Matrix of cross product on a HP 50 g

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• OpenGL Helper Library (GLU)

  Hello

  There no GLU library in the ndk blackberry?

  If so, can anyone give me the definition of the function gluLookAt sets out in this library, please.

  Already, thank you for your supply.

  monmomo04.

  "public static void gluLookAt(float eyeX, eyeY float, float eyeZ, float centerX, centerY of float, float centerZ, float upX, float upY, float upZ)" "

  Sorry for the late reply.

  In all, I was not able to import library glues that laurence spoke in his post (link to it: http://code.google.com/p/glues/ ), but fortunately the definition of the function works like a charm.

  Once again, thank you for your response.

  It is:

  gluLookAt (GLfloat eyex, eyey, GLfloat GLfloat eyez,
  GLfloat centerx, centery GLfloat, GLfloat centerz,.
  GLfloat upx upy upz GLfloat GLfloat) {}
  GLfloat m [16];
  GLfloat x [3], y [3], z [3];
  GLfloat mag;

  / * Make the rotation matrix * /.

  / * Vector Z * /.
  z [0] = eyex - centerx;
  z [1] = eyey - centery;
  z [2] = eyez - centerz;
  MAG = sqrt (z [0] * [0] z + z [1] * z [1] + [2] z * z [2]);
  If (mag) {/ * mpichler, 19950515 * /}
  z [0] / = mag;
  z [1] / = mag;
  [2] z / = mag;
  }

  / * Are vector * /.
  y [0] = upx.
  y [1] = upy;
  [2] y = upz.

  / * Vector X = cross Z * /.
  x [0] = y [1] * [2] z - y [2] * z [1];
  x [1] = y [0] * z [2] + [2] y * z [0];
  x [2] = y [0] * [1] z - y [1] * z [0];

  / * Recompute Y = Z X cross * /.
  y [0] = z [1] * x [2] - [2] z * x [1];
  y [1] = - z [0] * x [2] + [2] z * x [0];
  [2] y = z [0] * [1] x - z [1] * x [0];

  / * mpichler, 19950515 * /.
  / * cross product gives the area of a parallelogram, which is< 1.0="">
  * No perpendicular unit vectors length; therefore normalize x, y here
  */

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  y [1] / = mag;
  y [2] / = mag;
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  #define (row, col) M m [col * line 4 +]
  M (0, 0) = x [0];
  M (0, 1) = x [1];
  M (0, 2) = x [2];
  M (0, 3) = 0.0;
  M (1, 0) = y (0);
  M (1, 1) = y [1];
  M (1, 2) = y [2];
  M (1, 3) = 0.0;
  M (2, 0) = z [0];
  M (2, 1) = z [1];
  M (2, 2) = z [2];
  M (2, 3) = 0.0;
  M (3, 0) = 0.0;
  (3, 1) M = 0.0;
  M (3, 2) = 0.0;
  M (3, 3) = 1.0;
  #undef M
  glMultMatrixf (m);

  / Eyes on the origin of the translation * /.
  glTranslatef (-eyex, - eyey -, eyez);
  }

• Draw an arc with 3 points.

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  Welcome to QQ Group: LabVIEW_Home 213985957

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  580663 001

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  Manual

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  You can buy the SP9300 motherboard for $45 shipped on eBay:

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  The same seller also has the SU7300 for a few dollars less:

  http://www.eBay.com/ITM/584078-001-HP-dm3-1000-laptop-motherboard-w-Intel-SU7300-1-3GHz-CPU-/400600978029?PT=motherboards&hash=item5d45add26d

  I bought a little of this seller and it looks like they have a lot of them on the spot so must have dismantled a certain dm3s. Maybe if you call them they can steer you in a way or another based on real practical experience. I confess that I have the opportunity to work on this exact model.

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• How to create views of data from different databases tables in2

  Using Oracle 10.2 g
  
  I have 2 databases Gus and the haggis on schema Comqdhb.
  
  Glink indicates a link of database between Haggis and Gus
  
  In Gus, there is school that contains columns with same name upn, grade, subject, student of tables...
  
  STUDENT
  UPN
  academicYear
  
  Object
  
  Object
  
  GRADE
  examlevel
  grade
  
  SCHOOL
  SN
  
  In HAGGIS raising tables, grade, teacher containing columns upn... desc below.
  
  STUDENT
  UPN
  
  GRADE
  grade
  UPN
  academicyear
  level
  
  
  
  Create views in your database HAGGIS who join their all the qualities of the review. You should have a point of view that will produce the following relationship:
  examGrade (upn, subject, examlevel, sn, rank, academicYear)
  
  So I need to create a view that gets the data from the tables in the databases.
  
  create view as examGrade (upn, subject, examlevel, sn, rank, academicYear) like some s.upn
  
  
  But I don't get the selection of a column of 2 tables in different databases
  
  I mean if I said
  
  Select the UPN in comqdhb.student@glink,comqdhb.student;
  Select the upn name in comqdhb.student@glink,comqdhb.student
  *
  ERROR on line 1:
  ORA-00918: column ambiguously defined
  
  Help me, thank you.

  Hello

  Rider wrote:
  The issue is that I can't understand that I should create the view by the union of the haggis and the two gus data or only haggis.
  the reason I believe I need to combine the two is mentioned * "" create views in your database schema HAGGIS who join their all the qualities of the review. ". *
  By the mention of creating views and who join their all the qualities of the review, it probably means to obtain the data of the GUS and HAGGIS.

  This is my interpretation of the assignment, too.
  If you ask just the tables on Gus, you will get the ranks of three of the four schools: it's not all examination classes.
  If you ask just the tables on Haggis, you will get the ranks of any of the four schools: it's not all examination classes.

  2nd prob is that if have decided to create a view that gets the data from these two gus and therer haggis would be a lot of duplication involved due to the cross product

  Why would there be "repetition involved due to the cross-product"?
  If the quuery of Gus produces 100 lines, the request of product Haggis 30 rows, then the UNION of the two will have 100 + 30 = 130 lines (assuming, as you say, each student is at school only one).

  the query I wrote is

  Create view examGrade (upn, subject, examlevel, sn, rank, academicYear)
  as
  Select distinct s.upn as upn, g.subject as topic,
  g."LEVEL" as examlevel, g.grade as rank, to_number (g.academicyear) as academicyear
  of s comqdhb.student, comqdhb.grade g
  s.UPN, sb.subject, g.elevel, g.grade, s.acyr select Union
  of comqdhb.subject@glink sb,comqdhb.student@glink s,comqdhb.gradevalues@glink g;

  You should not write, not to mention not formatted zip code. I have a little time I can devote to answering questions in the forum. Do you want me
  b spend this time formatting your code, so I can understand the question, and no time to answer, or
  b spend only a little time reading understanding your code and spend most of my time to help you?
  I would prefer (b), but the choice is yours.
  See the statement that I posted in my last post for an example of the formatted code. You see how it appears in a box with a police fixed-width, and multiple spaces are printed? This is because I typed {code} (all small letters), before and after the section I wanted formatted.

  At least put each table in the FROM clause on a separate line, so it is easy to know if you have enough join conditions.
  If you have N tables in the FROM clause, you almost always have at least N-1 join conditions that specify how the tables are linked together. For example, if talk you about two tables, quality and student, you expect to see a join condition that tells you when you have data in a table, how to find related data in the other table, such as

  g_gus.upn = s_gus.upn
  

  No no no join conditions will cause "repetition involved due to the cross product.

  I downloaded my info here
  http://www.upload4free.com/download.php?file=44201983-School_ExamGrades.PDF

  
  http://www.upload4free.com/download.php?file=184648736-ExamGrades_Case_Study_2008FINAL.PDF

  Sorry, if there is data as long as you can't post here, there is much too much for me to read.
  Make a sample set, containing a few (maybe five) students and a few shades of each student. It is fine to copy a few lines of your actual data.

  That's all the time I have for today. I can't wait to get the data and formatted requests.

• Difference between a CROSS JOIN and a Cartesian product of the noted comma?

  Hello everyone,
  
  Oracle version: Oracle Database 11 g Enterprise Edition Release 11.2.0.1.0 - 64 bit
  OS: Linux Fedora Core 17 (x86_64)
  
  I was practicing on recursive subquery factoring based on oracle examples available in the documentation
  http://docs.Oracle.com/CD/E11882_01/server.112/e26088/statements_10002.htm#i2129904
  
  I was working on an example that displays the hierarchy of each manager with related employees. Here's how

  WITH tmptab(empId, mgrId, lvl) AS
  (
      SELECT  employee_id, manager_id, 0 lvl
      FROM employees
      WHERE manager_id IS NULL
      UNION ALL
      SELECT  employee_id, manager_id, lvl+1
      FROM employees, tmptab
      WHERE (manager_id = empId)
  )
  SEARCH DEPTH FIRST BY mgrId SET order1
  SELECT LPAD(' ', lvl * 3, ' ') || empId AS empId
  FROM tmptab;

  Which gives the desired result
  

  EMPID
  ---------------------
  100
     101
        108
        109
        110
        111
        112
        113
        200
        203
        204
        205
        206
     102
        103
        104
        105
        106
        107
     114
        115
        116
        117
        118
        119
     120
        125
        126
        127
        128
        180
        181
        182
        183
     121
        129
        130
        131
        132
        184
        185
        186
        187
     122
        133
        134
        135
        136
        188
        189
        190
        191
     123
        137
        138
        139
        140
        192
        193
        194
        195
     124
        141
        142
        143
        144
        196
        197
        198
        199
     145
        150
        151
        152
        153
        154
        155
     146
        156
        157
        158
        159
        160
        161
     147
        162
        163
        164
        165
        166
        167
     148
        168
        169
        170
        171
        172
        173
     149
        174
        175
        176
        177
        178
        179
     201
        202
  
  107 rows selected.
  
  SQL> 

  However, by chance, I noticed that if I put CROSS JOIN instead of put a comma between table names, the same query behaves differently.
  
  In other words, if instead of writing

  . . .
  UNION ALL
      SELECT  employee_id, manager_id, lvl+1
      FROM employees, tmptab
      WHERE (manager_id = empId)

  I am writing

  . . .
  UNION ALL
      SELECT  employee_id, manager_id, lvl+1
      FROM employees CROSS JOIN tmptab
      WHERE (manager_id = empId)

  I get the following error message

  ERROR at line 4:
  ORA-32044: cycle detected while executing recursive WITH query

  Any idea?
  Correct me if I'm wrong, but I remember, oracle supports as many JOIN CROSSROADS notation for Cartesian product (vector product =). For example

  SQL> WITH tmptab1 AS
    2  (
    3      SELECT 'a1' AS colval FROM DUAL UNION ALL
    4      SELECT 'a2' AS colval FROM DUAL UNION ALL
    5      SELECT 'a3' AS colval FROM DUAL
    6  ),
    7  tmptab2 AS
    8  (
    9      SELECT 'b1' AS colval FROM DUAL UNION ALL
   10      SELECT 'b2' AS colval FROM DUAL
   11  )
   12  SELECT t1.colval, t2.colval
   13  FROM tmptab1 t1 CROSS JOIN tmptab2 t2;
  
  CO CO
  -- --
  a1 b1
  a2 b1
  a3 b1
  a1 b2
  a2 b2
  a3 b2
  
  6 rows selected.
  
  SQL> LIST 13
   13* FROM tmptab1 t1 CROSS JOIN tmptab2 t2
  SQL>
  SQL>
  SQL> CHANGE /CROSS JOIN/,
   13* FROM tmptab1 t1 , tmptab2 t2
  SQL> 
  SQL>
  SQL> LIST
    1  WITH tmptab1 AS
    2  (
    3  SELECT 'a1' AS colval FROM DUAL UNION ALL
    4  SELECT 'a2' AS colval FROM DUAL UNION ALL
    5  SELECT 'a3' AS colval FROM DUAL
    6  ),
    7  tmptab2 AS
    8  (
    9  SELECT 'b1' AS colval FROM DUAL UNION ALL
   10  SELECT 'b2' AS colval FROM DUAL
   11  )
   12  SELECT t1.colval, t2.colval
   13* FROM tmptab1 t1 , tmptab2 t2
  SQL> 
  SQL> /
  
  CO CO
  -- --
  a1 b1
  a2 b1
  a3 b1
  a1 b2
  a2 b2
  a3 b2
  
  6 rows selected.
  
  SQL> 

  So if the two rated commas and CROSS JOIN have the same semantics, why do I get a cycle mentioned above cites recursive subquery factoring while the same query works pretty well with comma between table instead of CROSS JOIN names? Because if a cycle is detected (= current element ancestor) it means that the product with the CROSS JOIN notation produces duplicates which are absent in the result of the Cartesian product rated comma.
  
  I would appreciate it if you could kindly shed some light.
  
  Thanks in advance,
  
  Kind regards
  Dariyoosh

  Hello

  dariyoosh wrote:
  ... Oracle terminology could become really confusing. But once again, according to the online glossary, a Cartesian product is apparently regarded as a join
  http://docs.Oracle.com/CD/E11882_01/server.112/e25789/glossary.htm?type=popup#CNCPT44493
  >

  There is no doubt that a Cartesian product (also called cross join) is a join. If loops in a WITH recursive clause are detected after completing the joins, but before other conditions apply, the relevant question here is "what are the requirements to join?
  In the ANSI syntax, the distinction is always clear. Join conditions occur in the... Clause WE

  SELECT  employee_id, manager_id, lvl + 1
  FROM      employees
  JOIN        tmptab          ON  (manager_id = empId)     -- Join condition
  ;
  

  and other conditions occur in the WHERE (or HAVING or CONNECT BY) clause.

  SELECT  employee_id, manager_id, lvl + 1
  FROM            employees
  CROSS JOIN         tmptab
  WHERE  (manager_id = empId)     -- NOT a join condition
  ;
  

  In the joins of the former, it seems to be the case that any condition involving 2 or more tables (or the + indicator of outer join) is a condtion of join:

  SELECT  employee_id, manager_id, lvl + 1
  FROM      employees
  ,         tmptab
  WHERE  (manager_id = empId)     -- Join condition
  ;