START WITH and CONNECT BY in Oracle SQL (hierarchical)

Hi, the original table as below
Customer_ID         Account_ID          Paying_Account_ID         Parent_Account_ID          Company_ID
158                    158                    158                         158                     0
159                    159                    158                         158                     0
160                    160                    158                         158                     0
181                    181                    181                         181                     0
183                    183                    183                         183                     0
24669                  24669                  24669                       24669                   0         
24671                  24671                  24671                       24669                   0
24670                  24670                  24670                       24669                   0     
3385127                3385127                3385127                     24670                   0
To identify the hierarchical relationship of the data, which are PARENT_ACCOUNT_ID & ACCOUNT_ID, here's the query I used.
 select  lpad(' ', 2*level) || A.ACCOUNT_ID AS LEVEL_LABEL, CONNECT_BY_ISCYCLE "Cycle", LEVEL, A.* from ACCOUNT A
START WITH parent_account_id = account_id
CONNECT BY NOCYCLE  PRIOR A.ACCOUNT_ID = A.PARENT_ACCOUNT_ID
AND account_id != parent_account_id
;
It is the result of the query
Level_Label              Level          Cycle        Customer_ID             Account_ID        Paying_Account_ID      Parent_Account_ID      Company_ID
158                         1             0              158                     158              158                   158                     0
   159                      2             0              159                     159              158                   158                     0
   160                      2             0              160                     160              158                   158                     0
181                         1             0              181                     181              181                   181                     0
183                         1             0              183                     183              183                   183                     0
24669                       1             0              24669                   24669            24669                 24669                   0       
    24671                   2             0              24671                   24671            24671                 24669                   0
    24670                   2             0              24670                   24670            24670                 24669                   0
        3385127             3             0              3385127                 3385127          3385127               24670                   0
My question is how can I changed the query to calculate the values for:

My_Total_PR - number of my accounts to child PR which do not include himself.
Total_PR - Total number of accounts PR in the overall structure
My_Total_NPR - number of my accounts of child NPR which do not include himself.
Total_NPR - Total number of accounts NPR in the overall structure

* PR stand for responsible for payment, for example the responsible account payment 158 158 (Paying_Account_ID), therefore the Total_PR to 158 is 3 (158, 159, 160)
* NPR stand responsible for Non-payment, for example the responsible account payment 159 is 158 (Paying_Account_ID), so the Total_NPR for 159 1

This is the expected result, any advice appreciated. Thank you
Level_Label                     Level           Cycle           My_Total_PR     Total_PR     My_Total_NPR     Total_NPR     Paying_Account
158                               1                0                  2              3          0              0              158
    159                           2                0                  0              0          0              1              158
    160                           2                0                  0              0          0              1              158
181                               1                0                  0              1          0              0              181
183                               1                0                  0              1          0              0              183
24669                             1                0                  0              1          3              3              24669                   
    24671                         2                0                  0              1          0              0              24671
    24670                         2                0                  0              1          1              1              24670
        3385127                   3                0                  0              1          0              0              3385127
Published by: user11432758 on February 14, 2012 01:00

Published by: user11432758 on February 14, 2012 07:05

Hello

user11432758 wrote:
Hi here is the statement DDL, thank you

CREATE TABLE "SYSTEM"."ACCOUNT" ...

Do not create your own objects in the diagram of the SYSTEM or any scheme that comes with the database. Create a separate schema and place your items. You'll have fewer security problems, and the migration to a new database will be easier.

Here's a way to can get the aggregates you want:

WITH     got_descendants          AS
(
     SELECT     CONNECT_BY_ROOT account_id     AS ancestor_id
     ,     paying_account_id
     ,     LEVEL                    AS lvl
     FROM     account
     CONNECT BY NOCYCLE     PRIOR account_id     = parent_account_id
          AND          account_id          != parent_account_id
)
SELECT       ancestor_id
,       COUNT (CASE WHEN lvl             > 1
                  AND  ancestor_id  = paying_account_id THEN 1 END)     AS my_total_pr
,       COUNT (CASE WHEN ancestor_id  = paying_account_id THEN 1 END)     AS total_pr
,       COUNT (CASE WHEN lvl             > 1
                  AND  ancestor_id != paying_account_id THEN 1 END)     AS my_total_npr
,       COUNT (CASE WHEN ancestor_id != paying_account_id THEN 1 END)     AS total_npr
FROM       got_descendants
GROUP BY  ancestor_id
;

Output:

`             MY_         MY_
            TOTAL TOTAL TOTAL TOTAL
ANCESTOR_ID   _PR   _PR  _NPR  _NPR
----------- ----- ----- ----- -----
        158     2     3     0     0
        159     0     0     0     1
        160     0     0     0     1
        181     0     1     0     0
        183     0     1     0     0
      24669     0     1     3     3
      24670     0     1     1     1
      24671     0     1     0     0
    3385217     0     1     0     0

This gives the correct numbers, but how can bring us in an order that reflects the hierarchy, with the columns (for example lvl) that come from the hierarchy?
A solution would be to make two CONNECT BY queries; a service without START WITH clause (like the one above) who collects the aggregates and the other with a START WITH clause (as your original query), which is in the right order and columns such as level_label and level. We could join result sets and get exactly what we want. I'll leave that as an exercise.

Here is another way, which gets good results with only one CONNECTION PER request:

WITH     got_descendants          AS
(
     SELECT     CONNECT_BY_ROOT account_id     AS ancestor_id
     ,     paying_account_id
     ,     account_id
     ,     LEVEL                    AS lvl
     ,     CONNECT_BY_ISCYCLE          AS cycle
     ,     CASE
              WHEN  CONNECT_BY_ROOT account_id
                  = CONNECT_BY_ROOT parent_account_id
              THEN  ROWNUM
          END                    AS r_num
     FROM     account
     CONNECT BY NOCYCLE     PRIOR account_id     = parent_account_id
          AND          account_id          != parent_account_id
     ORDER SIBLINGS BY     account_id     -- Optional
)
,     got_o_num     AS
(
     SELECT     got_descendants.*
     ,     MIN (r_num) OVER (PARTITION BY  account_id)     AS o_num
     ,     MAX (lvl)   OVER (PARTITION BY  account_id)      AS max_lvl
     FROM     got_descendants
)
SELECT       LPAD ( ' '
            , 2 * (MIN (max_lvl) - 1)
            )  || ancestor_id                         AS level_label
,       MIN (max_lvl)                                AS "Level"
,       MIN (cycle)                                   AS "Cycle"
,       COUNT (CASE WHEN lvl             > 1
                  AND  ancestor_id  = paying_account_id THEN 1 END)     AS my_total_pr
,       COUNT (CASE WHEN ancestor_id  = paying_account_id THEN 1 END)     AS total_pr
,       COUNT (CASE WHEN lvl             > 1
                  AND  ancestor_id != paying_account_id THEN 1 END)     AS my_total_npr
,       COUNT (CASE WHEN ancestor_id != paying_account_id THEN 1 END)     AS total_npr
,       MIN (paying_account_id)                                    AS paying_account
FROM       got_o_num
GROUP BY  ancestor_id
ORDER BY  MIN (o_num)
;

Output:

`                             MY_         MY_
                            TOTAL TOTAL TOTAL TOTAL  PAYING_
LEVEL_LABEL     Level Cycle   _PR   _PR  _NPR  _NPR  ACCOUNT
--------------- ----- ----- ----- ----- ----- ----- --------
158                 1     0     2     3     0     0      158
  159               2     0     0     0     0     1      158
  160               2     0     0     0     0     1      158
181                 1     0     0     1     0     0      181
183                 1     0     0     1     0     0      183
24669               1     0     0     1     3     3    24669
  24670             2     0     0     1     1     1    24670
    3385217         3     0     0     1     0     0  3385217
  24671             2     0     0     1     0     0    24671

That's exactly what you asked for, except that you have posted the line with level_label =' 24671' before the line with level_label = "24671 '. You may not care about who comes first, but if it's important, explains why these lines should be in descending order of account_id, while "159 and 160" are in ascending order. You will need change the ORDERBY brothers and SŒURS clause accordingly.

Tags: Database

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    Hello

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    1.

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    A CONNECT BY query looks like an operation UNION ALL of the data of different levels, numbered 1, 2, 3 and more.

    Level 1 is filled with the START WITH clause.

    If there are data on level N, then N + 1 level is filled, using the CONNECT BY clause, which generally refers to something on the N level via the PRIOR operator.  Another way to put it is that level N + 1 is filled by a self-join with lines that have already chosen the level N.

    If there is no data on the level of N, the query stops.

    Let's see how this applies to your queries.

    Level being such an important concept in CONNECT BY queries, you might want to see in all your CONNECT BY queries all test and debug the.

    1 query, including the level are:

    SELECT ename, empno, mgr

    LEVEL

    FROM scott.emp

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    ;

    You will notice that I have re-arranged the CONNECT BY clause.  I find it a little more clear medium.  Of course, it never changes the results just if you say "x = y" or "y = x.

    The results, including the level, are:

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    ---------- ---------- ---------- ----------

    7839 KING 1

    What happened to produce these results?

    First level 1 has been met using the START WITH clause.  Level 1 is identical to the results of

    SELECT ename, empno, mgr

    AS LEVEL 1

    FROM scott.emp

    WHERE empno = 7839 - same as your START WITH clause

    ;

    It happens to be only 1 row in the table scott.emp who met the empno = 7839 condition, and we show a few columns of this line.

    That's all that need the level 1.  Something has been on level 1, so we're trying now to complete level 2, using the CONNECT BY condition.

    Any line that is included in the level 2 meets the empno = mgr PREREQUISITE condition, where the PREVIOUS operator refers to a line of level 1.  In this case, there is only 1 row at level 1, this line gets to have a NULL mgr.  Given that PRIOR mgr is NULL in this case, the condition to connect BY

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    FROM scott.emp

    START WITH mgr = 7839

    CONNECT BY PRIOR Mgr = empno

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    7782 7839 1 7782 CLARK

    7839 KING 2/7566/7839

    7839 KING 2/7698/7839

    7839 KING 2/7782/7839

    Again, we'll study how people got 1 level.  It happens to be 3 scott.emp lines that meet this condition START WITH, so there are 3 lines in the game at level 1.

    Given that the data on the level 1, the test of the query to complete level 2, referring to some PRIOR line on level 1.  Any line that meets the condition to connect BY, with a line any level 1 in the PREVIOUS line, will appear at level 2.

    Let's look at the line at level 1 where ename = 'JONES '.  Are there lines in sccott.emp that met the empno = mgr PREREQUISITE condition, where mgr PREREQUISITE is the column of Archbishop of the line with "JONES"?  Yes, there are one, the line with ename = 'KING', so that the rank is included at level 2.

    Let's look at the line at level 1 where ename = 'BLAKE '.  Are there lines in sccott.emp that met the empno = mgr PREREQUISITE condition, where mgr PREREQUISITE is the column of Archbishop of the line with "BLAKE"?  Yes, there are one, the line with ename = 'KING', so that the rank is included at level 2.

    Let's look at the line at level 1 where ename = 'CLARK '.  Are there lines in sccott.emp that met the empno = mgr PREREQUISITE condition, where mgr PREREQUISITE is the column of Archbishop of the line with 'CLARK '?  Yes, there are one, the line with ename = 'KING', so that the rank is included at level 2.

    There are thus 3 rows at level 2.  They happen to all be on the same line of the table emp; It is correct.  Remember, CONNECT BY is like a UNION ALL (not just a UNION).  It is a UNION of

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    PRIOR empno = mgr means exactly the opposite.  When you move from level N to level N + 1 in the query, you will move to an older person, to a junior position in the hierarchy.  This is called a query from top to bottom.  The employee level N will be the Manager of wover is a level N + 1.

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    Published by: user10648285 on October 17, 2011 23:42

    Published by: user10648285 on October 17, 2011 23:42

    Published by: user10648285 on October 17, 2011 23:43

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  4      union all select 2 as n from dual
  5      union all select 3 as n from dual
  6      union all select 4 as n from dual
  7      union all select 5 as n from dual
  8      union all select 6 as n from dual
  9      union all select 7 as n from dual
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---------- ----------
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