measurement of the phase of the signal

Hi all

I'm trying measureme the phase of the sine wave.

I produced sine waveform and give '' measure spectral '' VI express to measure the magnitude and phase. The block of spectral measure gives picture of the spectrum amplitude and phase with the difference in frequency of 1 Hz.

The input signal is 10 Hz sine wave. so I checked the 10th item in the table of phase and amplitude. I'm getting the right size. but I get different values for phase measurement

For example, if the input signal of 0 degrees phase shift, the spectral measure gives as-90 degree. If the input signal has the phase shift of 20 degrees, the measure blocks gives as-70 degrees.

I can't able to find that how to pass this phase-90 degree occurs.

Kindly help to solve. I thank in advance.

with respect,

Renaud V

Renaud V,

The spectral measurement VI uses the FFT internally. In the detailed help for the FFT, the following definition is displayed:

Note that exp(-j*2*pi*theta) = cos(2*pi*theta) - i * sin(2*pi*theta). This phase shift is defined in respect to the cosine, and non sine, explaining the 90-degree turn.

Lynn

Tags: NI Software

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