Reg: select stmt to get the day of the week in the last 20 years

Hello

I need to write a select statement or procedure that can give a performance of only one day given in the past 20years 20years and contracts at end of the current week in the calendar.

Thanks in advance

Published by: user648380 on January 14, 2010 12:06 AM

SELECT add_months(trunc(SYSDATE, 'IW'), -12 * 20) + (LEVEL * 7) monday
  FROM dual
CONNECT BY LEVEL < (add_months(trunc(SYSDATE, 'IW'), 12 * 20) - add_months(trunc(SYSDATE, 'IW'), -12 * 20)) / 7

Published by: fsitja on January 14, 2010 12:55 AM fixed... accident of copy/paste

Tags: Database

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Select 'Label', to_number (to_char (to_date(start_date,'yyyy-mm-dd'), 'IW')) - to_number (to_char (add_months (sysdate,-6), 'IW')) + 1 as a weekly sum, (col1) val yyy_view
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2 24 data
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and so on...

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Missed the part "Wednesday is considered date of last week. The week is Thursday to Wednesday. If so:
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Version of database

Oracle9i Enterprise Edition Release 9.2.0.8.0 - 64 bit Production
PL/SQL Release 9.2.0.8.0 - Production
CORE Production 9.2.0.8.0
AMT for HP - UX: 9.2.0.8.0 - Production Version
NLSRTL Version 9.2.0.8.0 - Production

data and model table

CREATE TABLE EXAMPLE
(
UNIT_ID1 VARCHAR2 (15 BYTE) NOT NULL,
COLL_DATE1 DAY,
ATTRIB_CODE1 VARCHAR2 (4 BYTE) NOT NULL,
UNIT_ID2 VARCHAR2 (15 BYTE),
COLL_DATE2 DAY,
ATTRIB_CODE2 VARCHAR2 (4 BYTE),
DATE OF AUDIT_INSERT_DATS NOT NULL
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Insert into SAMPLE
(UNIT_ID1, COLL_DATE1, ATTRIB_CODE1, UNIT_ID2, COLL_DATE2,
ATTRIB_CODE2, AUDIT_INSERT_DATS)
Values
('W039712008646', TO_DATE (OCTOBER 8, 2012 00:00:00 ',' DD/MM/YYYY HH24:MI:SS'), 'DP', 'W039712008646', TO_DATE (OCTOBER 8, 2012 00:00:00 ',' DD/MM/YYYY HH24:MI:SS'),)
'PP', TO_DATE (OCTOBER 9, 2012 11:10:56 "," MM/DD/YYYY HH24:MI:SS'));)
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(UNIT_ID1, COLL_DATE1, ATTRIB_CODE1, UNIT_ID2, COLL_DATE2,
ATTRIB_CODE2, AUDIT_INSERT_DATS)
Values
('W039712008646', TO_DATE (OCTOBER 8, 2012 00:00:00 "," MM/DD/YYYY HH24:MI:SS'), 'DP', NULL, NULL,)
'DP', TO_DATE (OCTOBER 9, 2012 11:11:02 "," MM/DD/YYYY HH24:MI:SS'));)
Insert into SAMPLE
(UNIT_ID1, COLL_DATE1, ATTRIB_CODE1, UNIT_ID2, COLL_DATE2,
ATTRIB_CODE2, AUDIT_INSERT_DATS)
Values
('W039712008647', TO_DATE (OCTOBER 8, 2012 00:00:00 "," MM/DD/YYYY HH24:MI:SS'), 'DP', NULL, NULL,)
'DP', TO_DATE (OCTOBER 9, 2012 11:15:18 ',' DD/MM/YYYY HH24:MI:SS'));)
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('W039712008649', TO_DATE (OCTOBER 8, 2012 00:00:00 "," MM/DD/YYYY HH24:MI:SS'), 'TP', NULL, NULL,)
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('W039712008650', TO_DATE (OCTOBER 8, 2012 00:00:00 "," MM/DD/YYYY HH24:MI:SS'), 'RD', NULL, NULL,)
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COMMIT;

-----------------------

unit_id W039712008646 has two records. I need a query to get the last disk based on audit_insert_dats. Any help is appreciated.
I tried to use max (audit_insert_dats) but not able to get a record
user_anumoses wrote:
unit_id W039712008646 has two records. I need a query to get the last disk based on audit_insert_dats.

You can use the ROW_NUMBER() analytic function
```
SQL> select *
  2  from
  3   (select a.*,
  4     row_number() over(partition by UNIT_ID1 order by AUDIT_INSERT_DATS desc) rn
  5    from sample a)
  6  where rn = 1;

UNIT_ID1        COLL_DATE ATTR UNIT_ID2        COLL_DATE ATTR AUDIT_INS         RN
--------------- --------- ---- --------------- --------- ---- --------- ----------
W039712008646   08-OCT-12 DP                             DP   09-OCT-12          1
W039712008647   08-OCT-12 DP                             DP   09-OCT-12          1
W039712008649   08-OCT-12 TP                             TP   09-OCT-12          1
W039712008650   08-OCT-12 RD                             RD   09-OCT-12          1
W039712008653   08-OCT-12 CX                             CX   09-OCT-12          1
```

Need to get the last value of the quarter
Hi expert,

I have data like this

Amount DATE column column

January $1 20

|

January 30, $50

Fed 60 1
|

February 28, $80

like that throughout the year

I will provide the first promt and selects the 1st quarter. Then, it will show you Jan, Feb, March in the Date column and the respective amounts in the amount column.

I need to put a formula into the amount column... So that I get the last day of the amonut of quarter.

Any help is appreciated.

Thank you
V

Published by: Vincent Krishna on May 25, 2011 06:43
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Apply the filter above on your amount column.

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How to get the last row and the sum of all columns in a query

Hello
is there a way to get the last record for a column and the sum of all the Archives to another column in the same query.
Best regards

You must set your needs correctly volunteers to help here...

Your data are not good enough to bring you a precise solution. Purpose, you do not have a column, which draws a distinction between the first and the last entry.

The solution becomes easy based on your design.

I introduced a grouping called 'id' column and a time column called 'time_of_insert' (only this way you can say with confidence that you can differentiate between the first and last (also a foolproof solution) - you can possibly use sequence (instead of date but if you say that you can insert two lines at the same time) ((and then likely sequence would be a better choice to differentiate instead of a timestamp field) etc...)

With your sample data, something like this can be done to get the desired results.

-----------------------------------------------------------------------------------------------------------------------

WITH dataset AS

(SELECT 1 id, 10 used, 8 remain, systimestamp + 1/24 time_of_insert FROM DUAL

UNION ALL

SELECT the 1 id, 1, 7, systimestamp + 2/24 FROM DUAL

UNION ALL

SELECT the id 1, 2, 5, systimestamp + 3/24 FROM DUAL

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SELECT 1 id, 1, 0, systimestamp + 4/24 FROM DUAL

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UNION ALL

SELECT the 1 id, 1, 4, systimestamp + 6/24 FROM DUAL)

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FIRST_VALUE (stay)

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last_row

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WHERE ROWNUM = 1;

Output:

------------------------

SUM_ALL LAST_ROW

------------------------------

15 4

See you soon,.

Manik.

get the month and year of date type
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I need to get the month and year of type date.

For example
```
select to_date('2011-01-17', 'yyyy-mm-dd') from dual;
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Reg: select stmt to get the day of the week in the last 20 years

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