Identify locked objects

Hello
How can I identify locked objects in my oracle DB?

Try this,

SELECT S.SID SID,
       S.USERNAME USERNAME,
       S.MACHINE MACHINE,
       L.TYPE TYPE,
       O.OBJECT_NAME OBJECT_NAME
  FROM V$LOCK L, V$SESSION S, DBA_OBJECTS O
 WHERE L.SID = S.SID
   AND USERNAME != 'SYSTEM'
   AND O.OBJECT_ID(+) = L.ID1
 ORDER BY S.SID;

Tags: Database

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      f6 dd=18 locks held 0    write locks 0    pid/thread 1284/2648
      f7 dd=17 locks held 0    write locks 0    pid/thread 1284/2648
      f8 dd=16 locks held 0    write locks 0    pid/thread 1284/2648
      f9 dd=15 locks held 0    write locks 0    pid/thread 1284/2648
      fa dd=14 locks held 0    write locks 0    pid/thread 1284/2648
      fb dd=13 locks held 0    write locks 0    pid/thread 1284/2648
      fc dd=12 locks held 0    write locks 0    pid/thread 1284/4184
      fd dd=11 locks held 0    write locks 0    pid/thread 1284/2672
      fe dd=10 locks held 0    write locks 0    pid/thread 1284/4184
      ff dd= 8 locks held 0    write locks 0    pid/thread 1284/2672
     100 dd= 7 locks held 0    write locks 0    pid/thread 1284/2672
     101 dd= 5 locks held 0    write locks 0    pid/thread 1284/2648
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80000045 WRITE         1 HELD    test.dbxml                page         11
8000004d dd= 6 locks held 0    write locks 0    pid/thread 1284/4100
8000004e dd= 6 locks held 0    write locks 0    pid/thread 1284/4100
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80000051 dd= 3 locks held 1    write locks 0    pid/thread 1284/2648
80000051 READ          1 HELD    test.dbxml                page         13
80000054 dd= 2 locks held 0    write locks 0    pid/thread 1284/5816
80000054 READ          1 WAIT    test.dbxml                page         13
80000055 dd= 1 locks held 0    write locks 0    pid/thread 1284/4824
80000055 READ          1 WAIT    test.dbxml                page         13
80000056 dd= 0 locks held 0    write locks 0    pid/thread 1284/2648
80000057 dd= 0 locks held 0    write locks 0    pid/thread 1284/2648
80000057 READ          1 WAIT    test.dbxml                page         11
=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=
Locks grouped by object:
Locker   Mode      Count Status  ----------------- Object ---------------
80000045 WRITE         1 HELD    test.dbxml                page         11
8000004e READ          1 WAIT    test.dbxml                page         11
80000057 READ          1 WAIT    test.dbxml                page         11

      b1 READ          1 HELD    test.dbxml                handle       10

      ad READ          1 HELD    test.dbxml                handle        8

      bc READ          1 HELD    test.dbxml                handle       14

80000051 READ          1 HELD    test.dbxml                page         13
80000045 WRITE         1 WAIT    test.dbxml                page         13
80000054 READ          1 WAIT    test.dbxml                page         13
80000055 READ          1 WAIT    test.dbxml                page         13

      b5 READ          1 HELD    test.dbxml                handle       12

      a1 READ          1 HELD    test.dbxml                handle        2

      b5 READ          6 HELD    test.dbxml                handle        0
      c0 READ          2 HELD    test.dbxml                handle        0
      f1 READ          1 HELD    test.dbxml                handle        0

      a9 READ          1 HELD    test.dbxml                handle        6

      a5 READ          1 HELD    test.dbxml                handle        4

      f1 READ          1 HELD    test.dbxml                handle       18

      c0 READ          1 HELD    test.dbxml                handle       16

    The problem here is that you have multiple active transactions on a single thread. The reason that the transaction wire 80000051 2648 is not moving forward and renounce its lock is because the thread is blocked with transaction 80000057 2648 thread waiting on page 11, that 80000045 holds. When a thread has several transactions in Berkeley DB XML built detection of blockages can not say he is in a bind, because it assumes that transactions are on different threads and therefore increase.

    Lauren Foutz

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