the tables are invisible in cc

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• I create a form based on two tables that have sequences also. When I create insert only row is inserted in the fields in table first and second fields of the table are empty. Why?

  Mr President.

  I create a form based on two tables that have sequences also. When I create insert only row is inserted in the fields in table first and second fields of the table are empty. Why?

  

  the page source is

  <?xml version='1.0' encoding='UTF-8'?>
  <ui:composition xmlns:ui="http://java.sun.com/jsf/facelets" xmlns:af="http://xmlns.oracle.com/adf/faces/rich"
                  xmlns:f="http://java.sun.com/jsf/core">
    <af:panelFormLayout id="pfl1">
      <af:group id="Group">
        <af:inputText value="#{bindings.VoucherId.inputValue}" label="#{bindings.VoucherId.hints.label}"
                      required="#{bindings.VoucherId.hints.mandatory}" columns="#{bindings.VoucherId.hints.displayWidth}"
                      maximumLength="#{bindings.VoucherId.hints.precision}"
                      shortDesc="#{bindings.VoucherId.hints.tooltip}" id="it1">
          <f:validator binding="#{bindings.VoucherId.validator}"/>
          <af:convertNumber groupingUsed="false" pattern="#{bindings.VoucherId.format}"/>
        </af:inputText>
        <af:inputDate value="#{bindings.VoucherDate.inputValue}" label="#{bindings.VoucherDate.hints.label}"
                      required="#{bindings.VoucherDate.hints.mandatory}"
                      columns="#{bindings.VoucherDate.hints.displayWidth}"
                      shortDesc="#{bindings.VoucherDate.hints.tooltip}" id="id1">
          <f:validator binding="#{bindings.VoucherDate.validator}"/>
          <af:convertDateTime pattern="#{bindings.VoucherDate.format}"/>
        </af:inputDate>
        <af:inputText value="#{bindings.Credit.inputValue}" label="#{bindings.Credit.hints.label}"
                      required="#{bindings.Credit.hints.mandatory}" columns="#{bindings.Credit.hints.displayWidth}"
                      maximumLength="#{bindings.Credit.hints.precision}" shortDesc="#{bindings.Credit.hints.tooltip}"
                      id="it2">
          <f:validator binding="#{bindings.Credit.validator}"/>
        </af:inputText>
      </af:group>
      <af:group id="g1">
        <af:inputText value="#{bindings.Lineitem.inputValue}" label="#{bindings.Lineitem.hints.label}"
                      required="#{bindings.Lineitem.hints.mandatory}" columns="#{bindings.Lineitem.hints.displayWidth}"
                      maximumLength="#{bindings.Lineitem.hints.precision}" shortDesc="#{bindings.Lineitem.hints.tooltip}"
                      id="it3">
          <f:validator binding="#{bindings.Lineitem.validator}"/>
          <af:convertNumber groupingUsed="false" pattern="#{bindings.Lineitem.format}"/>
        </af:inputText>
        <af:inputText value="#{bindings.VoucherId1.inputValue}" label="#{bindings.VoucherId1.hints.label}"
                      required="#{bindings.VoucherId1.hints.mandatory}"
                      columns="#{bindings.VoucherId1.hints.displayWidth}"
                      maximumLength="#{bindings.VoucherId1.hints.precision}"
                      shortDesc="#{bindings.VoucherId1.hints.tooltip}" id="it4">
          <f:validator binding="#{bindings.VoucherId1.validator}"/>
          <af:convertNumber groupingUsed="false" pattern="#{bindings.VoucherId1.format}"/>
        </af:inputText>
        <af:inputText value="#{bindings.Debit.inputValue}" label="#{bindings.Debit.hints.label}"
                      required="#{bindings.Debit.hints.mandatory}" columns="#{bindings.Debit.hints.displayWidth}"
                      maximumLength="#{bindings.Debit.hints.precision}" shortDesc="#{bindings.Debit.hints.tooltip}"
                      id="it5">
          <f:validator binding="#{bindings.Debit.validator}"/>
        </af:inputText>
        <af:inputText value="#{bindings.Credit1.inputValue}" label="#{bindings.Credit1.hints.label}"
                      required="#{bindings.Credit1.hints.mandatory}" columns="#{bindings.Credit1.hints.displayWidth}"
                      maximumLength="#{bindings.Credit1.hints.precision}" shortDesc="#{bindings.Credit1.hints.tooltip}"
                      id="it6">
          <f:validator binding="#{bindings.Credit1.validator}"/>
        </af:inputText>
        <af:inputText value="#{bindings.Particulars.inputValue}" label="#{bindings.Particulars.hints.label}"
                      required="#{bindings.Particulars.hints.mandatory}"
                      columns="#{bindings.Particulars.hints.displayWidth}"
                      maximumLength="#{bindings.Particulars.hints.precision}"
                      shortDesc="#{bindings.Particulars.hints.tooltip}" id="it7">
          <f:validator binding="#{bindings.Particulars.validator}"/>
        </af:inputText>
        <af:inputText value="#{bindings.Amount.inputValue}" label="#{bindings.Amount.hints.label}"
                      required="#{bindings.Amount.hints.mandatory}" columns="#{bindings.Amount.hints.displayWidth}"
                      maximumLength="#{bindings.Amount.hints.precision}" shortDesc="#{bindings.Amount.hints.tooltip}"
                      id="it8">
          <f:validator binding="#{bindings.Amount.validator}"/>
          <af:convertNumber groupingUsed="false" pattern="#{bindings.Amount.format}"/>
        </af:inputText>
      </af:group>
      <f:facet name="footer">
        <af:button text="Submit" id="b1"/>
        <af:button actionListener="#{bindings.CreateInsert.execute}" text="CreateInsert"
                   disabled="#{!bindings.CreateInsert.enabled}" id="b2"/>     
        <af:button actionListener="#{bindings.Commit.execute}" text="Commit" disabled="#{!bindings.Commit.enabled}"
                   id="b3"/>
        <af:button actionListener="#{bindings.Rollback.execute}" text="Rollback" disabled="#{!bindings.Rollback.enabled}"
                   immediate="true" id="b4">
          <af:resetActionListener/>
        </af:button>
      </f:facet>
    </af:panelFormLayout>
  </ui:composition>
  
  
  
  

  Concerning

  Go to your VO Wizard, select the tab of the entity and to check if both the EO is editable or not.

  See you soon

  AJ

• In the area of blur the pins are invisible. I can work with the pins, but I can´t see them. How can I make visible?

  In the area of blur the pins are invisible. I can work with the pins, but I can´t see them. How can I make visible?

  Hi ferdinandn

  What version of Phtooshop are you using?

  Is "View > Show > edit the pines ' activated when you select the blur filter?

  

  Concerning

  Assani

• all rows in the table are not eligible for the specified partition

  SQL > Alter Table ABC
  Exchange 2 Partition P1 with Table XYZ;
  
  Modified table.
  
  SQL > Alter Table ABC
  Exchange 2 Partition P2 with Table XYZ;
  
  
  P2 Partition Exchange with XYZ Table
  *
  ERROR on line 2:
  ORA-14099: all rows in the table are not eligible for the specified partition
  
  The exchange partition works fine for the first time. However, if we try to swap the 2nd partition it gives the error.
  How to solve this error?
  How can I find the lines which are not qualified for a specific part. is there a query to find out the same thing?

  >
  Well, exchange of syntax and logic is not clearly as it should (IMHO). There is no element of syntax that tells Oracle we want to Exchange partition data in a table that is not partitioned or not partitioned into partition table data.
  >
  What? Not sure where you got that but maybe it was before you had first cup of coffee? ;)

  An "Exchange", it's just that; an Exchange. Partition data end up in the non-partitioned table and vice versa. It is meaningless and totally obsolete if "we want Exchange partition data in a table that is not partitioned or not partitioned into partition table data".
  >
  It was decided by Oracle not partitioned table control. If the non-partitioned table is empty, it means you want to Exchange data partition in a non-partitioned table. And if not partitioned table is not empty, it means you want to Exchange data in the table that is not partitioned into partition.
  >
  There is no decision to make. The segments are swapped. Oracle doesn't check, know or even care if one or the other or both segments are empty. 'Control' which is carried out (by default except if NO CONTROL is used) only consists of ensuring all the data in the segment intended for the partition belongs to this partition.

  It is what gives the example of John. This can NEVER work if table1 is empty unless p1 is empty at the beginning:
  1 Exchange p1 with table1
  2 Exchange p2 with table1

  As John explains, assuming that no other operations are trying to put the data from p1 P2 which is not possible if p1 actually contains data.

  You can save it for next April 1!

• How to find if the data in the table are distributed on multiple disks

  Hi all
  
  I have a question on parallel processing.
  
  Assume that the Oracle (11 g 2) database is installed on a 12 CPU hardware has 24 independent labels, then I guess it's that we can have a maximum of 12 DOP.
  
  But if the table on which I use the parallel market that spans only 4 discs then the above 4 parallelism will degrade the performance of the query.
  
  My question is how do I know if the data in the table are spread over the number of disk drives, so that we can properly apply valid parallel operations on the table.
  
  Appreciate your valuable contributions here.
  
  Thank you
  MK.

  Just think logically.
  What is a table in the database? A segment.
  What is a segment made up of? Scopes.
  What is recorded on a scale? The id_fichier of the data file.

  ------------
  Sybrand Bakker
  Senior Oracle DBA

• Adding new partition in the table are

  Hello
  
  Oracle 9i
  Windows 2003 operating system
  
  The main entry/exit table is one of the base tables that has a large number of records and a very high success rate, and to avoid poor performance that may occur in such cases, Oracle Table partitioning technique has been examined in the early stages of the implementation of the system.
  
  Unfortunately, the technique used to divide data based on the year of the transaction considered the year 2010 as the last specific partition, so all records created after this year is gathered in a single partition and this may cause poor performance in the years to come.
  
  Are required to add another 10 partitions; up to the year 2020 taking into account that the downtime should be close to zero.
  
  Ground:
  
  According to my knowledge
  
  for this, so we can create a new table with the same columns and add required 10 more partitions, and if we take 2 scenarios like
  
  export/imp
  insertion in the new table select * from < table > old
  
  What is the best, and if we take exp/imp, if her take a few hours of time to complete a task... what will happen for the updates as insert, update, and delete in this time what will be the impact on the import... I mean if all committed tarnscations... These tarnscations automatically add to the table are not.
  
  Please tell me what is the best and the tarnscations should not effect... pls tell me how excatly we can complete the task.
  
  Concerning
  873393

  In my script, I have a DROP TABLE because I'll put up a reproducible demonstration. I can run the script repeatedly and regenerate the same demo data!
  In your environment you would not fall off the table!
  To simplify the demo for you: IGNORE the DROP TABLE command. Pretend it does not exist.

  Hemant K Collette

• The tables are all blacks in Dreamweaver CM³ and text is invisible

  I just spent CS3 to CC, and all my files imported right. Then the only problem is that when I go to change, all the tables where the text is has been missed to black! When I view the page in the browser, it is displayed correctly, but in DW I do not see the text due to the black background.

  I never had this problem during all these years of use of DW, what am I doing wrong or what I need to adjust in the settings to display correctly? Thank you!

  Geoffrey

  Try to do this-

  bgcolor = "c5c7c6."

  -be

  bgcolor = "#c5c7c6."

  That is why it is important to always show your code.

• Values in the table are not default values

  Hi every1,

  I'm working on a VI which relates to the evolution of the points in the chart. Almost, I finished my VI but the thing is that the table of values which

  IAM using here (table Y) do not appear in the value by default when I stop the vi. When I stop and run the vi finally stored values

  Table are defined. One thing is when I click on the stop button is not key to its end. The VI only stops when the stop button goes top

  and then at the bottom. I mean to stop twice the stop button must be clicked. Here's my VI.  Help me to know my mistake here in this

  VI..........

  AAH, I guessed correctly!

  Remove the local var of the button stop & place the terminal itself inside of the while loop inside & it wire directly to the conditional from the outside while loop.

  Please see the attached picture...

• Rows in the table are break on separate pages...

  I have 20 lines equipped table:

  first 3 lines are on one page, then half of the page is empty hen remaining 17 rows is on the second page.

  How can I keep table to break the lines. I want all rows in the table to succeed himself.

  Help, please. Thank you.

  Keep them with parameters are in the table > Format > Format line...

  

  Note: the first row on the second page may also have a start parameter that indicates that it is at the top of a page or column.

  The control of widows and orphans just specifies how many rows to keep together (widow is the first page; ( orphan , is the second page) when a table has over a page. The higher the number, the more lines are forced to remain together.

• Table not found but the data in the Table are available

  Hello
  
  I connected as SYS.
  
  When it is placed below query in sql navigator, no line not found.
  Select * from dba_objects where type_objet = 'TABLE' and object_name = 'GREM. "
  
  But when placed under query, the rows are retrieved.
  Select * from grem.
  
  How is that possible?

  Hulk says:
  It returns: SYNONYM

  So, you have your answer. Now, you can issue:

  column tbl format a79
  select  nvl2(table_owner,'"' || table_owner || '"."',null) || table_name || nvl2(db_link,'"@' || db_link,'"') tbl
    from  dba_synonyms
    where synonym_name = 'GREM'
  /
  {code}
  
  and see what table synonym points to.
  
  SY.                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                            
  

• Elements of the array are invisible

  I have a large table on my site - 310 lines/2 columns. When I'm working on that table in the 'Design', the lower part of the table view does not appear correctly. For example, in the table ( http://www.utmostchristianwriters.com/markets/temp.wrpubs.php) elements on the left column (alphabetically) stop that appear correctly in the title 'partnership of marriage '. The exact line where the display is faulty can change by a line or two, but it is almost always in the same place. If I'm moving down to the bottom of the table and click where the title should appear, the title displays sometimes after a few seconds, but then disappears again. If I need to work on the lower parts of this table, I have to work in "split" mode Any ideas on what is happening here? Older versions of DreamWeaver (IE version 4) display the same table without error at all.
  
  DreamWeaver 8.0.2 / Macintosh G4 933 MHz with 512 MB RAM / Mac OS 10.4.7

  I found another workaround solution in the bug for this issue report:

  Change the context menu set magnification in the lower right of the
  Document to 99% or 101% window. You can type these values directly in the
  Context menu of fixed magnification. For more information on the magnification of the value, see this
  page:

  http://livedocs.Macromedia.com/Dreamweaver/8/using/gs_02_b6.htm

  When you view Split solution, you are able to see the bottom
  of your page in Design view, or are you just using split view code to
  make changes to the bottom? I tried to use split across a page here.
  and there was no display of the lower part of the page in Design view. I have
  see the code though.

  --
  David Alcala
  Adobe technical support

• Regd select the column in the table area

  Hello
  
  I have a search page... Have used autocustomization to create... This page will be used to query data from a table and then we must also update two fields of results table and save.
  
  There is a region of results. I've included the multiselect table option that made me select a column as the first column of the table. Also, including a tableaction and a button upate with whom...
  
  I need to write a handler for the update now... but do not understand all the slect column...
  
  Whenever a user clicks on the boxes to select specific records and change the fields and click Update to save, how to write code to check whether the checkbox option has been activated or not?
  
  
  Please help me as soon as possible...
  
  
  Kind regards
  Preeti

  Hello

  Take a Transient attribute tell 'SelectFlag' in view object and to set the Instance of the view and the view attribute
  for multipleselection in the table.

  Now that the update is click on the button:

  If (PageContext.GetParameter ("Update")! = null)
  {
  OAApplicationModule am = pageContext.getApplicationModule (webBean);
  OAViewObject vo = (OAViewObject) am.findViewObject ("projVO1");
  Line [] row = vo.getAllRowsInRange ();
  Loop through lines
  for (int i = 0; i)<>
  {
  Check if checbox is checked or not
  If (line.getAttribute("SelectFlag").toString().equals("Y"))//means checbox is checked for this line.
  {
  write your logic
  }
  }
  }

  Thank you
  Gerard

• folders on the desktop are invisible

  so I opened my computer then my desktop applications and the file disappeared. If I go to the desktop, then they are there and if I try to drag an item to my counter top, it is always invisible

  Right click on an empty spot on your screen, go to view and turn on "show icons.

• width of the table are different for IE, that MZFX &amp; RULE

  Hello world

  I have three tables and would be of the same width (for looks).

  I tried the following:

  {#code_selection}
  Width: 50px;
  margin-left: 30%;
  }

  {#wash_type}
  Width: 398px;
  margin-left: 30%;
  }

  {#wash_schedule}
  Width: 398px;
  margin-left: 30%;
  }

  In IE, they are not aligned, but Mozilla & Google they are?

  Can someone explain what is happening?

  Thank you.

  Try this:

  {#code_selection}

  Width: 500px;

  margin-left: 30%;

  }

  {#wash_type}

  Width: 500px;

  margin-left: 30%;

  }

  {#wash_schedule}

  Width: 500px;

  margin-left: 30%;

  }

  Nancy O.

• check if the fields in the table are duplicated

  I neeed to check if the unique table fields are duplicated.
  
  I write this
  
  Select IID_DELOVNO_MESTO, IID_DEL_IN_NALOG from ZKET_DELA_IN_NALOGE_DM Z1
  where Z1. IID_DELOVNO_MESTO = (select IID_DEL_IN_NALOG from ZKET_DELA_IN_NALOGE_DM Z2)
  
  but I get
  
  SQL error: ORA-01427: einreihig subquery returns multiple rows
  01427 00000 - "einreihig subquery returns several lines.
  
  so I try with loop
  
  declare @stevec int;
  declare @izpis chain;
  
  Set @stevec = 1;
  While @stevec > 0
  Start
  Set @izpis = (select IID_DELOVNO_MESTO, IID_DEL_IN_NALOG from ZKET_DELA_IN_NALOGE_DM Z1
  where Z1. IID_DELOVNO_MESTO = (select IID_DEL_IN_NALOG from ZKET_DELA_IN_NALOGE_DM I2));
  end
  
  impression izpis
  
  and I get
  
  PLS-00103: encountered the symbol "@" when expecting one of the following values:
  
  begin function package pragma procedure subtype type use
  < an ID > < a double quote delimited identifier > form
  current cursor
  06550 00000 - "line %s, column % s:\n%s".
  * Cause: Usually a PL/SQL compilation error.
  
  and I don't know how to solve this problem.
  
  Published by: senza on Sep 2, 2008 02:08
  
  Published by: senza on Sep 2, 2008 02:17

  It will work, but there are probably more effective ways to do so.
  Note that the actual query starts from select * from sampledata. The front section is the only reason I can repeat your data

  with sampledata
  as
  (
  select 1 ID,12  IID_DELOVNO_MESTO,14 IID_DEL_IN_NALOG from dual union all
  select 2, 17, 15 from dual union all
  select 3, 12, 14 from dual
  )
  select * from sampledata
  where IID_DELOVNO_MESTO||IID_DEL_IN_NALOG in
  (
  select cols
  from
  (
  select IID_DELOVNO_MESTO||IID_DEL_IN_NALOG cols,count(IID_DELOVNO_MESTO||IID_DEL_IN_NALOG) from sampledata
  group by IID_DELOVNO_MESTO||IID_DEL_IN_NALOG
  having count(IID_DELOVNO_MESTO||IID_DEL_IN_NALOG) > 1
  )
  )