string
  ORA-06512: at line 6

  Follow what Paul has done...

  In fact, you do not need timestamp, date data type is enough

  SQL> declare
    2     fir_timestamp date :=
    3        to_date('01-jan-2012 13:30:00','dd-mon-yyyy hh24:mi:ss');
    4     sec_timestamp date :=
    5        to_date('01-jan-2012 14:00:00','dd-mon-yyyy hh24:mi:ss');
    6     c number;
    7  begin
    8     c:= round((sec_timestamp-fir_timestamp)*24*60);
    9     dbms_output.put_line(c);
   10  end;
   11  /
  30
  
  PL/SQL procedure successfully completed.
  

  If you want to place on timestamp

  SQL> declare
    2     fir_timestamp timestamp :=
    3        to_timestamp('01-jan-2012 13:30:00','dd-mon-yyyy hh24:mi:ss');
    4     sec_timestamp timestamp :=
    5        to_timestamp('01-jan-2012 14:00:00','dd-mon-yyyy hh24:mi:ss');
    6     c number;
    7  begin
    8     c:= round((
    9     to_date(to_char(sec_timestamp,'ddmmyyyyhh24miss'),
   10             'ddmmyyyyhh24miss')-
   11          to_date(to_char(fir_timestamp,'ddmmyyyyhh24miss'),
   12             'ddmmyyyyhh24miss')
   13           )*24*60);
   14     dbms_output.put_line(c);
   15  end;
   16  /
  30
  

• How to find the relationship between the tables

  Hello
  I am working in Oracle R12
  
  How to find the relationship between these tables INV_MIN_MAX_TEMP, po_requisition_lines_all and Per_all_people_f
  
  These two tables, I joined with po_requisition_lines_all and Per_all_people_f To_person_id of PO and anyone HR table but I can't able to join this table with other tables INV_MIN_MAX_TEMP
  
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• Find the difference between two date and time

  Hi friends,
  
  I wanted to find the difference between two date and time, but my qury is slightest error "invalid number."
  
  

  select sql_step_num,proc_name,run_seqno,start_date,end_date,(to_char(start_date,'HH24-MI-SS') - to_char(end_date,'HH24-MI-SS') ) as ed  
  from eval.EVAL_RUNTIME_DETAILS
  where trunc(start_date) = trunc(sysdate) 
  order by sql_step_num;

  You try to get the feel between two char strings.
  And more difference between two dates gives a NUMBER of days.
  Try this:

  select sql_step_num,proc_name,run_seqno,start_date,end_date,numtodsinterval(end_date-start_date,'DAY') as ed
  from eval.EVAL_RUNTIME_DETAILS
  where trunc(start_date) = trunc(sysdate)
  order by sql_step_num;
  

• FormCalc - how to calculate the difference between the two fields datetime in hh: mm?

  Hello!

  I am building a form of time sheet in which I need to calculate the difference between the start and end times and present the result.

  I'm trying to do with FormCalc but if it is easier with JS is ok too.

  So that's what I did on the total field, by using the calculate on a NUMERIC field called decimalValue event:

  elapsed = Time2Num (endTime.formattedValue, "HH: mm")-Time2Num (startTime.formattedValue, "HH: mm")

  And then I tried to convert a time field:

  Total = decimalValue.rawValue;

  $.formattedValue = Num2Time (total, "HH: mm")

  Well, it doesn't work, it gives me crazy results in the datetime (total) field. If I type 09:00 and 09:30, the final result is... 22:30. Huh?

  Please, could someone help me understand how this thing works?

  Thanks a lot for the tips!

  Marcos

  Hi Marcos,

  Here are some examples:

  https://Acrobat.com/#d=kCPIgVkd09qrx6h-WRXxbQ

  https://Acrobat.com/#d=EsWqBMBt3sgEXnMSsK5pRA

  Hope that helps,

  Niall

• How to make the difference between the mouse down events in the control of the chain (click on contour vs click Center)?

  Hello

  I have a control over the chain on my UI and I would like to make the difference between mouse different events, that is to say, to be able to differentiate a click on the outline or the label of the controller vs right-clicking on the Center (between the control in "edit" mode)

  The reason is that sometimes if the user does click not in the Center but in the scope of control, Labview fires the mouse event down but the typed keys are not registered...

  Is it possible to distinguish the two?

  Thanks a lot for your help

  Set the string "update as you type" and use instead a "changed value" event Now, the event fires whenever a new character is entered.

• How to tell the difference between default programs downloaded vs programs

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  What operating system is installed on your computer?

  Built-in applications on Windows will not appear in the control panel of Windows. The programs you have downloaded only appears in the Panel. If you want to uninstall any program downloaded, you can uninstall it from Control Panel.

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