Display records between 2 dates in a report

Similar Questions

• Get records between two Dates

  Hello
  
  I have my structure of the table and records build here
  http://sqlfiddle.com/#! d099ef/4/7
  
  I would like to get the records between two dates.
  For example, I would get the records between October 1, 2001 and October 31, 2001.
  
  How can I get the records. Any help is much appreciated.
  
  Concerning
  
  Published by: ponic on 29 August 2012 09:42

  ponic says:

  Start       End
  4th Jul    12th Dec
  4th Jul    10th Oct
  3rd Oct   19th Nov
  3rd Oct   4th Oct
  

  I would like to have all the lines between October 1, 2001 and October 31, 2001
  If the above lines because every OCTOBER under the foregoing.

  Thank you

  Try

  select *
  from products_range
  where product_start_date <= to_date('31-oct-2001', 'dd-mon-yyyy')
  and product_end_date >= to_date('1-oct-2001', 'dd-mon-yyyy')
  

  Published by: Paul Horth on August 29, 2012 00:46

• Problem link DB between active Data Guard and reports application database

  My version of the 11.2.0.2.0 and OS database is Oracle Solaris 10 9/10.
  I am facing a problem in my custody of data Active data base for purposes of tax. Active Data guard information is as below.
  
  SQL > select name, database_role, open_mode from v$ database;
  
  NAME DATABASE_ROLE OPEN_MODE
  --------- ---------------- --------------------
  ORCL PHYSICS READ SHALL ONLY APPLY
  
  Detail of the problem is less than
  ------------------------------
  I have created a db link (name: DATADB_LINK) between active data guard and report of application of data base for purposes of tax.
  SQL > create database DATADB_LINK link to connect to HR identified by HR using 'DRFUNPD ';
  Database link created.
  
  But when I run a query using db link to my database of enforcement report I got this error below.
  
  ORA-01555: snapshot too old: rollback segment number 10 with the name ' _SYSSMU10_4261549777$ ' too small
  ORA-02063: preceding the line of DATADB_LINK
  
  Then I see logfile named database alart Active Data Guard and get below error
  
  ORA-01555 caused by the following SQL statement (SQL ID: 11yj3pucjguc8, time of request = 1 sec, SNA: 0x0000.07c708c3): SELECT "A2". "' BUSINESS_TRANSACTION_REFERENCE ', 'A2 '. "' BUSINESS_TRANSACTION_CODE ', MAX (CASE 'A1'. "TRANS_DATA_KEY"WHEN "feature' AND 'A1'." " END OF TRANS_DATA_VALUE"), MAX (CASE 'A1'. "TRANS_DATA_KEY" WHEN 'otherFeature' THEN 'A1' '. "" END OF TRANS_DATA_VALUE")
  
  But the interesting point if I run the query report directly in the Active Data Guard database, I got never error.
  
  So it's a problem of link DB between active Data Guard and other databases?

  Fazlul Kabir Mahfuz wrote:
  My version of the 11.2.0.2.0 and OS database is Oracle Solaris 10 9/10.
  I am facing a problem in my custody of data Active data base for purposes of tax. Active Data guard information is as below.

  SQL > select name, database_role, open_mode from v$ database;

  NAME DATABASE_ROLE OPEN_MODE
  --------- ---------------- --------------------
  ORCL PHYSICS READ SHALL ONLY APPLY

  Detail of the problem is less than
  ------------------------------
  I have created a db link (name: DATADB_LINK) between active data guard and report of application of data base for purposes of tax.
  SQL > create database DATADB_LINK link to connect to HR identified by HR using 'DRFUNPD ';
  Database link created.

  But when I run a query using db link to my database of enforcement report I got this error below.

  ORA-01555: snapshot too old: rollback segment number 10 with the name ' _SYSSMU10_4261549777$ ' too small
  ORA-02063: preceding the line of DATADB_LINK

  Then I see logfile named database alart Active Data Guard and get below error

  ORA-01555 caused by the following SQL statement (SQL ID: 11yj3pucjguc8, time of request = 1 sec, SNA: 0x0000.07c708c3): SELECT "A2". "' BUSINESS_TRANSACTION_REFERENCE ', 'A2 '. "' BUSINESS_TRANSACTION_CODE ', MAX (CASE 'A1'. "TRANS_DATA_KEY"WHEN "feature' AND 'A1'." " END OF TRANS_DATA_VALUE"), MAX (CASE 'A1'. "TRANS_DATA_KEY" WHEN 'otherFeature' THEN 'A1' '. "" END OF TRANS_DATA_VALUE")

  But the interesting point if I run the query report directly in the Active Data Guard database, I got never error.

  So it's a problem of link DB between active Data Guard and other databases?

  Check this statement that applies to your environment

  * ORA-01555 on Active Data Guard Standby Database [1273808.1 ID] *.

  also

  http://asktom.Oracle.com/pls/asktom/f?p=100:11:0:P11_QUESTION_ID:8908307196113

• records between specific dates

  Hi all
  
  We have a table named where it is saved all the information of people as well as their start date and end date I need the list of all employees who were at the table between the dates
  
  (1) 2001 and 2002
  (2) 2002 and 2003
  (3) 2003 and 2004
  (4) 2004 and 2005
  
  
  
  Any suggestions on what are really appreciated.
  
  Thank you
  
  PK

  Hello

  Your question could mean several different things.
  Please post some sample data and the result you want to obtain from these data. If you post the CREATE TABLE and INSERT statements (or equivalent), then people will be able to test their ideas.

  Looks like you need join a table that contains a line for each period of time in whioch you are interested (2001-2002, 2002-2003,...) to your table and do a COUNT, with period of GROUP BY.
  If you do not have a table with one line per period, you can generate a result set that will work as well in a subquery.

  The join condition will be something like

  (     start_date <= end_period
  AND     end_date   >= begin_period
  )
  

• Number of records between two dates which lasted more than a minute

  I need to count the number of events/records in a single table with the dates of appointment and for how long the appointments in another table, I have two cells to hold dated (start and end dates) give a range. I want to count the number of appointments that lasted more than a minute falling into the test range.

  I am sure that this is COUNTIFS and I tried to make it work.

  Hope you can help.

  Thank you

  You could do something like that

  

  The data table on the left and are named "Data."

  Data in the table on the right.  Enter the Start Date, end Date and time Min.

  D2 = COUNTIF (Data::B, "> =" & C2, Data::A, "> =" & A2, Data::A,")<>

  It's abbreviation dethrone select cell D2, and then type (or Coptic and paste here) the formula:

  = COUNTIFS(Data::B, ">="&C2, Data::A, ">="&A2, Data::A, ")<>

• Request for between two dates.

  Hello
  
  I have a date column and I want to choose the records between two dates, the output of this column is: 19/08/2003-02:11
  
  My query is:
  
  SELECT THE POINT DTM
  WHERE DTM BETWEEN JULY 1, 2012 "-JULY 15, 2012"
  
  Help, please.
  
  Thank you

  >
  I have a date column and I want to choose the records between two dates, the output of this column is: 19/08/2003-02:11

  My query is:

  SELECT THE POINT DTM
  WHERE DTM BETWEEN JULY 1, 2012 "-JULY 15, 2012"

  Help, please.
  >
  Help with what? You do not have a question or indicate if you have a problem any.

  Do you need to know how to use TO_DATE instead of literals in the WHERE clause?

  SELECT DTM FROM ITEM
  WHERE DTM BETWEEN TO_DATE('07/01/2012', 'MM/DD/YYYY') AND TO_DATE('07/15/2012', 'MM/DD/YYYY');
  

• Since the last update when you import images directly into Lightroom, metadata display the correct focal length, but display no information of the lens, Lightroom reports only as "unknown lens", the news of the lens are in meta-data... whe

  Since the last update when importing image directly in Lightroom, metadata display the correct focal length, but will not display any information from the lens, Lightroom reports only as 'unknown lens', the info from the lens is in the meta-data... When you change an image in LR in PS then save, lens Info appears as if by magic. This is a problem of workflow for those who could use multiple lenses on a shoot... What is the status on this issue? I shoot with Nikon D800... thnx ted-lens-metadata-field-missing-on-import?topic-reply-list[settings][filter_by]=company_promo https://feedback.photoshop.com/photoshop_family/topics/camera-raw-9-5-lens-information-aux I posted this on FB with LIGHTROOM page, they instructed me to send you.  Needless to say that it is a huge problem for the workflow, and reduce my bright room isn't an option because whenever he do it takes two days to arrive, and I have no time to lose if I appreciate some type of response as soon as possible

  What is the status on this issue?

  The link you gave clearly indicates the status of this issue. Adobe is working on it.

• Display data in the report to pl/sql

  I need to display data in a report using pl/sql.
  
  The structure of the table would be fixed, but the data it would come from a pl/sql.
  
  Is this possible in Apex 3.2.1 for that? If so, how can we do this?

  Hi Hozy,

  As much as I know APEX report cannot manipulate the slider.

  If the options are:
  1)
  Try the PIPE...
  http://www.databasejournal.com/features/Oracle/article.php/2222781/returning-rows-through-a-table-function-in-Oracle.htm

  (2) as has said Roel, complete apex collection using your ps/sql and use it in the report.

  Kind regards
  Shijesh

• Display the months between two dates

  Hello:
  I need all the months between two dates. I entered two dates as January 15, 2001 and 2011-mar-03. I want the result as below.
  
  JANUARY 15, 2011 - JANUARY 31, 2011
  February 1, 2011 - February 28, 2011
  MARCH 1, 2011 - MARCH 3, 2011
  
  I held this result of sql query in oracle. Could you please suggest me?
  Thanks in advance.
  Abhishek

  SELECT     GREATEST(st, ADD_MONTHS(TRUNC(st, 'MONTH'), (LEVEL - 1))) dt,
             LEAST(ed, LAST_DAY(ADD_MONTHS(TRUNC(st, 'MONTH'), (LEVEL - 1)))) ld
        FROM (SELECT DATE '2011-01-15' AS st, DATE '2011-03-03' AS ed
                FROM DUAL)
  CONNECT BY LEVEL <= MONTHS_BETWEEN(TRUNC(ed, 'MONTH'), TRUNC(st, 'MONTH')) + 1
    ORDER BY 1;
  
  DT                       LD
  ------------------------ ------------------------
  15.01.2011 00:00:00      31.01.2011 00:00:00
  01.02.2011 00:00:00      28.02.2011 00:00:00
  01.03.2011 00:00:00      03.03.2011 00:00:00
  

  HTH, Urs

• How to display each month between the date range

  I want a query that gives me the number of months between two dates given for example, if I going January 1, 2009 and April 1, 2009 then I should get on February 1, 2009 and March 1, 2009 in my trips
  
  Thank you very much

  Srix wrote:
  Thanks for the request

  It is not working do not when the effective date is differs from that in a year i.e start date January 1, 2009 and end date February 1, 2009, that it does not give u then required result

  I don't know what you mean? The dates are in the same year.

• Display buttons in a region report only if there is data in the report

  Hi friends,
  
  I have a region of report in which there is a report, 2 buttons and a text field. I want to show these buttons and
  
  text field only if there is data in the report. How can I do this? Help, please
  
  
  Thank you
  
  TJ

  Hello

  Define buttons conditionally as Exists (SQL query returns at least one row). The same use and the WHERE clause as your report, but change the SELECT part

  SELECT 1 
  

  BR, Jari

• Difference between 2 dates using PHP

  Hello

  Having some problems with the calculation of the difference between 2 dates.

  I noticed that about half of the results output 552 months... where is should be approximately 24 months...

  I also noticed that records that display this incorrect calculation having the month following the date less than the current month, it fixed $date2 as 01/01/1970

  This is the code:

  <? PHP

  Calculate the remaining months

  $date1 = date('d/m/Y');

  $date2 = $renewal_row ["enddate"];

  $date2 = date (a/m/Y ", strtotime (str_replace ('. ', ' ' ', $renewal_row [' enddate ']', $renewal_row ['enddate']))");

  $diff = abs (strtotime ($date2) - strtotime ($date1));

  $years = floor ($diff / (365 * 60 * 60 * 24));

  $months = floor (($diff-$years * 365 * 60 * 60 * 24) / (30 * 60 * 60 * 24));

  $days = floor (($diff-$years * 365 * 60 * 60 * 24-$months * 30 * 60 * 60 * 24) / (60 * 60 * 24));

  printf ("%d years, %d months, %d days\n", $years, $months, $days);

  $months_remaining = ($years * 12) + $months;

  ? >

  <? PHP echo "$date1 ='.strtotime ($date1).» ('. $date1.) ") date2 = '.strtotime ($date2).' ('. $date2.) ('') = Difference'. $diff;? >

  The date correct difference between these dates:

  $date1 = 1452038400 (06/01/2016) date2 = 1520035200 (03/03/2018) difference = 67996800

  Day with incorrect difference:

  $date1 = 1452038400 (06/01/2016) date2 = 1452038400 difference =(20/11/2016)

  Note that if the $date2 month exceeds the month current (June) it messes up.

  Any help would be appreciated!

  Assuming that this ["enddate"] $renewal_row is stored in a MySQL/MariaDB DATE, DATETIME, or TIMESTAMP column.

  $now = new DateTime();

  $end = new DateTime ($renewal_row ['enddate']);

  $time_remaining = $now-> diff ($end);

  echo $time_remaining-> format (' %m month %d days ");

• FaceTime will not open on my Macbook pro (el capitan).  Message: "FaceTime close unexpectedly.  Click Reopen to reopen the application. Click report to display more detailed information and send a report to Apple. "Please help me.

  FaceTime will not open on my Macbook pro (el capitan).  Message: "FaceTime close unexpectedly.  Click Reopen to reopen the application. Click report to display more detailed information and send a report to Apple. "Please help me.

  Please launch the Console application in one of the following ways:

  ☞ Enter the first letters of his name in a Spotlight search. Select from the results (it should be at the top).

  ☞ In the Finder, select go utilities ▹ of menu bar or press the combination of keys shift-command-U. The application is in the folder that opens.

  ☞ Open LaunchPad and start typing the name.

  Step 1

  For this step, the title of the Console window should be all Messages. If it isn't, select

  SYSTEM LOG QUERIES ▹ all Messages

  in the list of logs on the left. If you don't see this list, select

  List of newspapers seen ▹ display

  in the menu at the top of the screen bar.

  In the upper right corner of the Console window, there is a search box to filter. Enter the name of the application crashed or process. For example, if Safari has crashed, you would enter "Safari" (without the quotes).

  Each message in the journal begins with the date and time when it was entered. Select the messages since the time of the last fall, as appropriate. Copy to the Clipboard by pressing Control-C key combination. Paste into a reply to this message by pressing command + V.

  The journal contains a large amount of information, almost everything that is not relevant to solve a particular problem. When you post a journal excerpt, be selective. A few dozen lines are almost always more than enough.

  Please don't dump blindly thousands of lines in the journal in this discussion.

  Please do not post screenshots of log messages - text poster.

  Some private information, such as your name, may appear in the log. Anonymize before posting.

  Step 2

  In the Console window, clear the search box, and then select

  DIAGNOSIS AND diagnostic USE information reports ▹ user

  (not diagnose them and use Messages) in the list of logs on the left. There is a disclosure triangle to the left of the list item. If the triangle is pointing to the right, click it so that it points downwards. You will see a list of reports of incidents. The name of each report begins with the name of the process and ends with ".crash". Select the most recent report on the process in question. The content of the report is displayed at right. Allows you to copy and paste to validate all of the content, text, not a screenshot.

  I know that the report is long, perhaps several hundred lines. Please report all this anyway. If the report is only a few lines, make sure that you have disabled the search box.

  If you don't see any report, but you know, he had an accident, you have chosen diagnostic and using the list of Log Messages. INFORMATION on the USE of DIAGNOSTIC AND choose instead.

  In the interest of privacy, I suggest that, before posting, you change the UUID ' anonymous, ' a long string of letters, numbers and dashes in the header of the report, if it is present (it cannot be). "

  Please do not post other types of diagnostic report - they are very long and rarely useful.

  When you post the journal excerpt or the accident report, you might see an error message on the web page: "you have included content in your post that is not allowed", or "the message contains invalid characters." It's a bug in the forum software. Thanks for posting the text on Pastebin, then post here a link to the page you created.

  If you have an account on Pastebin, please do not select private in exposure menu to paste on the page, because no one else that you will be able to see it.

• acquisition and recording of analog data with producer consumer model

  Someone on this forum, in a separate last week discussion, suggested that I use the producer model consumer data acq.  My ultimate goal is to acquire analog channels 1-4 continuous data, display graphical band style and save the data on the boot disk when the user presses the 'Start Saving' button (and will continue to display recorder cards).  Economy will stop when the user presses the button "Stop Saving" but strip map will continue to operate.

  My attempt to use the producer-consumer model is attached (LV 8.5 only).  It does not work.  I have not tried to implement for recording user controls - just trying to make simple continuous display and save (1 channel) at this stage, using this model.  VI runs, but the graphic Strip is never updated with the actual data, and the data file that is saved has zero byte inside.

  Thank you.

  WCR,

  Looked at your code, and you are right.  It won't work.

  Take a look at this example:

  http://decibel.NI.com/content/docs/doc-2431

  The VI of the acquisition must be inserted in the loop of the producer.  In addition, you must tell him how many samples for (otherwise, it will get 0).

• How to calculate the difference between 2 dates, but with interruptions and stops between

  Hello

  How can I calculate the difference in minutes between 2 dates but taking into account the existence of a table in the Appendix, so if between start_date and end_date arguments, there is no 'work time' then this part of the time will not be included in the total difference.

  Records of the time table example:

  Time_configuration	start_hour	end_day	end_hour
  2	19:00	3	07:00
  3	19:00	4	07:00

  so for example first record said that on Monday you start at 19:00 and leave the next day at 7:00 and then save the same sort of thing.

  There is an event that I want to track how many minutes lasted. for example, this event began the day 2 at 19:00 and ended the day 3 at 21:00

  Theoretically, this event really lasted: 840 minutes. This 840 minutes are within the limits of the annex.

  Thanks in advance.

  The storage of the dates not as data type DATE in most cases is bad design. In addition, how do you know what day of the date is 2 at 19:00? East - Monday 2 November 2015 or Monday, March 7, 2016? It is the same for the event. In any case, assuming that both calendar and events don't extend over several weeks:

  According to schedule)
  Select time_configuration 2, 19:00 ' start_hour, end_day 3,' 07:00 ' end_hour of all the double union
  Select 3, 19:00 ', 4,' 07:00 ' double
  ),
  event like)
  Select event_id 1, time_configuration 2, 19:00 ' start_hour, end_day 3: 21:00 ' end_hour of the double
  )
  Select e.event_id,
  Sum)
  less (e.end_day + to_date (e.end_hour, 'HH24'), s.end_day + to_date (s.end_hour, 'hh24:mi')).
  greater (e.start_day + to_date (e.start_hour, 'HH24'), s.start_day + to_date (s.start_hour,'hh24:mi'))))
  ) * 24 * 60 minutes
  Appendix s,
  e event
  where e.start_day + to_date(e.start_hour,'hh24:mi')< s.end_day="" +="">
  and e.end_day + to_date(e.end_hour,'hh24:mi') > s.start_day + to_date(s.start_hour,'hh24:mi')
  E.event_id group
  /

  EVENT_ID MINUTES
  ---------- ----------
  1 840

  SQL >

  SY.