without regular expression

Similar Questions

• regular expression: an integer in the range 0.100

  What is the best regular expression to satisfy the need:
  (1) input string must be whole, the minimum value is 0, the maximum value is 100, no other symbols are allowed in the channel, no comma without a space.
  
  The example data:

  with T as 
  (select '-1' str from dual --not ok
  union
  select '0' str from dual --ok
  union
  select '1' str from dual --ok
  union
  select '100' str from dua --ok
  union
  select '1000' str from dual-- --not ok
  union
  select '101' str from dual --not ok
  union
  select '10.1' str from dual --not ok
  union
  select '10,1' str from dual --not ok
  union
  select 'a' str from dual --not ok)
  select * from T
  where regexp_like(str,'^[[:digit:]]{0,3}$');

  Hello

  I think you hit the key to this solution; using regular expressions, it is better to make a special case of '100'.

  You accept the numbers 1 and 2 digits that begin with '0'. would be unwise to accept 3 digit like '007' numbers, too?
  Here's a regex solution that makes and also an inelegant way to achieve the same results without regular expressions:

  SELECT     ROWNUM
  ,     str
  ,     CASE
            WHEN  REGEXP_LIKE ( str
                        , '^'          || -- Beginning of string
                          '('          || -- number, which is either
                            '(100)'     || --     100
                          '|'          || -- or
                            '(0?'     || --     optional leading 0
                            '\d{1,2})'|| --     2 digits
                          ')'          || -- end number
                          '$'             -- End of string
                        )
            THEN  'Okay'
       END     AS regexp
  ,     CASE
            WHEN  LENGTH (str)     <= 3
            AND   TRANSLATE ( str
                      , 'X0123456789'
                      , 'X'
                      )     IS NULL
            AND   LPAD ( str
                    , 3
                    , '0'
                    )          <= '100'
            THEN  'Okay'
       END     AS non_regexp
  FROM     t
  ;
  

  Output:

      ROWNUM STR  REGE NON_
  ---------- ---- ---- ----
           1 -1
           2 0    Okay Okay
           3 007  Okay Okay
           4 08   Okay Okay
           5 1    Okay Okay
           6 10.1
           7 100  Okay Okay
           8 1000
           9 101
          10 999
          11 a
          12
  

  I added these lines to the sample data:

  union
  select null str from dual
  union
  select '007' str from dual
  union
  select '08' str from dual
  

• Complex regular expressions without multiple passes

  Does anyone know of a tool that can handle more complex regular expressions without chaining of multiple copies of the VI regular expressions?

  For example, if I have a XML string as

  Power supply error has occurred.

  Sorensen SGA166/188

  and I am interested in the tag method to retry only, I could write a regular expression something like

  .*.*

  to parse the string inside the tag.

  kc64 wrote:

  For example, if I have a string like

  My email address is [email protected].  Please no spamming not me.

  and I am interested in the domain name of the email only address, I could write a regular expression something like

  @(\w)*\. (com: net | org)

  to parse the string 'gmail '.

  Forgive me if I am away from base, but I'm flying blind at the moment (not LV to test what I say).  You can add to the power of a regular expression using submatches or capture groups.  The regular expression you wrote will grab (I think) @gmail.com for the entire game.  Let's say you want to get 'gmail' without a second function call.  You can do the first group of a little dishonest selection by moving the * inside the parentheses.  Then, on the BD pull down on the bottom of the function of regular expression matching to expose a variable number of submatches (both should be in this case).  The first should be 'gmail '.   The second one should be "com."

  In summary, @(\w*)\.) (com: net | org) should give you gmail in the first submatch.  Of course, my Perl is a little rusty and LV cannot apply in the same way.

• Validation of attribute text WITHOUT using regular expressions

  Hello world

  I'm working on a few validation rules for a text attribute and one of the conditions is that the text string can contain only alphanumeric characters.

  Because of the requirements that I can't use a regular expression here (the output should be a Boolean value confirming if the text is valid or not), so I need to find a way to write this in the rules...

  Yes, is there an easier way of writing this rule that the use of the ' Contains (< text >, < substring >)' function? Like this:

  

  [Etc. for all the non alpha numeric characters]

  If not, is it possible to write a rule that States that the text contains ONLY the following characters

  

  [Etc for all alphanumberic characters]

  Or is there some other function I could use it here?

  Appreciate any thoughts or input about how this could be solved, thank you in advance for your help.

  Unfortunately, regular expressions are the ideal solution for exactly the scenario you are exhibitor. The only alternative other than a broad 'or' statements is regular expressions, or write a custom function.

• "Matches regular Expression" and "Model match" vi behaves differently

  Hello

  I need a simple matching chain and experimenting that found the "Regular Expression Match' and 'Correspondence model' vi behave a little differently. I guess that the entries of the regular expression on the two the same behavior. It's a difference that I discovered that the "|" character ("vertical" character, commonly used as an operator 'or') is recognized as such in the regex to Match vi, but not in the match vi model (where it is taken to the letter). Furthermore, I can't find any document using (online or in LabVIEW) on the ' | ' usage in regular expressions of character. Is - this documented anywhere?

  For example, suppose I want corresponding to one of the following 4 words: 'The' or 'fast' or 'brown' or 'fox '. The regular expression ' the | fast | Brown | Fox' (without the quotes) works for the vi Regular Expression Match but not the match pattern vi. Here is a photo of the block diagram and the results of the façade:

   

  The Help explains that the vi Regular Expression Match performs a little more slowly the match vi pattern, so I started with the latter. But since he does not work for me, I'll use the old. But does anyone have an idea of the speed difference? I guess that's negligible in a simple example.

  Thank you!

  Thank you, Jeff. That's what I was looking for. BUT my version of LabVIEW 8.5, does NOT say "functionfor example, the Match model does not support the parenthesis or vertical bars (|) characters.«» !

  See: http://zone.ni.com/reference/en-XX/help/371361D-01/glang/match_pattern/

  and http://zone.ni.com/reference/en-XX/help/371361D-01/glang/match_regular_expression/

  It is not mentioned in the help of special characters used for the match pattern : http://zone.ni.com/reference/en-XX/help/371361D-01/lvhowto/specialcharformatchpatt/

  The only place | has 'talked', it is in the sentence: "some regular expressions that use alternating (such as (. |))". \s)*) require significant resources to deal with when it is applied to the large input strings. "But I'm not processing a large chain.

  It seems that NEITHER fixed this omission. What version is your help?

  Ed

• How to capture multiple line String using regular expressions?

  Hello

  I have a simple program like this:

  

  What I want to accomplish is to capture everything between > start and > to end with a single regular expression matching node. It seems that the definition of multiples? true or False does not help.

  I'm using LabVIEW 2012.

  If it is impossible to capture using a single node, that's fine. But I want to assure you that I can make full use of this node without combining several others.

  Thank you!

  > start([\w\s]*) > end

  A point matches any character except line break characters.  You have two of them.

  

• regular expression for the xml tags

  Dear smart people of the labview world.

  I have a question about how to match the names of xml text elements.

  The image that I have some xml, for example:

  Peter

  13

  and I want to match all of the names of elements, that is to say: no, son, grandson, age, regardless of any attribute have these items. There is a regular expression, I can loop, that can do this? (Something like "\<.+\> ". "") It is no good because it matches the entire xml string.) I'd really only two different expressions, one for the match start elements, e.g. and one for the correspondence of the elements, for example.

  Thanks for your help in advance!

  Paul.

  The site Of regular Expressions will be very convenient.

  They have some good tutorials on regexp with a demo of the XML tags:

  Here is a small excerpt:

  The regular expression <\i\c*\s*>matches an opening of the XML without the attributes tag corresponds to a closing tag. <\i\c*(\s+\i\c*\s*=\s*("[^"]*"|'[^']*'))*\s*>corresponds to an opening with a number any attributes. Put all together, <(\i\c*(\s+\i\c*\s*=\s*("[^"]*"|'[^']*'))*| i\c*)\s*="">corresponds to an opening with attributes or a closing tag.  (source)

  If you want advanced XML analysis I suggest JKI XML toolkit.

  Tone

• Regular expression - get longer channel number

  I think it's easy, but I can't get it. Lets say I have a string "A1_1000", I would like to remove the 1000 using regular expressions. When I fed regular expression Match I get '1', which is not the longest number. I know other ways to do it, but I want to clean the solution in one step. Anyone know the regular expression to the right to achieve this? Thank you!

  ceties wrote:
  It is the best solution I've been able to come. I wonder if there are "more smooth way" without the cycle of.

  Since several checks are needed, I would tend to beieve we must travel opportunities. in this example

  

  I start to check at '0' offset in the string to a number. Provided that I have find a number, I check if it is longer that any previous number, I found and if so, store the new number more in the shift register.

  Have fun!

  Ben

• Regular expression breaks script

  I have the following statement of regular expressions in my JSX file:

  var regex = /[^/]*(?=\.[^.]+($|\?))/; // Doesn't work while this does: var regex = /[\u0400-\u04FF]+/;
  

  
  .. .and it breaks execution of my script for unknown reasons. What's not here? I thought the syntax / theRegEx.
  (comment to the statement of regex solves the problem and the script runs normally)

  I tested the regex here:
  RegExr: Learn, build, & Test of RegEx

  .. .on this string: "c:/Users/martin.dahlin/Desktop/Test/lolFile.lol".
  gives me "lolFile" without the quotes.

  xbytor is right, there is really no "regex-standard/compliance. Basic things work quite universally, but there are the specifics of the platform and conventions and you just test & work around them.

  That said, get into your regular expression to Tester online regex and a debugger: JavaScript, Python, PHP, and PCRE gives and error "/ separator unescaped ', i.e. must be ' / [^\/] * (?)» = \. [ ^.] +($|\?)) /". Also the use of the explicit constructor is a tad safer, typos lead more reasonable errors.

• Regular Expressions of Drivng me crazy!

  Oracle Version 11 GR 2

  Scripts of test data

  CREATE TABLE REGEX_TEST

  (ID NUMBER 4,

  VARCHAR2 (50) COMMENTS

  );

  Insert into REGEX_TEST (ID, COMMENTS) values (1, "< Little Red Riding Hood > #title");

  Insert into REGEX_TEST (ID, COMMENTS) values (2, "#title < Little Red Riding Hood > #publisher < Penguin >");

  Insert into REGEX_TEST (ID, COMMENTS) values (3, ' #title < Little Red Riding Hood > #publisher < Penguin > #pages < 30 > ");

  Congratulations to Frank Kulash to provide the following SQL to clean the field of comments only properly marked the text in the field

  Properly tagged text is defined as

  Start by #.

  then nameOfHashTag

  then < valueOfHashTag >

  The number or name of hashtags is variable and is not known at design time

  The Frank provided SQL is (with a slight mod)

  Original, SELECT comments

  REGEXP_REPLACE (comments

  , '(^|>)[^#.*<]*'

  "\1") that cleaned

  of REGEX_TEST;

  Source language

  
  CLEANED#title < little Red Riding Hood >#title < little Red Riding Hood >#title < little Red Riding Hood > #publisher < Penguin >
  #title < little Red Riding Hood > #publisher < Penguin >#title < little Red Riding Hood > #publisher < Penguin > #pages < 30 >#title < little Red Riding Hood > #publisher < Penguin > #pages < 30 >

  
  

  FIRST QUESTION: I understand the [^ #. * <] * component - search for zero or more occurrences of anything that is not a # tracking of zero or more characters, then a < and I understand the () sets a capturing group, but I don't understand how it works - 1 is probably a reference to the Group?

  Now, I add a few more - lines to see how he treats badly marked text that is

  void <>

  text that is not marked

  text is not enclosed by sharp hooks

  Insert into REGEX_TEST (ID, COMMENTS) values ('4, #title <>");

  Insert into REGEX_TEST (ID, COMMENTS) values (5, "#title <>#publisher < Penguin >");

  Insert into REGEX_TEST (ID, COMMENTS) values (6, "#title < Little Red Riding Hood > text that isn't marked < Penguin > #publisher");

  Insert into REGEX_TEST (ID, COMMENTS) values (7, "#title oops I forgot #publisher < Penguin > rafters").

  
  

  
  

  Original, SELECT comments

  REGEXP_REPLACE (comments

  , '(^|>)[^#.*<]*'

  "\1") that cleaned

  of REGEX_TEST;

  Source language

  
  CLEANED#title < little Red Riding Hood >#title < little Red Riding Hood >#title < little Red Riding Hood > #publisher < Penguin >
  #title < little Red Riding Hood > #publisher < Penguin >#title < little Red Riding Hood > #publisher < Penguin > #pages < 30 >#title < little Red Riding Hood > #publisher < Penguin > #pages < 30 >#title <>#title <>#title <>#publisher < penguin >
  #title <>#publisher < penguin >#title < little Red Riding Hood > text that is not signposted #publisher < Penguin >
  #title < little Red Riding Hood > #publisher < Penguin >#title oops I forgot the #publisher < Penguin > rafters#title oops I forgot the #publisher < Penguin > rafters

  SECOND QUESTION: Is there any way I can specify that the <>cannot be empty - I played a bit with the +? but impossible to get what I want.  Similarly, the latter (without text no sharp hooks)-I guess this would be impossible because you don't know if it was wong, until you have met the # next date you would be somehow to follow back and ignore the whole group.

  I learned two things in this

  1. regular expressions are extremely powerful

  2. but they will drive you crazy?

  Once again thanks a lot for the help

  BTW - I managed to do what I had to do it using a lot of PL/SQL code, but not very fast!

  Hello

  So, you want only the substrings that are well-formed attribute/value pairs (attribute or value may be missing).  You want to ignore anything in the comments that is not part of a well-formed pair.

  It is not very difficult to get a single well-formed pair.  The problem is that there is no good way to say 'everything that is not part of a well-formed pair '.  One solution is to extract from each pair trained well on a separate line and then re - combine them into a single string by id, like this:

  WITH split_data AS

  (

  SELECT id

  comments

  REGEXP_SUBSTR (comments,

  , '#'      ||  -sign #.

  '[^<]+'  || ="" --="" 1="" or="" more="" of="" any="" characters="" except="">

  '<'      || ="" --=""><>

  '[^>]+'  ||  -1 or several characters any except >

  '>'          -- > sign

  1

  LEVEL

  ) AS well_formed_pair

  LEVEL AS pair_num

  OF regex_test

  ([LEVEL CONNECTION <= regexp_count="" (comments,=""> <> <[^>] + > ')

  AND PRIOR id = id

  AND PRIOR SYS_GUID () IS NOT NULL

  )

  SELECT id

  commented THAT the original

  LISTAGG (well_formed_pair) WITHIN GROUP (ORDER BY pair_num)

  THAT cleaned

  OF split_data

  GROUP BY id, comments

  ORDER BY id

  ;

  The 2nd argument of REGEXP_SUBSTR above is actually the same as the 2nd argument of REGEXP_COUNT.  I wrote one of them in a more detailed form, hoping to make it clear what happens if has been done.  You can write an expression so be it.

  The result is just what you asked:

  ID CLEANED ORIGINAL
  --- ---------------------------------------- ---------------------------------
  1 #title #title

  2 #title#publisher #title#pu
      blisher

  3 #title#publisher #title#pu
      #pages<30> blisher#pages<30>

  4 #title<>

  5 #title<>#publisher #publisher

  6 #title #title#pu text
  is not marked #publisher blisher

  7 #title oops I forgot that the rafters whoops # #title forgotten angle br
  Editor ackets #publisher

• pattern by using regular expressions match

  I'm playing (and wrong) with regular expressions

  Select regexp_substr (1 < PSN > / # < 231 > # < 3 25 3 > / < ABc > ',' < [[: alnum:]] + > ') twice;

  give < PSN > - I understand that

  Select regexp_substr (1 < PSN > / # < 231 > # < 3 25 3 > / < ABc > ',' < [[: alnum:]] + >, 1.2 ') twice;

  give < 231 > - I understand that

  Select regexp_substr (1 < PSN > / # < 231 > # < 3 25 3 > / < ABc > ',' < [[: alnum:]] + >, 1.3 ') twice;

  give < ABc > which confused me until I realized that < 3 25 > has not been matched, because it has a space inside

  so I changed it to

  Select regexp_substr (1 < PSN > / # < 231 > # < 3 25 3 > / < ABc > ',' <. * + > ', 1.3) twice;

  who gave a syntax error, so I changed it again to

  Select regexp_substr (1 < PSN > / # < 231 > # < 3 25 3 > / < ABc > ',' <. * + > ') twice;

  that works, but gives < PSN > / # < 231 > # < 3 25 3 > / < ABc >

  I guess because the. * corresponds to anyting that all but the last closure >

  The question I have is how can I retrieve the text of mounting bracket included (even if it has multiple spaces)?

  Hello

  9c5dfde3-EAAE-45A7-80a1-bba8a71c826c wrote:

  Thanks for that - is there a way to return all 4 surrounded by extracts of <> without resorting to PL/SQL?

  Of course;

  REGEXP_REPLACE (str

  , '(^|>)[^<>

  , '\1'

  )

  Returns a copy of str with all outside rafters removed, for example

  <231><3 25="">

  .  It doesn't matter how many pairs of sharp hooks - there is.

• regular expression replacement

  
  Hi gurus,

  I have a requirement where I have to replace some characters in duplicate and retain the values of this column in order of alphabatic and digital control. Please find below examples of data

  Thanks in advance

  sample data:

  SELECT 'ZZYYXXAAABBBDDDCCC' DOUBLE COL1

  UNION ALL

  SELECT 'DDDCCCAAA' OF THE DOUBLE

  UNION ALL

  SELECT 'SDBBACCCC' OF THE DOUBLE

  UNION ALL

  SELECT "99988866332154" DOUBLE

  UNION ALL

  SELECT "77663322996" DOUBLE

  Expected:

  ABCDXYZ

  ADC

  ABCD

  12345689

  23679

  Hello

  I don't think that regular expressions will help with that.

  Here's a way to do it:

  WITH single_characters AS

  (

  SELECT DISTINCT

  col1

  , SUBSTR (col1, LEVEL 1) AS a_char

  OF sample_data

  CONNECT BY LEVEL<= length="">

  AND PRIOR col1 = col1

  AND PRIOR SYS_GUID () IS NOT NULL

  )

  SELECT LISTAGG (a_char) WITHIN GROUP (ORDER BY a_char) AS expected

  OF single_characters

  GROUP BY col1

  ;

  This assumes that col1 is unique.  If this is not the case, use all that is unique, even something drift of ROWID or ROWNUM, in CONNECT BY and GROUP BY clauses.

  The output I get is exactly what you posted:

  EXPECTED

  --------------------------------------------------------------------------------

  23679

  12345689

  ACD

  ABCD

  ABCDXYZ

  I guess that's what you really want.

  Regular expressions can not re - organize a string so that the characters are in order; you need to split the string into pieces, order parts and then put back together them.  Given that you have to do it just to get the characters in order, it's simple remove duplicates without problem with regular expressions.

• Java regular expression

  Hello

  Can you help me how to replace all the commad located on a string between double quotes 2?

  for example, I have a text file that contains data such as as follows

  A, "-16,12","178,245", "-15,506"

  B, "-16,12","178,245", "-15,506"

  C, 0, 0.1

  I need a result like this:

  A, "-16.12", "-178.245", "-15.506".

  B, "-16.12", "-178.245", "-15.506".

  C, 0, 0.1

  I did this, but without the regular expression. It seems to me that a regular expression, it is more elegant to parse each line and replace it.

  Thank you

  in which case you can be sure that all the change always are enclosed in doublequotes the regex would be like this:

  line.replaceAll("(\"-?\\d*),(\\d*\")","$1.$2");
  

  Good bye

  DPT

• Regular expression to remove the space in the HTML tag

  Hi all

  My HTML string is as below.

  Select ' < CityName > RICHMOND < / Nom_ville >

  < StateCd > ABCD CDE

  < StateCd / >

  < CtryCd > CAN < / CtryCd >

  < CtrySubDivCd > BC < / CtrySubDivCd > ' double Str

  Output desired is

  < CityName > RICHMOND < / Nom_ville > < StateCd > ABCD CDE

  < StateCd / > < CtryCd > CAN < / CtryCd > < CtrySubDivCd > BC < / CtrySubDivCd >

  I want to remove these spaces of the tag value box with only spaces otherwise leave it as what. Please help to implement the same using regular expressions.

  Hello

  We don't know what you want.  This site seems to be formatting your message in a weird way.

  As the statement

  SELECT «...» "THE DOUBLE;

  without formatting, to show your entry and after the exact output desired friom as, with as little in shape as possible.  It might be useful if you use some character like ~ instead of spaces (just for viewing; we will find a solution that works for spaces).

  To remove the text which consists of spaces and nothing else between the tags, you can say

  REGEXP_REPLACE (str

  , '> +<>

  , '><>

  )

  How is this string generated?  Maybe there is an easier and more effective way to keep the bad wrtings sub off the chain in the first place.

• ADF Email of Validation using regular expressions

  Hello
  
  Wanted to add search Email Validation VO.
  
  It works if I put

  <af:validateRegExp pattern="[A-Z0-9._%+-]+@[A-Z0-9.-]+\.[A-Z]{2,4}" 
                                           messageDetailNoMatch="The value {1} is not a valid email address:"/>

  However, this requires identification of email to be entered in capital letters.
  
  I tried with below the option does not work.
  

                 <af:inputText value="#{bindings.xxEmail.inputValue}" label="Email"
                                        required="#{bindings.xxEmail.hints.mandatory}"
                                        columns="#{bindings.xxEmail.hints.displayWidth}"
                                        maximumLength="#{bindings.xxEmail.hints.precision}"
                                        shortDesc="#{bindings.xxEmail.hints.tooltip}" id="it5">
                              <f:validator binding="#{bindings.xxEmail.validator}"/>
                              <f:validateLength minimum="6"/>              
                              <af:validateRegExp pattern="[A-Za-z0-9._%+-]+@[A-Za-z0-9.-]+\.[A-Za-z]{2,4}" 
                                           messageDetailNoMatch="The value {1} is not a valid email address:"/>
                          </af:inputText>

  I got over information of
  ADF Email of Validation using regular expressions
  The user enter email id without @.
  
  
  
  Please suggest this model to reach.
  
  
  Thank you
  JIT
  
  Published by: appsjit on January 25, 2013 19:08

  Hello.
  My English is not very good.

  I use below format and it works

  
  "^ [_A-Za-z0 - 9-] + (\.). [_A-Za-z0-9-]+)*@[A-Za-z0-9][A-Za-z0-9-]+ (-.)] ([A Za-z0-9] +) * (-.) [A-Za - z] {2,}) $»
  messageDetailNoMatch = "the value {1} is not a valid email address" / >

  Habib

  Published by: Habib Eslami on January 26, 2013 01:22